barmar Posted July 19, 2020 Report Share Posted July 19, 2020 Was this a "best hand" robot tournament? Then you know that partner has at most 16 HCP, and more likely has less. Without a fit or a running suit, it generally takes about 33 HCP to make a slam. So slam is not likely. However, since you actually do have a spade fit, 6♠ from your side (to protect the ♥K from the opening lead) is not actually a bad contract. But you'll never get there by jumping directly to 4NT. Quote Link to comment Share on other sites More sharing options...
KingCovert Posted July 20, 2020 Report Share Posted July 20, 2020 I'd imagine that would be madness. A 1 ♦ is far too unlimited for a quantative NT repsonse. It is a 12-21 HCP opening. Would opener be expected to accept with a non minimal hand of 14HCP or would a maximum of 21 be the requirement? How would opening hand be expected to handle the potential two or three suiters with a void holding minimal values? 4NT simply cannot be quantative, you need a tight range in strength AND shape in order for that to make sense. Well, if you think that partner has anywhere near 19-21 HCP with any regularity when you might bid 4NT quantitative, then, I suppose you have a point. Keycard just seems like a dumb agreement. Perhaps that's because I play Inverted Minors and Criss-Cross when I play 2/1. I just can't think of any serious auction where I'd ever bid 4NT here, but, if I ever felt like it would be right, it would be on some 2NT opener type hand, and I'd want it to be quantitative. Quote Link to comment Share on other sites More sharing options...
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