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Patching the holes in a transfer system


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1NT = strong unbalanced with no 4M (responder's 2 negative can be passed with clubs and a minimum)

2m = natural unbalanced with no 4M

I'd prefer to separate 5m4Om from 6+ m before it's too late, so maybe

 

1N = 10-15, (31)54* / "10-15", 6+ D, no M / "10-15", 5D5C / "16+", unBAL, no M

...2 = to play opposite 10-15, 5D4C

......P = "10-15, 4+ C"

......2 = "10-15", 6+D4-C

......2+ = "16+"

...2 = to play opposite "10-15"

......P = "10-15"

......2+ = "16+"

...(...)

2 = "10-15", 6+ C, no M

2 = 10-15, (31)45.

 

?

 

A slight variation that enables Responder to pass 2 more often, but at the cost of having the 1N opening only promise 4 D:

 

1N = 10-15, (31)45* / "10-15", 6+ D, no M / "10-15", 5D5C / "16+", unBAL, no M

...2 = to play opposite 10-15, 4D5C

......P = "10-15", 5+ C

......2 = "10-15", 6+D4-C

......2+ = "16+"

...2 = to play opposite "10-15"

......P = "10-15"

......2+ = "16+"

...(...)

2 = "10-15", 6+ C, no M

2 = 10-15, (31)54.

 

* treating instead 22(54) as BAL

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