AL78 Posted December 16, 2022 Report Share Posted December 16, 2022 MPs, playing Benj Acol weak NT: [hv=pc=n&w=sq74hak65dk6ct962&d=e&v=e&b=6&a=1sp2c2d3dp]133|200[/hv] Do you show the three card spade support or the diamond stop? Quote Link to comment Share on other sites More sharing options...
pescetom Posted December 16, 2022 Report Share Posted December 16, 2022 MPs, playing Benj Acol weak NT: [hv=pc=n&w=sq74hak65dk6ct962&d=e&v=e&b=6&a=1sp2c2d3dp]133|200[/hv] Do you show the three card spade support or the diamond stop?Not my system and I'm not sure what the agreed meaning of 3♦ is (stop ask?) and whether that lengthens the spades or how likely they were to be 4 card in the first place.But if as I imagine 2♣ was not a game force and 3♠ is non-forcing then 4♠ looks logical and sensible to me in any case. Quote Link to comment Share on other sites More sharing options...
LBengtsson Posted December 16, 2022 Report Share Posted December 16, 2022 Not my system and I'm not sure what the agreed meaning of 3♦ is (stop ask?) and whether that lengthens the spades or how likely they were to be 4 card in the first place.But if as I imagine 2♣ was not a game force and 3♠ is non-forcing then 4♠ looks logical and sensible to me in any case. Tough hand to evaluate knowing that ♦Kx is most likely dead, there is a possible ♣ loser, and the ♠ suit (should you choose this suit as trump) could break badly. I am seriously trying to work out the hand shape (and what East actually has?) to bid 3♦ here playing Acol 4M (assumed) also? And, could 3♦ be a semi-splinter here agreeing ♣ suit? To be honest, I am not sure what the best bid is here, though I agree with pescetom that you have the values for 4♠, it might not be the best place to alight in game. Quote Link to comment Share on other sites More sharing options...
AL78 Posted December 16, 2022 Author Report Share Posted December 16, 2022 Tough hand to evaluate knowing that ♦Kx is most likely dead, there is a possible ♣ loser, and the ♠ suit (should you choose this suit as trump) could break badly. I am seriously trying to work out the hand shape (and what East actually has?) to bid 3♦ here playing Acol 4M (assumed) also? And, could 3♦ be a semi-splinter here agreeing ♣ suit? To be honest, I am not sure what the best bid is here, though I agree with pescetom that you have the values for 4♠, it might not be the best place to alight in game. No it couldn't be a semi-splinter, we don't have that agreement. I was the one bidding 3♦ and I'll give a bit of time for others to put forward an opinion if they wish but it was the only reasonable forcing action I could think of at the time. Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted December 16, 2022 Report Share Posted December 16, 2022 No it couldn't be a semi-splinter, we don't have that agreement. I was the one bidding 3♦ and I'll give a bit of time for others to put forward an opinion if they wish but it was the only reasonable forcing action I could think of at the time. What's your agreement about double over 2♦ ? to me 3♦ would be a good club raise. I'm suspecting you actually have a strong NT without a diamond stop. Quote Link to comment Share on other sites More sharing options...
AL78 Posted December 16, 2022 Author Report Share Posted December 16, 2022 What's your agreement about double over 2♦ ? to me 3♦ would be a good club raise. I'm suspecting you actually have a strong NT without a diamond stop. We haven't discussed that situation (sorry, we only play together once a month at most and my partner has been on vacation for the previous five weeks), but I would probably have something like a 5413 shape. Quote Link to comment Share on other sites More sharing options...
AL78 Posted December 16, 2022 Author Report Share Posted December 16, 2022 I have decided to post the full deal so you can see what I had and what happened. Cyberyeti was very close to estimating my hand: [hv=pc=n&s=s865hqt843dj75cj5&w=sq74hak65dk6ct962&n=sjthj7daqt982c843&e=sak932h92d43cakq7&d=e&v=e&b=6&a=1sp2c2d3dp3sp4sppp]399|300[/hv] Without the interference I would have bid 2NT showing 15-16 bal/semi-bal but can't do that without a diamond stop. 3♣ would have been non-forcing. I thus decided to cue bid firstly to establish a game force and secondly to ask partner for any further information to assist in deciding which game. If she takes it as a good hand with club support I am fine with that, otherwise it has to be forcing and asking for more information. The problem is she has one bid available and two pieces of information to show (a diamond stop and three card spade support). She decided to show her spades so I bid the spade game and after a diamond lead made 11 tricks. This was worth 6/18 MPs in a field of 10.5 tables as four other pairs bid and made 3NTW+3 on a diamond lead. Partner was disappointed we ended up in the wrong game and I tried to console her by saying the optimal piece of information to show is not obvious and it was not unreasonable to play in the spade game. With one diamond stop 3NT would have gone down and 4♠ would have made 10 tricks if the spades had broken 4-1. Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted December 16, 2022 Report Share Posted December 16, 2022 I have decided to post the full deal so you can see what I had and what happened. Cyberyeti was very close to estimating my hand: [hv=pc=n&s=s865hqt843dj75cj5&w=sq74hak65dk6ct962&n=sjthj7daqt982c843&e=sak932h92d43cakq7&d=e&v=e&b=6&a=1sp2c2d3dp3sp4sppp]399|300[/hv] Partner was disappointed we ended up in the wrong game and I tried to console her by saying the optimal piece of information to show is not obvious and it was not unreasonable to play in the spade game. With one diamond stop 3NT would have gone down and 4♠ would have made 10 tricks if the spades had broken 4-1. Clubs would need to be 4-1 offside also, you have 3 spades, 3 clubs and 2 hearts, you are pratically always making 9 in NT although that will lose out to people making 10 in spades. Once you know partner has a diamond stop, 6♣(W) comes into the equation, and in practice this makes easily. Quote Link to comment Share on other sites More sharing options...
AL78 Posted December 16, 2022 Author Report Share Posted December 16, 2022 Clubs would need to be 4-1 offside also, you have 3 spades, 3 clubs and 2 hearts, you are pratically always making 9 in NT although that will lose out to people making 10 in spades. Once you know partner has a diamond stop, 6♣(W) comes into the equation, and in practice this makes easily. Sorry, miscounted, you always have eight on top and a ninth on a diamond lead. Quote Link to comment Share on other sites More sharing options...
helene_t Posted December 16, 2022 Report Share Posted December 16, 2022 Partner will have 5-4 or better in the blacks, with other hands he could have doubled or bid hearts or nt or 3s.. It is tempting to bid 3n to protect dK against the Lead but I will just bid a normal 3s. Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted December 17, 2022 Report Share Posted December 17, 2022 Partner will have 5-4 or better in the blacks, with other hands he could have doubled or bid hearts or nt or 3s.. It is tempting to bid 3n to protect dK against the Lead but I will just bid a normal 3s. If you're playing Acol with a weak NT where you open the major with 4M4m32 what do you do with AKxx, xx, xxx, AKQx ? You either have to agree that 2N doesn't guarantee a stop, or that this hand type can double, but without that agreement ... Quote Link to comment Share on other sites More sharing options...
helene_t Posted December 17, 2022 Report Share Posted December 17, 2022 If you're playing Acol with a weak NT where you open the major with 4M4m32 what do you do with AKxx, xx, xxx, AKQx ? You either have to agree that 2N doesn't guarantee a stop, or that this hand type can double, but without that agreement ...OK good point :) yes 4-4 black is also possible although with less than gf strength I can't bid 3d. With this hand I would bid 3c or maybe dbl but add the q of spades and I would bid 3d. Partner willexpect 5 spades as 4 is exceptional. Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted December 17, 2022 Report Share Posted December 17, 2022 OK good point :) yes 4-4 black is also possible although with less than gf strength I can't bid 3d. With this hand I would bid 3c or maybe dbl but add the q of spades and I would bid 3d. Partner willexpect 5 spades as 4 is exceptional. With less than GF strength you opened 1N Quote Link to comment Share on other sites More sharing options...
helene_t Posted December 17, 2022 Report Share Posted December 17, 2022 With less than GF strength you opened 1NTrue, I must be sleeping. Yes you are right, the alternatives are dbl and 3di. Quote Link to comment Share on other sites More sharing options...
helene_t Posted December 17, 2022 Report Share Posted December 17, 2022 With less than GF strength you opened 1NTrue, I must be sleeping. Yes you are right, the alternatives are dbl and 3di. Quote Link to comment Share on other sites More sharing options...
helene_t Posted December 17, 2022 Report Share Posted December 17, 2022 With less than GF strength you opened 1NTrue, I must be sleeping. Yes you are right, the alternatives are dbl and 3di. Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted December 17, 2022 Report Share Posted December 17, 2022 True, I must be sleeping. Yes you are right, the alternatives are dbl and 3di. Or you agree 2N (which is GF playing weak NT) doesn't show a diamond stop which is not as unreasonable as you might think (we actually play 2N as GF not necessarily balanced). Arguably you could agree 3N shows the stop and only 4 spades, 2N then 3N doesn't show the stop. Quote Link to comment Share on other sites More sharing options...
AL78 Posted December 17, 2022 Author Report Share Posted December 17, 2022 Or you agree 2N (which is GF playing weak NT) doesn't show a diamond stop which is not as unreasonable as you might think (we actually play 2N as GF not necessarily balanced). Arguably you could agree 3N shows the stop and only 4 spades, 2N then 3N doesn't show the stop. Doesn't that end up wrongsiding a NT contract in some cases? Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted December 17, 2022 Report Share Posted December 17, 2022 Doesn't that end up wrongsiding a NT contract in some cases? It rarely does as in this case, but this is how we would bid the hand without the interference, except that we don't open the major with 4-4 so as it happens would wrongside clubs instead. Our auction would be (there may be more bids between 3♠ and 4♠, I don't think we'd sniff 6♣) 1♠-2♣(2♦)2N-3♥(nat 4♣/4♥)3♠(5+♠)-4♠ Quote Link to comment Share on other sites More sharing options...
Lovera Posted December 18, 2022 Report Share Posted December 18, 2022 I have decided to post the full deal so you can see what I had and what happened. Cyberyeti was very close to estimating my hand: [hv=pc=n&s=s865hqt843dj75cj5&w=sq74hak65dk6ct962&n=sjthj7daqt982c843&e=sak932h92d43cakq7&d=e&v=e&b=6&a=1sp2c2d3dp3sp4sppp]399|300[/hv] Without the interference I would have bid 2NT showing 15-16 bal/semi-bal but can't do that without a diamond stop. 3♣ would have been non-forcing. I thus decided to cue bid firstly to establish a game force and secondly to ask partner for any further information to assist in deciding which game. If she takes it as a good hand with club support I am fine with that, otherwise it has to be forcing and asking for more information. The problem is she has one bid available and two pieces of information to show (a diamond stop and three card spade support). She decided to show her spades so I bid the spade game and after a diamond lead made 11 tricks. This was worth 6/18 MPs in a field of 10.5 tables as four other pairs bid and made 3NTW+3 on a diamond lead. Partner was disappointed we ended up in the wrong game and I tried to console her by saying the optimal piece of information to show is not obvious and it was not unreasonable to play in the spade game. With one diamond stop 3NT would have gone down and 4♠ would have made 10 tricks if the spades had broken 4-1. Yes, the contract is not what even E expected. It must be considered that if the pair reaches the slam when it has a double fit, it is advisable to choose the 4-4 fit because with the other suit, losers can be discarded. Perhaps it also depends a little on the Acol system (which I don't apply) because E has a hand of 12 points:2♣ does this show directly? But maybe we meet on 3♦ which should be UCB indicating the excellent support for ♣ contract that E would have played also having the King protected on the exit of N. But having W a 5-4-2-2 and however, being at the top of the second range it was clearer to bid 4♦(=almost game) which would probably have been followed by the cue of 4♥(=12/+ points) which could direct the auction. Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted December 18, 2022 Report Share Posted December 18, 2022 Yes, the contract is not what even E expected. It must be considered that if the pair reaches the slam when it has a double fit, it is advisable to choose the 4-4 fit because with the other suit, losers can be discarded. Perhaps it also depends a little on the Acol system (which I don't apply) because E has a hand of 12 points:2♣ does this show directly? But maybe we meet on 3♦ which should be UCB indicating the excellent support for ♣ contract that E would have played also having the King protected on the exit of N. But having W a 5-4-2-2 and however, being at the top of the second range it was clearer to bid 4♦(=almost game) which would probably have been followed by the cue of 4♥(=12/+ points) which could direct the auction. 2♣ the way we play Acol shows 9+ points with 5 or 10+ with 4, Acol people vary exactly how much it shows but it usually around this (in very old fashioned Acol could be a little less). Quote Link to comment Share on other sites More sharing options...
AL78 Posted December 18, 2022 Author Report Share Posted December 18, 2022 2♣ the way we play Acol shows 9+ points with 5 or 10+ with 4, Acol people vary exactly how much it shows but it usually around this (in very old fashioned Acol could be a little less). With all my partners a 2/1 shows a good 9+HCP. Quote Link to comment Share on other sites More sharing options...
Lovera Posted December 18, 2022 Report Share Posted December 18, 2022 2♣ the way we play Acol shows 9+ points with 5 or 10+ with 4, Acol people vary exactly how much it shows but it usually around this (in very old fashioned Acol could be a little less). I thought so (9 and not 12 p. as i use to bid) and that's why i' ve talked in that way. Quote Link to comment Share on other sites More sharing options...
pescetom Posted December 18, 2022 Report Share Posted December 18, 2022 This one is easier for us, where 2♣ establishes a game force and does not promise 5 cards or deny any degree of spades support.Now we can play a 3♦ cue as a stop ask and simply raise clubs here:-- 1♠2♣ (2♦) 3♣3♠ 4♣4♦ 4♠ [♠!♥]5♥ [odd keycards, ♥♥] 5♠p Although in one eccentric partnership this would probably go:-- 1NT2♣ 2♠[5]4♠ p Quote Link to comment Share on other sites More sharing options...
Frank_lol_ Posted December 18, 2022 Report Share Posted December 18, 2022 We play a 2/1 gf system, so we use the cuebid to say:“hey, i have Axx, Kxx or Qxx, you should bid 3NT with atleast Ax, Kx, Qx so we have 2 stops”So, similar to the bidding above, ours would go:1♠-2♣ (2♦)3♣-3♠ 4♣*-4♦4♠**-4NT***5♣+-5♦++5♠+++-6♣++++* slam intrest** denies ♥ stop*** 6RKC+ 1/4++ key queens?+++ second step, 1 queen++++ opener has 5=x=x=4, 6♣ with 4-4 is the best contract Quote Link to comment Share on other sites More sharing options...
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