steve2005 Posted January 5, 2022 Report Share Posted January 5, 2022 In Transfer Walsh 1♣ is either balanced 2+♣ not in the range of 1N/2N/2♣ or 4♣441 or 5+♣.With the 1♦ and 1♥ bids being transfers showing a 4+ major. In most versions of Transfer Walsh the 1♠ response is used to show 4+ or even 5+ diamonds. For example see https://en.wikipedia.../Transfer_Walsh In one variation 1NT response is a balanced invitational hand around 10-12 hcp. In this case, the 1♠ response can include any length for the minors. The one detailed write-up available in pdf at 21twalsh.pdf (mgoetze.net) the 1♠ response shows 4+ clubs.This would seem to be more useful as it finds a club fit right away if opener has clubs.This method also uses 2M and 3M bids to show a splinter with at least 5-4 in the minors. This seems like a good idea but has a flaw when opener is 44(32) and responder is (31)(45). Any thoughts on the efficiency of which minor suit length to show with the 1♠ response to 1♣? Quote Link to comment Share on other sites More sharing options...
HardVector Posted January 5, 2022 Report Share Posted January 5, 2022 I like the 1♠ bid to show 6+ hcp and deny a major. You primarily want to clarify opener's hand, are they balanced 12-14/18-19, or are they unbalanced with real clubs? If they show balanced, you can decide if you want to play in 1n or 2c with a minimum or show better hands with other bids. Showing 4 clubs right away doesn't seem as useful as finding out about what your partner has opened. That allows 1n to show an unbalanced hand with 5+ clubs, and 2c to show diamonds. Quote Link to comment Share on other sites More sharing options...
fromageGB Posted January 5, 2022 Report Share Posted January 5, 2022 Absolutely concur with HardVector (other than I like 5+ with my lack of 4 card major). If opener rebids 1NT 12-14 then 2♣ is to play, 2♦ to play, 2♥ is 11+ 5+ clubs (remember 1♠ denies a major), 2♠ is 11+ with 5+ diamonds, and 2NT natural invite, 3m is a natural slam invitation. Given the options available with 1♠, the alternative bids of 1NT, 2♣ and 2♦ are not wanted naturally, so all can show both majors in one bid. I play 1NT as 54xx or 45xx 6+ hcp, 2♣ as exactly 4 cards both majors 11+, 2♦ as 5 cards both majors (any strength). As 1♣ 2♣ is 44xx 11+, weaker 44xx hands reply 1♦ to show hearts, and over 1♥ (denying 4) then rebid 1NT to show 4 spades. Before anyone quibbles over my 1♠ on 5+ hcp but 1NT needing 6hcp, 1NT is forcing, so if opener does not have a 4 card major he rebids 2♣ and then responder transfers to the 5. As it is forcing to the 2-level, I say 6+ while a simple 1♠ then pass 1NT is 5+ as it is at the one level. Choose your own values. Quote Link to comment Share on other sites More sharing options...
mw64ahw Posted January 5, 2022 Report Share Posted January 5, 2022 Other: I'll only show a minor suit with 5+♣/♦ when (31)(54) or 6+ otherwise with a direct 2m, so 1NT shows ~6-10hcp, no major and at worst 22(54). This frees up 1♠ to be game invitational for me Quote Link to comment Share on other sites More sharing options...
nullve Posted January 5, 2022 Report Share Posted January 5, 2022 I have played the following* in one partnership: 1♣: 11-13-or-17-19 if balanced. Forcing. 1♣-1N: can be thought of as a natural invite opposite a Woodsonian** 11-13-or-17-19 NT. (Opener rejects/accepts the invite with MIN=11-13/MAX=17-19, respectively.)1♣-1♠: like a Walsh 1♦ response if unbalanced OR a balanced hand without a major not in range for the 1N response 1♣-1♠; 1N = 11-13-or-17-19 NT. The point is to be able to stop in 1N opposite 17-19 BAL when there is no fit. For example: Opener: a) 12 BALb) 18 BAL Responder: c) 2 hcp, 3343d) 8 hcp, 3343 a)-c): 1♣-1♠; 1N-Pa)-d): 1♣-1N; Pb)-c): 1♣-1♠; 1N-Pb)-d): 1♣-1N; 3N-P * essentially an idea described by BBF contributors zenko (in 2010) and helene_t (a few years later)** The original Woodson NT is a natural 1N opening showing either 10-12 or 16-18 hcp. (Yes, simultaneously!) Quote Link to comment Share on other sites More sharing options...
helene_t Posted January 6, 2022 Report Share Posted January 6, 2022 4+ in a particular minor is not so useful, I think, you probably want to bid 1♠ with any 33(43) or 5m332 hand that can't bid 1NT for whatever reason (rightsiding, range of of 1NT, 1NT is artificial?) So I think 1♠ is whatever is left over after we defined the 1NT and 2♣ responses. We play 2♣ as 10+ points with clubs as the system evolved from a natural system where we also played inverted minors, but it may be better to play 2♣ as diamonds and 1♠ as clubs-or-balanced. Quote Link to comment Share on other sites More sharing options...
kgr Posted January 6, 2022 Report Share Posted January 6, 2022 4+ in a particular minor is not so useful, I think, you probably want to bid 1♠ with any 33(43) or 5m332 hand that can't bid 1NT for whatever reason (rightsiding, range of of 1NT, 1NT is artificial?) So I think 1♠ is whatever is left over after we defined the 1NT and 2♣ responses. We play 2♣ as 10+ points with clubs as the system evolved from a natural system where we also played inverted minors, but it may be better to play 2♣ as diamonds and 1♠ as clubs-or-balanced.This is how I play it. I will bid 1S with f.i.:rightsiding NT: Axx=xxx=Axxx=AxxGF with D: AKxx=Axx=AQxxx=xWeak with D: xx=xxx=AQxxxx=xx (after 1NT we bid then 2C as a puppet to 2D) Quote Link to comment Share on other sites More sharing options...
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