arunodoysa Posted December 3, 2020 Report Share Posted December 3, 2020 Hi All, I have a question assuming players follow Lebensohl and hence, assuming players prefer to use Lebensohl cue bid stayman. Say, N opens 1NT, E replies 2C (natural hand reply, could be 6/7 C) S has 4 card of a major eg. H (or S) and 2/3 cards C with a stopper and say a 2/3 card of the second major. How should S proceed? 1. if S bids 2NT invoking Lebensohl, N has to relay bid 3C which takes up his cue bidding space2. if S bids 3C invokings cue bid stayman, S denies stopper in C (Fast denies rule) although S actually has a stopper. Now if N does not have 4 card in H (or S), N might be in dilemma to call 3NT as N has no info that S actually has a stopper. Note that if the opponent's bid was anything else then 2C, it would be an easy stayman cue bid. Would appreciate a bidding method for this corner case. Thanks in advance! Quote Link to comment Share on other sites More sharing options...
Stephen Tu Posted December 3, 2020 Report Share Posted December 3, 2020 Natural 2c interference is exceedingly rare these days. But in any case, a large number of players play double of 2c as stayman (or alternately negative allowing opener to pass with strong clubs), so you have potentially 2 ways to bid stayman (double or 3c), one of them (probably 3c) can deny a stopper. As for Lebensohl stopper implications, you don't really get them when the suit is clubs and you use stayman, since you don't have 2nt followed by cue bid at the 3 level available, if you aren't going to utilize double of 2c. 1 Quote Link to comment Share on other sites More sharing options...
TylerE Posted December 3, 2020 Report Share Posted December 3, 2020 Systems on over 2♣ interference. X is Stayman. No Leb. No need, they haven't actually taken away any bidding space. Why go a level higher? Quote Link to comment Share on other sites More sharing options...
smerriman Posted December 3, 2020 Report Share Posted December 3, 2020 Normally when playing lebensohl, it only applies for overcalls of 2♦ - 2♠; over a 2♣ overcall, you can just play "systems on" with double = Stayman. Quote Link to comment Share on other sites More sharing options...
Vampyr Posted December 3, 2020 Report Share Posted December 3, 2020 Normally when playing lebensohl, it only applies for overcalls of 2♦ - 2♠; over a 2♣ overcall, you can just play "systems on" with double = Stayman. But if you want to have a “slow” sequence, you can agree that 3♦ is Stayman after Lebensohl. You don’t really need a third way to bid diamonds. Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted December 3, 2020 Report Share Posted December 3, 2020 But if you want to have a “slow” sequence, you can agree that 3♦ is Stayman after Lebensohl. You don’t really need a third way to bid diamonds.Alternatively, switch to Rubensohl so that 2NT becomes the Stayman call and now 3♣ from Opener denies a stop with direct 3M calls showing that major with a stop. As others have written though, it is much simpler just to play system on with X as Stayman. 1 Quote Link to comment Share on other sites More sharing options...
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