nullve

That's part of lebensohl over (2M)-X-(P) but necessarily over 1N*-(2M), * some 3-point range, e.g. 15-17 where 3m = NAT GF is playable because of partner's narrow range.

A major suit fit is less (more) likely after Teller has shown high (low) shortage. So it seems that 2N as high (low) shortage will wrong-side otherwise attractive notrump contracts more (less) often.

Two-way 1♣ opening based on Scamp's (strong) 1♣ opening: 1♣ = Scamp's 1♣ OR 11-13, either 3334 or 5C(332) 1♣-1♦/♠/N/2♠+: as in Scamp 1♣-1♦; 1♠: includes all 11-13 hands 1♣-1♦; 1♠-1N; P = 11-13 1♣-1♥; 1♠-1N/2♠+: as in Scamp 1♣-1♥; 1♠-2♣/♦/♥ = Scamp's 1♣-2♣/♦/♥, resp. 1♣-1♥; 1N = 11-13 1♣-1♠; 2♣ = 11-13 1♣-1N; 2♦ = 11-13 1♣-2♣/♦/♥ = Scamp's 1♣-1♥; 1♠-2♣/♦/♥, resp. 1♣-2♣; 2♥/3♣ = 11-13, not 3325 (wants to play 3♦ rather than 2♠ opposite 4S5D) 1♣-2♣; 2♠ = 11-13, 3325 (wants to play 2♠ rather than 3♦ opposite 4S5D) 1♣-2♦; 2♠ = 11-13 1♣-2♥; 3♣ = 11-13 1♣-2N/3♣/♦; step 2 = 11-13 (Law-protected but not GF) This should leave the symmetric relay structure intact.

So when do you open 1♠ with only 4?

I've played this in one partnership. The name we (or my partner, who wrote the notes) used was 'Romex spørremeldinger' (lit. 'Romex asking bids').

One often has to apply the Law in situations where one doesn't know, but can only estimate, the number of total trumps. As North I would estimate total trumps to be ~ 16 on this deal.

Aargh, yes. Will edit my post.

Yes, I want to force to game opposite 15 BAL. Do I want to be in game opposite this particular 15 count: KQJ2 AJ2 832 A43? Not really.

2♦ I want to * show 3c support and INV values opposite an unbalanced hand with 5+ S; * force to game opposite 15 BAL.

1st/2nd: P = "normal" OR 11-13, either 3343 or 3352* 1♣ = "16+" unBAL OR 17+ BAL 1♦ = "10-15", either 1-suited w/ 6+ C, 4+C5+M (C never longer) or C+D 2-suiter* 1♥ = "10-15", either 1-suited w/ 6+ H, 4+H5+O (H never longer) or 4H(441) OR 11-13 BAL, 4-5 H 1♠ = "10-15", either 1-suited w/ 6+ S, 4+S5+O (S never longer) or 4144 OR 11-13 BAL, 4-5S2-3H 1N = 14-16 BAL* 2♣ = "10-15", either 1-suited w/ 6+ D or 4+D5+M (D never longer) (...) P-?: P = 0-7, usually BAL 1♣: as in 1st/2nd OR 8-10, BALish** 1♦: as in 1st/2nd OR 11-13, either 3343 or 3352** (...) 1♦-1M; ?: 1N = 2-suited w/ 5+D4+C (C never longer) C+D 2-suiter OR ___? 2♣ = 2-suited w/ 4+D5+C (D never longer) C 1-suiter (...) 2♣-?: P: rare! 2♦ = to play opposite the 1-suited hand 2♥ = INV w/ 5+ H OR any GF ...2♠ = 5+ S ......2N = GAR relay (GF) ......3♣/♦/♥ = NAT NF ......(...) ...2N = 1-suited ......3♣ = GF relay ......3♦/♥ = NF ......(...) ...3♣+ = 5+ H, GAR developments (GF) 2♠ = INV, 5+ S ...P = MIN, 5-H2(3)S ...2N = MIN, 5H1-S ...3♣ = D 1-suiter (and likely 1- S if MIN?) ...3♦ = MAX, 5+ H ......3♥ = 2 H .........3♠ = 5H2S .........3N = 5H1-S .........4♣+ = 6+ H ......3♠ = 6+S1-H .........3N = 5-6H1-S .........(...) ...3♥ = MIN, 6+H2-S ...3♠ = INV, 3 S ...(...) ...4♠ = to play (...) * Alternatively: P = "normal" 1♣ = as above OR 11-13, either 3343 or 3352 or P = "normal" 1♦ = as above OR 11-13, 3343 1N = as above OR 11(12?)-13, 3352 ** Alternatively, 1♦ = as in 1st/2nd OR 11-13, 3343 1N = as in 1st/2nd OR 11-13, 3352

(5332) is balanced but not flat? (In pilun's Symmetric Relay book, flat hands have either (4333) or (4432) shape.)

Form of scoring? Did 2♣ deny three spades? 1♣-(p)-1♠-(X) 2♣-(3♥)-? Calls with their IMO default meanings: P = unable to compete (duh) X = takeout (a misnomer, since partner shouldn't take out without extra shape) 3♠/4♣ = competitive, NF (you can't afford to play these as GF, especially not at MP) 3N = strong suggestion, rarely taken out 4♦ = NAT GF (although I can imagine a pair like Brink - Drijver using the bid as SI+ with 6+ S, or maybe 4♦/♥ as SI+ w/ C SUPP/6+ S, resp.) 4♥ = GF C raise, does not promise a heart control ...4♠ = S control (although I've recenty seen a pair (Brink - Drijver again?) playing what seemed like proxy cuebids in a similar situation, so that e.g. 4♠ = control in opps' suit, hearts) ...(...) 4♠/5♣ = to play 4N = RKC(♣) (there are probably better uses, but...) 5♦/5♥ = ERKC(♣) 5♠ = NAT SI, likely no H control (the #1 reason to torture partner with this bid) 5N = pick a slam 6♣ = to play, could be a sacrfice I'd bid 4N.

? DavidKok claimed that T-Walsh eliminates the need for weak jump shifts. I then gave what to me looks like a counterexample. That's all.

Opener: 18 hcp, 1435 Responder: 3 hcp, 6232 Your T-Walsh auction?

I agree with this. This begs the question: Are you always able to find a 6-2 spade fit after 1♦-1♠ 2♣-2♥ 3♣ ?

No, natural, denying doubleton support.

Of course she can. But 3♠ over 1♦-1♠ 2♣-2♥ 3♣ is not even close to showing a solid spade suit, because Responder might just be looking for a 6-2 spade fit. Which is unlikely to be a problem, because over 1♦-1♠ 2♣-2♥ 3♣-3♠ 3N Responder can cuebid 4♥ to set spades as trumps.

Here's a structure over 1♣-(2♠) based on lebensohl (aka Good/bad) and a very (too?) aggressive (MP-oriented?) takeout style: P = weak or trap ...X = takeout ......P = LoTT-based, mandatory with 12-17, 4333 ......2N = Good/bad .........3♣ = 12-17 ............P/3♦/♥ = NAT .........3♦+ = 21+, NAT ......3♣/♦/♥ = expecting to play there opposite 12-14, FG opposite 15 ...2N = 18-20 X = FG or defending 2♠X opposite 18, takeout. NB! Also made on most GF hands without a S void or positional S stopper, for lack of a better call. ...P = LoTT-based, as always, and mandatory with 12-17, 4333 ...2N = Good/bad: 12-14, not 4333 OR 18+ w/ S stopper) ......3♣ = P/C .........P/3♦/3♥ = 12-14, NAT .........3♠ = 18+, 4 H, S stopper .........3N = 18-20, 2-3 H, S stopper .........(...) .........4♥ = 18-20, 5 H .........(...) ......3♦ = ELC .........P = 12-14, 2-3 H .........3♥ = 12-14, 4-5 H .........3♠+ = 18+ ......3♥ = FG, 5+ H ......3♠ = FG, 4- H, stopper ask ......3N = FG, 4- H, S stopper, NF ......(...) ...3♣ = 15-17, NAT ......(...) ......3♦ = ELC ......3♥ = FG, 5+ H ......(...) ...3♦ = 15-17 NAT ......(...) ......3♥ = FG, 5+ H ......(...) ...3♥ = 15-17, 4(5) H ...3♠ = 18+, 4 H, no S stopper ...3N = 18-20, 2-3 H, no S stopper ...4♥ = 15-17, 5 H 2N = Good/Bad (aka lebensohl), FG opposite 18 ...3♣ = 12-17 ......P = to play 3♣ ......3♦/♥ = to play ......3♠ = FG, 4 H, positional S stopper ......3N = 3- H, positional S stopper, NF ......(...) ...3♦+ = 18+, NAT 3♣/3♦/3♥ = to play opposite 12-14, FG opposite 15 3♠+ = FG, S void

Or maybe 1♣: always BAL 1N = 3-suited (range?) 2♣ = 10-16, 6+m* 2N = 5-5 minors ? * i.e. what Marciński - L'Écuyer played in 1st/2nd NV vs. V in the 2022 Bermuda Bowl. Their cc + notes.

How many of the openings 1♣,...,2N in your system (Dutch Doubleton with Multi 2♦?) have no anchor suit? I think five: 1♣, 1N, 2♣, 2♦ and 2N. How many of the openings 1♣,...,2N in (what I've called) Boring Roman Club with freed up 2M/2N openings have no anchor suit? Not necessarily more than four (1♣, 1♦, 2♣ and 2♦). And if 2♣ and 2♦ are freed up as well, then not necessarily more than two (1♣ and 1♦).

Boring Roman Club with freed up 2M/2N openings: 1♣ = 12+ BAL 1♦ = Roman 1♦ OR unBAL part of Roman 1♣-1♦; 2♣+ ...1♥ = relay ......1♠ = Roman 1♦ except "11-15" instead of "11-21" ......1N = Roman 1♦ except "16-21" instead of "11-21" ......2♣+ = unBAL part of Roman 1♣-1♦; 2♣+ ...(...) 1M = Roman except M always real if "11-15" 1N = "11-15", 6+ C, 1-suited OR Roman 2M OR Roman 2N (5+D4+C version) ...2♣ = P/C ......P = 1-suited ......2♦ = Roman 2N (5+D4+C version) ......2M = Roman 2M ...2♦ = relay ...(...) 2M/N: freed up One could free up the 2m openings as well by instead opening * 1♣ with 44(41) and 44(50) * 1M with 4M144 and 4M(540) * 1♦ (or 1N!?) with 5M044 .

Boring Roman Club: 1♣ = 12+ BAL 1N = Roman 1♣-1♦; 2♣ OR any unBAL GF ...2♣ = relay ......2♦ = any unBAL GF ......2♥+ = Roman 1♣-1♦; 2♣-2♦; 2♥+ ...(...) other = Roman Boring Roman Club with strong 1♦: 1♣ = 12+ BAL 1♦ = "16+", unBAL 1M = Roman except with "11-15" instead of "11-21" 1N = Roman 1♦ except with "11-15" instead of "11-21" ...2♣ = relay ......2♦ = Roman 1♦-1♥; 2♦ ......2M = Roman 2M except with D instead of C ......2N = Roman 2N (the version with 5+D4+C) except with minors reversed (so 4+D5+C) ...(...) other = Roman

1♠-1N 2♣-2♠ 3♦-3♠ ?

What do you open with xx55 and less than 16 hcp?