raspeball Posted April 24, 2020 Report Share Posted April 24, 2020 I wanted feedback on the following idea. Assumption you use 1nt-2nt as puppet stayman, normally only with hands with gamestrength and want to check if you should play 3nt or 4♥/♠. My proposed idea has the following respones: 3♣= No 5 card major. Could have one or both 4 card major(s), or could be a hand without 4 or 5 card major.3♦=No 4 card major. Could have a 5 card major, or could be a hand without 4 or 5 card major. So a hand with no 4 or 5 card major could choose to bid 3♣ or 3♦ randomly. Further responses could be as follows:1nt-2nt3♣ 3♦=4 card ♥ and 4 card♠3♥=4 card ♠3♠=4 card ♥3nt= No 4 card major (Was searching for 5 card major) 1nt-2nt3[♦ 3♥=3 card ♠3♠=3 card ♥3nt= Both majors, want to play 4 major if opener have a 5 card major. The advantage (i think) is that there could be less information leakage if we end up in 3nt. My questions are: 1: Assuming that you want to play 1nt-2nt as puppet, do you think this idea has merit, or has it some flaw that i have not seen?2: Do you think the method have any problems with disclosure, since a hand without 4-5 major, could bid both 3 ♣ or 3♦?3: Do you know somebody playing this already? Quote Link to comment Share on other sites More sharing options...
nige1 Posted April 24, 2020 Report Share Posted April 24, 2020 Interesting convention but artificial and complex.Please would a Moderator move this to Non-Natural System Discussion. 1 Quote Link to comment Share on other sites More sharing options...
Vampyr Posted April 25, 2020 Report Share Posted April 25, 2020 2: Do you think the method have any problems with disclosure, since a hand without 4-5 major, could bid both 3 ♣ or 3♦? Random responses are not usually truly random. They can be if partner, say, counts up his spot cards in the black suits and bids one thing if they are odd and the other if they’re even. If you don’t do something like this, there will be a pattern, and even if you haven’t worked out what it is you will have to disclose it. So yes there will be a problem. Quote Link to comment Share on other sites More sharing options...
nullve Posted April 25, 2020 Report Share Posted April 25, 2020 Interesting idea! So Opener's rebid is * always 3♣ with a 4c major;* always 3♦ with a 5c major;* 3♣ and 3♦ with probabilities p and 1-p, respectively, with no major. Obviously, you want p to be much higher than 0 so that Opener cannot be counted on to have 4 OM after 1N-2N3♣-3OM*3N-P, * 4 M and < 4 OM but you also want it to be much lower than 1 so that Opener cannot be counted on to have 5 OM after 1N-2N3♦-3OM*3N-P. * 3-4 M and < 3 OM I don't know what the best value of p is, but maybe 1/2 is close enough. If so, notice how the opening leader might apply "restricted choice" when guessing whether Opener has the other major or no major! Quote Link to comment Share on other sites More sharing options...
raspeball Posted April 25, 2020 Author Report Share Posted April 25, 2020 Random responses are not usually truly random. They can be if partner, say, counts up his spot cards in the black suits and bids one thing if they are odd and the other if they’re even. If you don’t do something like this, there will be a pattern, and even if you haven’t worked out what it is you will have to disclose it. So yes there will be a problem. Thanks for your reply. Yes this is kind of what i was thinking of. If i choose to say that with no 4 or 5 card major i bid 3♣ if I have an odd number of black cards, and 3♦ with an even number of black card, would that be ok? Quote Link to comment Share on other sites More sharing options...
raspeball Posted April 25, 2020 Author Report Share Posted April 25, 2020 Interesting idea! So Opener's rebid is * always 3♣ with a 4c major;* always 3♦ with a 5c major;* 3♣ and 3♦ with probabilities p and 1-p, respectively, with no major. Obviously, you want p to be much higher than 0 so that Opener cannot be counted on to have 4 OM after 1N-2N3♣-3OM*3N-P, * 4 M and < 4 OM but you also want it to be much lower than 1 so that Opener cannot be counted on to have 5 OM after 1N-2N3♦-3OM*3N-P. * 3-4 M and < 3 OM I don't know what the best value of p is, but maybe 1/2 is close enough. If so, notice how the opening leader might apply "restricted choice" when guessing whether Opener has the other major or no major! Good point. This is something that I did not think about.Lets say that the hand with a 4 or 5 card major are distributed like this:25% have a 5 card major, and 75% have one/two 4 card(s) major. Then i think it make sense that the hands without a 4 or 5 card major should bid 3♦ on only 25% of those hands, and 3♣ on the remaining 75%. Quote Link to comment Share on other sites More sharing options...
pescetom Posted April 25, 2020 Report Share Posted April 25, 2020 Random responses are not usually truly random. They can be if partner, say, counts up his spot cards in the black suits and bids one thing if they are odd and the other if they’re even. That would be legal, but not truly random to someone who knows anything at all about the deal (as partner does, even just looking at his own cards). It is an example of legal encryption, although difficult for partner to decrypt and pointless as it stands. Quote Link to comment Share on other sites More sharing options...
Vampyr Posted April 26, 2020 Report Share Posted April 26, 2020 Thanks for your reply. Yes this is kind of what i was thinking of. If i choose to say that with no 4 or 5 card major i bid 3♣ if I have an odd number of black cards, and 3♦ with an even number of black card, would that be ok? Yes, but that is pretty revealing to declarer. Hand parity is an interesting idea though, That would be legal, but not truly random to someone who knows anything at all about the deal (as partner does, even just looking at his own cards). It is an example of legal encryption, although difficult for partner to decrypt and pointless as it stands. You could make it more difficult by basing it on, say, your lowest red card. It is not pointless, as it is a way to (more or less) randomise two bids. The point is not whether partner can interpret it but whether declarer can. Quote Link to comment Share on other sites More sharing options...
pescetom Posted April 26, 2020 Report Share Posted April 26, 2020 You could make it more difficult by basing it on, say, your lowest red card. It is not pointless, as it is a way to (more or less) randomise two bids. The point is not whether partner can interpret it but whether declarer can. Sure, I just meant pointless as encryption in that partner has no interest in interpreting it. It's still a legal way to randomise two bids. Quote Link to comment Share on other sites More sharing options...
awm Posted April 26, 2020 Report Share Posted April 26, 2020 When opener has a five-card major, it seems like you will always want to know what it is. If responder has 0-2 in each major there's no reason to bid puppet in the first place, so after 1nt-2nt-3♦ responder will always ask. After the common 1nt-2nt-3♦-3nt-pass, defenders know opener has no four or five card major, whereas using the more standard responses opener's four-card major holding will often be less obvious (i.e. 1nt-2nt-3♣-3nt-pass and opener could be 2-4 in each major, or 1nt-2nt-3♣-3♥-3nt and opener's heart holding is hidden). The 1nt-2nt-3♦-3M sequence is just asking for a lead directional double! It seems like it's probably better to use the more standard rebids: 3♣ = no five-card major (may or may not have four-card major)3♥/3♠ = that five-card major Quote Link to comment Share on other sites More sharing options...
straube Posted April 26, 2020 Report Share Posted April 26, 2020 When opener has a five-card major, it seems like you will always want to know what it is. If responder has 0-2 in each major there's no reason to bid puppet in the first place, so after 1nt-2nt-3♦ responder will always ask. After the common 1nt-2nt-3♦-3nt-pass, defenders know opener has no four or five card major, whereas using the more standard responses opener's four-card major holding will often be less obvious (i.e. 1nt-2nt-3♣-3nt-pass and opener could be 2-4 in each major, or 1nt-2nt-3♣-3♥-3nt and opener's heart holding is hidden). The 1nt-2nt-3♦-3M sequence is just asking for a lead directional double! It seems like it's probably better to use the more standard rebids: 3♣ = no five-card major (may or may not have four-card major)3♥/3♠ = that five-card major I used to do this. Liked that it didn't leak much information. Why disclose whether opener has a 4-cd major if responder may not even have one? I also used 3D as any 4333 to be able to avoid mirrored 4M333 4M contracts. Using 3D for something so specific and relatively unimportant never seemed worthwhile but I never found a better use. Quote Link to comment Share on other sites More sharing options...
raspeball Posted April 28, 2020 Author Report Share Posted April 28, 2020 When opener has a five-card major, it seems like you will always want to know what it is. If responder has 0-2 in each major there's no reason to bid puppet in the first place, so after 1nt-2nt-3♦ responder will always ask. After the common 1nt-2nt-3♦-3nt-pass, defenders know opener has no four or five card major, whereas using the more standard responses opener's four-card major holding will often be less obvious (i.e. 1nt-2nt-3♣-3nt-pass and opener could be 2-4 in each major, or 1nt-2nt-3♣-3♥-3nt and opener's heart holding is hidden). The 1nt-2nt-3♦-3M sequence is just asking for a lead directional double! It seems like it's probably better to use the more standard rebids: 3♣ = no five-card major (may or may not have four-card major)3♥/3♠ = that five-card major Thanks for your reply. The reasoning for the proposed idea is that I hate the following auction: Responder search for one major, opener shows 5 card suit in the other, and we end up playing 3nt. Now opener have revealed way to much of his hand, and the defense gets much easier than it should be :).In my proposed idea the sequence:1nt-2nt;3♦-3♥(=3 or 4 ♠ and by implication 0-2♥)3nt=Opener does not have 5 card ♠. Opener have now shown: No 4-5 card♠, not 4♥ (Opener might still have 5 card ♥). But I see that my suggested alternative gives way to many lead directing options. Inspired by the responses i have come up with an alternative to the alternative: :) 1nt-2nt;? 3♣ responses. Denies 5 card major. May or may not have 4 card majors(Same as above)3♦=5 card ♠, or no 4 or 5 card major.3♥= 5 card ♥, or no 4 or 5 card major. Now there is room for responder to show 3 card in the major that opener might have. There are different ways to do this, one is: 1nt-2nt;3♦ ? 3♥=Asks opener to bid 3♠ with 5 spades3♠=Asks opener to bid 4♠ with 5 ♠ (Responder wants to play the hand!).3nt=Not interested in 5 card ♠. 1nt-2nt;3♥ ? 3♠=Asks opener to bid 4 ♥ with 5 card hearts.3nt=To play. Not interested in 5 card ♥. True the proposed alternative also gives the opponent more lead directing opportunities, and occasionally gives away more information than needed about openers hand. But it avoids the worst situation in my mind where opener shows a specific 5 card major and later ends up in 3nt. Quote Link to comment Share on other sites More sharing options...
nullve Posted April 28, 2020 Report Share Posted April 28, 2020 The main problem with this second variant seems to be that whenever Responder is searching for a 5-3 major fit, Opener will not be able to deny 5 cards in the major without revealing that he has in fact no major. (Compare 1N-2N3♦(1)-3♥(2)3N(3)-P (1) 5c major or no major(2) 3-4 S(3) not 5 S (so either 5 H or no major) with 1N-2N3♦(1)-3♥(2)3N(3)-P (1) 5 S or no major(2) 3-4 S(3) not 5 S (and therefore no major).) Quote Link to comment Share on other sites More sharing options...
raspeball Posted April 28, 2020 Author Report Share Posted April 28, 2020 The main problem with this second variant seems to be that whenever Responder is searching for a 5-3 major fit, Opener will not be able to deny 5 cards in the major without revealing that he has in fact no major. (Compare 1N-2N3♦(1)-3♥(2)3N(3)-P (1) 5c major or no major(2) 3-4 S(3) not 5 S (so either 5 H or no major) with 1N-2N3♦(1)-3♥(2)3N(3)-P (1) 5 S or no major(2) 3-4 S(3) not 5 S (and therefore no major).) This is true. But it is less bad that the opponent knows that I don't have a 4 or 5 card major, than that they knows that I have 5 card major when I end up in 3nt. Quote Link to comment Share on other sites More sharing options...
nullve Posted April 28, 2020 Report Share Posted April 28, 2020 Idea, using a fantasy step 3F between 2N and 3♣: 1N-2N = puppet to 3F 1N-2N; 3F -?: 3♣ = Puppet Stayman with 3-4 S and 3-4 H3♦ = 4 H and 0-2 S3♥ = 4 S and 0-2 H3♠ = 3 H and 0-2 S3N = 3 S and 0-2 H (NF) Or one could, back in reality, use 2♠ as a puppet to 2N. :( Quote Link to comment Share on other sites More sharing options...
nullve Posted April 28, 2020 Report Share Posted April 28, 2020 Another idea: * Use the Jacoby transfer 2M-1 also as "M Stayman" on choice-of-game type hands with 4 M and 0-2 OM. (Problem: Must figure out how to sign off in 3N on these hands after 1N-2M-1; 2M(= 2-3 M or 4M333). Maybe use 3♠ over 1N-2M-1; 2M as a puppet to 3N?)* Use the 2N response as a true puppet to 3♣, then over 1N-2N; 3♣, P = weak hand with 6+ C3♦ = GF, 4 cards in one major, 3 in the other...3♥ = no 5c major......3♠ = 4 H and 3 S......3N = 4 S and 3 H...3♠ = 5 H (=> e.g. 4♦ = wants partner to declare 4♥)...3N = 5 S (=> e.g. 4♥ = wants partner to declare 4♠)3♥ = GF, 3 S and 0-2 H3♠ = GF, 3 H and 0-2 S3N = NF, 3 S and 3 H Quote Link to comment Share on other sites More sharing options...
awm Posted April 28, 2020 Report Share Posted April 28, 2020 How about: 1nt-2nt = 2 (or less)-3, 3-3, or 4-3 majors (either longer)3♣ by opener forced and:... 3♦ = 4-3 majors (opener bids three of a 4M or four of a 5M or 3nt with no interest)... 3M = three cards in the other major, 0-2 here... 3nt = 3-3 majors choice of games With 4-4 or 2-4 majors just bid 2♣ stayman. 1 Quote Link to comment Share on other sites More sharing options...
nige1 Posted April 28, 2020 Report Share Posted April 28, 2020 (edited) How about 1NT - 2NT = PUP to 3♣ with 3 M and 4 OM; or with 0-2 M and 3 OM. Then after 1NT - 2NT - 3♣ -3♦ = ART 3 M and 4 OM. Then opener bids 3M with 4M, 4M with 5M, 3NT with no interest.3M = ART 0-2 M 3 OM.3NT = P/C 33 MM.With 44 MM or 0-2 M and 4 OM, just bid 2♣ Stayman. Simple, cunning, and conceals opener's hand. :) Although 1N - 2N - 3♣ - 3M: might invite a double for the lead :( Edited May 2, 2020 by nige1 Quote Link to comment Share on other sites More sharing options...
raspeball Posted April 29, 2020 Author Report Share Posted April 29, 2020 How about: 1nt-2nt = 2 (or less)-3, 3-3, or 4-3 majors (either longer)3♣ by opener forced and:... 3♦ = 4-3 majors (opener bids three of a 4M or four of a 5M or 3nt with no interest)... 3M = three cards in the other major, 0-2 here... 3nt = 3-3 majors choice of games With 4-4 or 2-4 majors just bid 2♣ stayman. That works.But after the sequence1nt-2nt3♣-3♦3♥(=4♥)-3nt(4 ♠ and 3♥)the defenders know to much. Also after the normal stayman sequence we provide the opponents with more information than we want to (With the 4-4 major hand with responder I think we have to accept it,but with the 4-2 hands it is avoidable.). I actually thought about a similar scheme, where openers 3♣ was forced.The scheme would then be:1nt-2nt3♣-? 3♦=4-4 in majors. 3♥=4 ♠, not interested in ♥. 3♠=4 ♥, not interested in ♠. 3nt=3-3 in majors. The downside here is that you cannot show the hands with 3 cards in one major, and 0-2 cards in the other (But some of those hand might be bidding 1nt-3x to show a three-suited hand anyway, depending on your agreements). Quote Link to comment Share on other sites More sharing options...
nullve Posted April 29, 2020 Report Share Posted April 29, 2020 (edited) I actually thought about a similar scheme, where openers 3♣ was forced.The scheme would then be:1nt-2nt3♣-? 3♦=4-4 in majors. 3♥=4 ♠, not interested in ♥. 3♠=4 ♥, not interested in ♠. 3nt=3-3 in majors.No Puppet variant can beat regular Stayman when Responder is 4-4 in the majors. In fact, it can only do worse. Here's why: Suppose Responder is 4-4 in the majors. Then, * if Opener has a major suit M, the best possible auction would be one where the M fit gets established without Responder revealing that he also has 4 OM (Compare e.g. your action 1N-2N(1)3♣(2)-3♦(3)3♥(4)-4♥P (1) puppet to 3♣(2) forced(3) 4 S and 4 H (4) 4-5 H with the regular Stayman auction (which also happens to be the LIPS (= Low Information Puppet Stayman) auction) 1N-2♣2♥-4♥P.) * if Opener has no major, the best possible auction would be one where he shows that (which is equivalent to answering 'No' to the two questions 'Do you have 4 or 5 hearts?' and 'Do you have 4 or 5 spades?') and Responder doesn't show a specific major (Compare your auction 1N-2N(1)3♣(2)-3♦(3)3N(4)-P (1) puppet to 3♣(2) forced(3) 4 S and 4 H (4) no major or the LIPS auction 1N-2♣(1)2♦(2)-3N(3)P (1) like regular Stayman, but not used on choice-of-game type hands with only one 4c major (which go through 1N-3♣, or LIPS proper)(2) no major(3) 4 S and 4 H with the regular Stayman auction 1N-2♣2♦-3N(1)P (1) 4 S or 4H .) Edited April 29, 2020 by nullve Quote Link to comment Share on other sites More sharing options...
raspeball Posted April 29, 2020 Author Report Share Posted April 29, 2020 No Puppet variant can beat regular Stayman when Responder is 4-4 in the majors. In fact, it can only do worse. Here's why: Suppose Responder is 4-4 in the majors. Then, * if Opener has a major suit M, the best possible auction would be one where the M fit gets established without Responder revealing that he also has 4 OM (Compare e.g. your action 1N-2N(1)3♣(2)-3♦(3)3♥(4)-4♥P (1) puppet to 3♣(2) forced(3) 4 S and 4 H (4) 4-5 H with the regular Stayman auction (which also happens to be the LIPS (= Low Information Puppet Stayman) auction) 1N-2♣2♥-4♥P.) * if Opener has no major, the best possible auction would be one where he shows that (which is equivalent to answering 'No' to the two questions 'Do you have 4 or 5 hearts?' and 'Do you have 4 or 5 spades?') and Responder doesn't show a specific major (Compare your auction 1N-2N(1)3♣(2)-3♦(3)3N(4)-P (1) puppet to 3♣(2) forced(3) 4 S and 4 H (4) no major or the LIPS auction 1N-2♣(1)2♦(2)-3N(3)P (1) like regular Stayman, but not used on choice-of-game type hands with only one 4c major (which go through 1N-3♣, or LIPS proper)(2) no major(3) 4 S and 4 H with the regular Stayman auction 1N-2♣2♦-3N(1)P (1) 4 S or 4H .) Good point!The 4-4 major hand should then bid 2♣.If the 4-4 major hands can be taken out, that make the 3 ♦ free for other purposes:1nt-2nt3♣-?3♦=one 3 card major, not interested in the other major(Opener relays with 3♥, and responder bids 3♠ with 3 card hearts and 3nt with 3 card spades)3♥=4 ♠, not interested in ♥.3♠=4 ♥, not interested in ♠.3nt=3-3 in majors. Another option is to use 3♦ as awm suggested, but with opener always relaying for information (So that defenders does not know if he has the other major or not, if we ends up in 3nt) Quote Link to comment Share on other sites More sharing options...
nullve Posted April 29, 2020 Report Share Posted April 29, 2020 Another option is to use 3♦ as awm suggested, but with opener always relaying for information (So that defenders does not know if he has the other major or not, if we ends up in 3nt)Well, I think what I suggested, which was 3♦ = GF, 4 cards in one major, 3 in the other...3♥ = no 5c major......3♠ = 4 H and 3 S......3N = 4 S and 3 H...3♠ = 5 H (=> e.g. 4♦ = wants partner to declare 4♥)...3N = 5 S (=> e.g. 4♥ = wants partner to declare 4♠), is even better, but let me explain. If Opener has a 5c major M, then he will eventually be forced to reveal it, because he has the kind of hand that should play 4M opposite Responder's promised 3 or 4c support. So temporarily concealing the suit by using a mandatory 3♥ relay can be no better than letting 3♥ deny 5 M. It's actually worse, because if the contract is going to be 4M after 1N-2N3♣-3♦3♥(1) (1) relay anyway, because Opener has 5 M, * Responder will have revealed whether he is 4-3 or 3-4 in the majors [compare with the situation after 1N-2N; 3♣-3♦; 3M+1 = 5 M];* a lead-directing double is available to Advancer over 1N-2N; 3♣-3♦; 3♥-3♠ [compare with the situation after 1N-2N; 3♣-3♦; 3♠ = 5 H]* only Opener can be declarer in 4♥ after 1N-2N; 3♣-3♦; 3♥ [compare with the situation after 1N-2N; 3♣-3♦; 3♠ = 5 H];* only Responder can be declarer in 4♠ after 1N-2N; 3♣-3♦; 3♥-3♠ [compare with the situation after 1N-2N; 3♣-3♦; 3N = 5 S]. Quote Link to comment Share on other sites More sharing options...
raspeball Posted April 29, 2020 Author Report Share Posted April 29, 2020 Well, I think what I suggested, which was , is even better, but let me explain. If Opener has a 5c major M, then he will eventually be forced to reveal it, because he has the kind of hand that should play 4M opposite Responder's promised 3 or 4c support. So temporarily concealing the suit by using a mandatory 3♥ relay can be no better than letting 3♥ deny 5 M. It's actually worse, because if the contract is going to be 4M after 1N-2N3♣-3♦3♥(1) (1) relay anyway, because Opener has 5 M, * Responder will have revealed whether he is 4-3 or 3-4 in the majors [compare with the situation after 1N-2N; 3♣-3♦; 3M+1 = 5 M];* a lead-directing double is available to Advancer over 1N-2N; 3♣-3♦; 3♥-3♠ [compare with the situation after 1N-2N; 3♣-3♦; 3♠ = 5 H]* only Opener can be declarer in 4♥ after 1N-2N; 3♣-3♦; 3♥ [compare with the situation after 1N-2N; 3♣-3♦; 3♠ = 5 H];* only Responder can be declarer in 4♠ after 1N-2N; 3♣-3♦; 3♥-3♠ [compare with the situation after 1N-2N; 3♣-3♦; 3N = 5 S]. You are correct, your way is better if 3♦ shows 4-3 or 3-4 in the majors (I did not read carefully enough what you wrote, and not even what i wrote myself !) :) But in the sequence:1nt-2nt3♣-3♦?I dont see why opener cannot bid 3♥ with 5 card hearts sometimes (Especially if he is not afraid of a lead directing double of 3 ♠, and he prefer to declare the hand himself). If responder shows 4 hearts, opener can play play 4hearts without showing that he has 5 hearts:1nt-2nt;3♣-3♦3♥-3♠4♥ If responder bid 3nt, opener can still correct to 4♥.And I assume that opener can jump directly to 4♥/♠ over 3♦, if he think that he should declare :) Another (stupid) idea that is that opener shows that he might or might not have one major: 1nt-2nt?3♣=Denies 4 or 5 card spades.(Opener might or might not have 4 or 5 card hearts).3♦=Denies 4 or 5 card hearts.(Opener might or might not have 4 or 5 card spades).With both majors one possibility is that opener bids 3nt directly (Leaking information if responder only was interested in 5 card majors). This leaves room for responder to choose who should declare. After 3♣ from opener, responder bid 3nt if he is not interested in hearts, or bids 3♥ with 3 card hearts, and 3♠ with 4 hearts.Simillary after 3♦ from opener responder bids 3nt with no interest in spades, and 3♥ with 4 spades and 3♠ with 3 card spades. Quote Link to comment Share on other sites More sharing options...
glen Posted April 29, 2020 Report Share Posted April 29, 2020 Fun thread, thanks everybody 1NT-2NT Modified Puppet, after 2NT: 3♣: any hand except not five hearts and hands five spades or without a four card major can bid 3♦3♦: four ♥s, 3♥ asks (3NT 3-4-3-3, 3♠ slam interest, 4♥ to play), 3♠: 5♠s, 3NT: not four ♥s or five ♠s3♥: four ♠s, 3♠ asks (3NT 4-3-3-3, 4♣ slam interest, 4♠ to play), 3NT: fewer than 4♠s3♠: 0-2 ♠s, fewer than 4 ♥s (should be 3 ♥s exactly)3NT: 3 ♠s, 0-3♥s3♦: asks doubleton or shorter major, only bid or 3♥ with five ♥s, can have five ♠s or no four card or longer major3♥: 0-2 ♥s, 3-4 ♠s3♠: 0-2 ♠s, 3-4 ♥s3NT: 3-4 ♠s, 3-4 ♥s3♥: describe ♥ length only, with four or five ♥s:3♠: 3 ♥s3NT: 0-2 ♥s4♣: slam interest 4♥s4♥: 4♥s to play3NT: to play, usually no five or four card major though can be flat with no suit interest Quote Link to comment Share on other sites More sharing options...
nullve Posted April 29, 2020 Report Share Posted April 29, 2020 I dont see why opener cannot bid 3♥ with 5 card hearts sometimes (Especially if he is not afraid of a lead directing double of 3 ♠, and he prefer to declare the hand himself). If responder shows 4 hearts, opener can play play 4hearts without showing that he has 5 hearts:1nt-2nt;3♣-3♦3♥-3♠4♥ If responder bid 3nt, opener can still correct to 4♥.True. I didn't think of that. :( And I assume that opener can jump directly to 4♥/♠ over 3♦, if he think that he should declare :)Yes, but at the cost of revealing that he has honours he wants to protect. Quote Link to comment Share on other sites More sharing options...
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