qlpsecond Posted February 23, 2019 Report Share Posted February 23, 2019 首先，明确前提开叫2C需要6张梅花（无论是否有4张高花），这是Berkowitz书中推荐的，网上的Rodwell访谈......也是这样设定的。在Berkowitz的书中，有这么一个论述开叫1D，应叫1S，开叫人再叫2C，这个序列......开叫人除了双低套之外，还可能是1444/1453/1435 我想请教一下后续进程中，怎么明确开叫人的牌情呢？如果没有已经明确的方案（也就是说需要自己设计），那该怎么设定呢？ 谢谢！ Quote Link to comment Share on other sites More sharing options...
ynhhyjb Posted February 25, 2019 Report Share Posted February 25, 2019 请附上具体牌例。 Quote Link to comment Share on other sites More sharing options...
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