Wackojack Posted June 29, 2005 Report Share Posted June 29, 2005 One partner I play with has strong views on the correct lead from J1082. Assuming the opponents bidding has been uninformative except that the points between them are roughly equal. e.g. 1NT (12-14) - 3NT. You have no obvious lead other than your 4-card spade suit. Your standard leads are 4th highest and top of sequence. Do you lead the 2 or Jack and why? With a known strong hand on your right and weak on your left or vice versa, would you change your selection? I would be grateful for your views. Quote Link to comment Share on other sites More sharing options...
Echognome Posted June 29, 2005 Report Share Posted June 29, 2005 Like every other lead problem, knowing the rest of your hand is important. That being said, the correct textbook lead in standard is the J as this is a near sequence. Playing Rusinow leads it would be the 10. Quote Link to comment Share on other sites More sharing options...
whereagles Posted June 29, 2005 Report Share Posted June 29, 2005 With JT9x or JT8x, the book lead is the jack. With JT7x or worse, it is 4th best. Quote Link to comment Share on other sites More sharing options...
SoTired Posted June 29, 2005 Report Share Posted June 29, 2005 IMHO and without going thru all the possibilites:J108x is different than J107x. With J107x, leading the J could cost a trick unless partner has the protected Q or 9. With J108x, you are also saved when declarer has the 9. Since whether declarer or dummy is the stronger hand does not affect who might have the 9, I don't think their relative strength matters. Quote Link to comment Share on other sites More sharing options...
P_Marlowe Posted June 29, 2005 Report Share Posted June 29, 2005 The Jack. The same in case the suit is JT7x. With kind regardsMarlowe Quote Link to comment Share on other sites More sharing options...
pigpenz Posted June 29, 2005 Report Share Posted June 29, 2005 i play jackthats about as close as you can come to j109x with out having the real thing Quote Link to comment Share on other sites More sharing options...
kgr Posted June 29, 2005 Report Share Posted June 29, 2005 From JT8x I would play the J. Playing the J can cost a trick if LHO has the 9. Same as from KQTx.... but is it really the same and where does it stop? What do you play from?:T97x986x Quote Link to comment Share on other sites More sharing options...
SoTired Posted June 29, 2005 Report Share Posted June 29, 2005 I treat 987x as xxxx since no honors Quote Link to comment Share on other sites More sharing options...
Guest Jlall Posted June 29, 2005 Report Share Posted June 29, 2005 jack is also useful for unblocking purposes. If declarer has A9x opp Qxx it is necessary as well, etc. Quote Link to comment Share on other sites More sharing options...
Wackojack Posted June 30, 2005 Author Report Share Posted June 30, 2005 OK Let me make the case for leading the 2. It wins over leading the Jack for the following: 1. Most hands with 9 in dummy: e.g. J1082 Q94 73 AK65 (here it would be wrong for declarer to put in the 9)or J1082 Q94 K73 A65or J1082 Q974 K A653 or any stiff honour with partneror J1082 9743 KQ A65 or J1082 Q975 K4 A63 2. Some hands with 9 with declarer e.g. J1082 Q75 K4 A63Here leading the 2, defenders can always make 2 tricks in the suit. If Jack is led, this hand may be endplayed to take only one trick in the suit. 3. 9 in dummy e.g. J1082 KQ75 9 A643 Lead of 2, then declarer can only make 3 tricks. Lead of Jack, then declarer finesses twice against leader for 4 tricks. I have been selective, taking only the cases where leading the 2 has an advantage. However, I am beginning to think that there are less cases where leading the Jack has the advantage. Can anybody show that I am wrong? PS Another advantage is that if partner leads the Jack and you see the 9 either in your hand or in dummy, then you can infer that it is not from J108x, most likely J108xx. :) Quote Link to comment Share on other sites More sharing options...
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