Real bridge players count tricks, not hcp. I don't need pd to have 7 hcp to make 10 tricks. SK, HQ, or or even Sxx (with S lead) can get us 10 tricks. You can count (at most) oneH trick for defense. Besides, your LHO could have SK (though not likely).
For hand #1, I pass. As for #2, I would bid 4NT, depends on the number of key cards pd holds, I will decide how high I will go: if pd has 0, I stop at 5D, if pd has 1, I bid 6, and 7 if pd has 2.
Well, the only chance I see is RHO (you) holds ♠Kx, ♥Axxxx, ♦Kxxx, ♣xx. I would cash SA and then small S. East, asfter winning SK, would have to give you a ♦ trick or give you a ruff-sluff (another D pitched on S). If my RHO drops SK on SA, I would have to throw LHO in with 4th S (pitching D in hand) and play DKJ split.
This method strictly based on HCP is ill advised. If responder has ♠KJx, ♥AQxxx, ♦xxx, ♣Axx, or ♠Kx, ♥Qxxxxx, , Kx, ♣AQx or other "minimum" hands, slam would be very good.
Well, fast arrival is accepted by most expert players, I believe. After 2/1 game forcing response and agreed trump, to jump to game surely shows a minimum hand.
Yes, 3H is encouraging, better than 4H. Good H spots, 2 side Aces and Q in your suit, a promising hand. 3H leaves more spaces for partnership to explore slam (before game). If pd bids 3S/4C, I would cue-bid 4D. If pd cue-bid 4D, I would bid 4H (no club control).
1♦ - 2♦ (D slam was almost sure, I would ignore the possible S fit) 3♣ - 3♥ 3♠ - 4♣ 4♦ - 4♥ 4♠ - 4NT 5♥ - 5NT 7♦ 3♣: natural or strength 3♥/...4♠: cue 4NT: RKC 5NT: King asking 7D: 2 side Kings
Well, I will begin with top spades. If they split (4-2 or 3-3), I have 9 tricks. If (after 2nd spade) spades turned out to be 5-1 (or 6-0 after one spade), I will play a small D to my hand (if S6-0, I would play DA and Dx).