pescetom Posted January 29, 2020 Report Share Posted January 29, 2020 MP[hv=pc=n&w=sat4hq4dkjcakj642&e=sj76ha72daq76cq53&d=s&v=n&b=15&a=p?]266|200[/hv] Seeing both hands it appears that EW can't go far wrong however they bid, yet in last night's MP tournament only 41% of tables actually bid a slam here (16% bid 6♣, 25% bid 6NT, 52% bid 3NT). What would your usual methods have led to, assuming an uncontested auction? Quote Link to comment Share on other sites More sharing options...
Tramticket Posted January 29, 2020 Report Share Posted January 29, 2020 It's always easy when you can see the two hands. The key is west's rebid: playing our (weak NT) system after the bidding starts 1♣-1♦, I will have a choice between 3♣, 1NT (15-18) and 2NT (19-20). The playing strength in the club suit would persuade me to choose to rebid 2NT and I would hope that this would persuade East to push on to slam. Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted January 29, 2020 Report Share Posted January 29, 2020 For us: 1♣(4+)-3N (opposite a club, this is precisely 3343 13-15) now there are lots of ways of continuing,a pretty likely one being: 4♦(keycard)-5♣(2+Q)5♦(K)-5N(something I can't show another way so ♦Q with no major K)6N (can count 12 and 13 can't be better than a finesse) Quote Link to comment Share on other sites More sharing options...
TMorris Posted January 29, 2020 Report Share Posted January 29, 2020 MP[hv=pc=n&w=sat4hq4dkjcakj642&e=sj76ha72daq76cq53&d=s&v=n&b=15&a=p?]266|200[/hv] Seeing both hands it appears that EW can't go far wrong however they bid, yet in last night's MP tournament only 41% of tables actually bid a slam here (16% bid 6♣, 25% bid 6NT, 52% bid 3NT). What would your usual methods have led to, assuming an uncontested auction? And if the Q ♦ were the Q ♠ how would one bid it? Quote Link to comment Share on other sites More sharing options...
pescetom Posted January 29, 2020 Author Report Share Posted January 29, 2020 For us it would go much like Cyberyeti, 1♣-2♣(semi-artificial) or 1♣-3NT, after either of which 4♦ is RKCB(♣).If responder did bid a natural 1♦ then we would probably proceed 2NT 4NT 6NT which may be old fashioned but still has sense I think.I wouldn't be keen to reverse into 2♠ on three cards, but the hand can take it and that should work out well too. After a 1♦ response I saw one West rebid a natural 3♣, which I don't much like here but surely deserved more than the 3NT response it received. Quote Link to comment Share on other sites More sharing options...
pescetom Posted January 29, 2020 Author Report Share Posted January 29, 2020 And if the Q ♦ were the Q ♠ how would one bid it? Meaning that East holds ♠QJ76 ♥A72 ♦A76 ♣Q53 ?I don't see that as a real problem in bidding terms, assuming East will respond 1♠. A rebid of 3♣ looks better now, or one could still risk 2NT or even 2♦ if that is known style. Quote Link to comment Share on other sites More sharing options...
helene_t Posted January 29, 2020 Report Share Posted January 29, 2020 Playing Forum Precision, we might bid1♣-2NT (13-15)6NT or maybe1♣-2NT (13-15)4♣-4♦(control)4♠-4NT (should be to play but conveniently is is RKC for clubs)5♣(0/3)-5NT(all)6NT(minimum) But this is a bit pointless as we probably can't stop below slam anyway even if we miss two keycards, so the first auction is better. However, Walter Walrus wouldn't bid it with a combined 31 points, and I could see myself ending in 3NT, after for example (standard bidding)1♣-1♦2NT-3NT In Benji Acol, as I played with pick-upps in Lancaster, it might go2NT-6NT I am learning Polish Club at the moment so I am curious if someone can help me out:1♣-1♦2♣- 2NT ?We obviously don't play full system on after 2♣ as responder can't have a game force with length in a major, so maybe 2NT shows this. Opener could maybe bid 6NT now, but responder is unlimited so it's a bit crude. Maybe just 3♣ and then some control bids? Quote Link to comment Share on other sites More sharing options...
gwnn Posted January 29, 2020 Report Share Posted January 29, 2020 I am learning Polish Club at the moment so I am curious if someone can help me out:1♣-1♦2♣- 2NT ?We obviously don't play full system on after 2♣ as responder can't have a game force with length in a major, so maybe 2NT shows this. Opener could maybe bid 6NT now, but responder is unlimited so it's a bit crude. Maybe just 3♣ and then some control bids?I played1C-2S = balanced invite or balanced rightsiding.1C-2NT = 13+ balanced, GF. 1C-1D2C-2NT sounds more likeAxxQxxJxxxxxx(1C-1D was either 0-7 or 8-11 unbalanced 1 or 2 minors.) 1 Quote Link to comment Share on other sites More sharing options...
nige1 Posted January 29, 2020 Report Share Posted January 29, 2020 [hv=pc=n&w=sat4hq4dkjcakj642&e=sj76ha72daq76cq53&d=s&v=n&b=15&a=P1C(!C or BAL)P2C(ART 12+ HCP)P2D(Sound opener G/F)P3N(MIN BAL)P6N(Punt)]266|200|pescetom "MP. Seeing both hands it appears that EW can't go far wrong however they bid, yet in last night's MP tournament only 41% of tables actually bid a slam here (16% bid 6♣, 25% bid 6NT, 52% bid 3NT). What would your usual methods have led to, assuming an uncontested auction?+++++++++++++++++++++++++++ Perhaps, on a good day :) [/hv] 1 Quote Link to comment Share on other sites More sharing options...
KingCovert Posted January 30, 2020 Report Share Posted January 30, 2020 Probably 6♣. Depends which one of us is West, my partner might find 6NT. Not sure that he would decide it's better though... I wouldn't think of it probably. 1♣ = 15+ (in 1st and 2nd seat)1♦ = Game-Forcing2♣ = 4+♣2NT = 3-♣, no 5-card suit, Stronger than 3NT.3♣ = 6+♣, no 2nd suit.3♦ = Ace of diamonds.3♠ = Ace of spades.4♥ = Ace of hearts.5♦ = King of diamonds.6♣ = To Play. 6NT? Kind of hard for West to really see it though. 3♦ should agree clubs, in my mind, since we can never have diamond fit as West has no 2nd suit, and East has no 5-card suit. Possibly a slam try in No-Trump though.5♦ should 100% show both AK♣, given the lack of a 4NT bid for 1430.After 3♦, I might just bid 1430, but, I think this might throw away any chances at grand. I really can't ever know when it's on in a 1430 auction. Partner is flat though, seems unlikely. So, in keeping this in mind, I might also just pragmatically bid 6♣ directly over 3♦. Quote Link to comment Share on other sites More sharing options...
ahydra Posted February 2, 2020 Report Share Posted February 2, 2020 Transfer Walsh 1C-1S (5+ pts no major)3C-4C4D-4H (cues)4S-4N (cue, 1430)5D-?? I'm not sure if East picks 6N as it's pairs, or 6C to be safe - knowing of 6C, 3D and 2 major aces, you may need to build a trick in a major after discarding the other major on the diamonds. For sure opps are leading a major so I think 6C is more prudent. The DJ is a huge card but neither player knows it. If playing a style where 5N followup to RKC can't be raised to 7, then that works well (on another hand) as it reveals to East if there is a 12th quick trick. ahydra Quote Link to comment Share on other sites More sharing options...
AL78 Posted February 2, 2020 Report Share Posted February 2, 2020 I doubt I would find it with any of my regular partners. The only way I can see playing some variety of Acol is as follows: 1♣ - 1♦2NT* - 4NT**6NT *18-19 HCP** Quantitative Far more likely, it would go: 1♣ - 1♦3♣ - 3NT or 1♣ - 1♦2NT - 3NT Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.