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Jettison


nige1

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[hv=pc=n&s=SAKQHKDAKCAK76543&w=S8HT987D9876CQJT9&n=SJT9HAQJ32DQJT2C2&b=1&a=PP7NPPP&p=HT]399|300|

Yesterday, on Bridgez.com, there was a deal like this, which I've slightly embellished

7N by South on a lead

[/hv]

[hv=pc=n&s=SAQJT987HKQ6DK87&w=S6HJT987DQJT9CKQJ&n=SKHADACA32AT98765432&b=2&a=PP7NPPP&p=S6]399|300|

Similar theme.

7N by South on a lead.

[/hv]

[hv=pc=n&s=sAQJ76543h8dc9764&n=s2hA765432dA932cA&b-3&a=1HP1SP2DP3C(FSF)P3DP4N(RKC)P5C(0/3)P6SP6NPPP&p=HKHAH9H8]400|300|

Against South's 6N,

LHO leads K won by dummy's A while RHO follows with 9.

After this start, declarer can make on any subsequent defence.

How must declarer play?

What are the defenders' hands?

 

 

Hint

 

LHO all honours

 

[/hv]

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[hv=pc=n&w=SKHKQJTDKQJTCKQJT&s=sAQJ76543h8dc9764&n=s2hA765432dA932cA&b=3&a=1HP1SP2DP3C(FSF)P3DP4N(RKC)P5C(0/3)P6SP6NPPP&p=HKHAH9H8S2S8SASKSQCTD2S9SJCJD3STS7CQH2D4S6DTH3D5S5DJH4D6S4HTH5D7S3{!S3 triple-squeezes LHO. if LHO discards a !H, then you cross to !CA and concede a !H. If LHO discards a !D then dummy's !D9 is good. So LHO discards his last !C, you discard !CA and RHO is squeezed.}CKCA{+ If RHO discards a !D then you endplay him in !C, with the !C7. So RHO discards a !C. Now you cash !C9 and lead !C7, squeezing LHO again. Dummy discards the red suit that LHO keeps.}C2C9HJH6C3C7HQD9C8{+<br>Finally, RHO is endpayed because dummy and declarer's hand are both high.}]700|700|

Composed for Elena Jeronimidis BridgePlus magazine.

Andrew Robson republished it in the Times.

For completeness, here is the solution.

Please keep pressing Next for play and explanation.[/hv]

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Hello.

 

For the first board above, it goes like this.

 

South wins the opening lead with the A in dummy, dropping the K, then plays QJ, discarding AK from hand. Then play QJ10 from dummy, discarding AKQ. Then J109 from dummy.

 

Just before 9, West has this:

-

9

9

QJ10

 

Simple squeeze. If W throws a , N can cash two and two . If W throws a , South's four . If W throws a , N plays 2 to continue the squeeze.

 

I didn't cheat! I've figured it out for myself. Now if only I pull something like this off in actual play!

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I am not sure that the diagram is quite working (or I am being stupid). Surely west can throw a diamond at trick 11 and east can exit in diamonds at trick 12? Or have I missed something?

If East keeps x 8xx then declarer cashes 9 and exits with 7.

The losing squeezes West again. Dummy keeps the red suit that West abandons.

Hence, after winning 8, East is endplayed, because both dummy and declarer's hand are high.

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[[hv=pc=n&s=SAQJT987HKQ6DK87&e=S6HJT987DQJT98CQJT&n=SKHADACA32AK98765432&b=4&a=PP7NPPP&p=S6]399|300|

A variant of the 2nd problem, composed for Bridge World, was something like this.

South to make 7NT on a lead.[/hv]

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If East keeps x 8xx then declarer cashes 9 and exits with 7.

The losing squeezes West again. Dummy keeps the red suit that West abandons.

Hence, when RHO wins 8, he is endplayed, because both dummy and declarer's hand are high.

You have reduced to:

 

[hv=pc=n&s=shdc764&w=shqdkqc&n=sh76dac&e=shd8c85]399|300[/hv]

 

In this trick 11 position, you are showing west discarding a heart and agree that both dummy and declarer's hands are high.

 

But on the 7, West can throw Q and East wins with the eight and exits in diamonds. West will take the last trick with the Q.

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[[hv=pc=n&s=SAQJT987HKQ6DK87&e=S6HJT987DQJT98CQJT&n=SKHADACA32AK98765432&b=4&a=PP7NPPP&p=S6]399|300|

A variant of the 2nd problem, composed for Bridge World, was something like this.

South to make 7NT on a lead.[/hv]

I think the start is fairly straightforward. S overtakes the K with the A and cashes all the spades, throwing clubs plus A. Then K throwing a club. Five cards left:

North:

-

-

A

AK98

South:

-

Q6

K87

-

 

What happens when S plays the Q depends on what E has kept. Suppose he's abandoned the hearts and is left with:

-

-

QJ

QJ10

 

Then S throws another club and watches E's discard. If a diamond, S cashes 6 throwing A and cashes three diamonds. If E throws a club, S throws a club on 6 and dummy is high.

 

But if E has kept two hearts (no point in keeping one), he cannot have kept two diamonds and three clubs. S makes the same discard but on Q this time.

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You have reduced to: [hv=pc=n&s=shdc764&w=shqdkqc&n=sh76dac&e=shd8c85]399|300[/hv]

In this trick 11 position, you are showing west discarding a heart and agree that both dummy and declarer's hands are high.

But on the 7, West can throw Q and East wins with the eight and exits in diamonds. West will take the last trick with the Q.

[hv=pc=n&s=shdc764&w=shqdkqc&n=sh7da9c&e=shd8c85]399|300|

Sorry, Tramticket, you are quite right,

I made a mistake in the solution above,:(

(It's quite hard to ensure that every trick is correct,

especially when your sight is poor)

When declarer leads 7, dummy should comprise x and A9.

Now the claim thatt "West is squeezed again" becomes correct..

Dummy keeps the suit that West abandons :)

I've corrected my solution above to reflect your criticism

Thank you,[/hv]

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I think the start is fairly straightforward. S overtakes the K with the A and cashes all the spades, throwing clubs plus A. Then K throwing a club. Five cards left:

North:

-

-

A

AK98

South:

-

Q6

K87

-

 

What happens when S plays the Q depends on what E has kept. Suppose he's abandoned the hearts and is left with:

-

-

QJ

QJ10

 

Then S throws another club and watches E's discard. If a diamond, S cashes 6 throwing A and cashes three diamonds. If E throws a club, S throws a club on 6 and dummy is high.

 

But if E has kept two hearts (no point in keeping one), he cannot have kept two diamonds and three clubs. S makes the same discard but on Q this time.

661_Pete has the correct idea and his ending is nearly right but

declarer must wait to jettison of a red ace

until after East has committed himself.

For example, In his suggested ending,

East can defeat the contract by keeping JT QJT

 

The solution is for declarer to delay the discard of the appropriate red ace,

until his last ,

As 661_Pete points out, If East abandons and

obstinately hangs onto his s, then,

on declarer's last , declarer jettisons dummy's A..

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661_Pete has the correct idea and his ending is nearly right but

declarer must wait to jettison of a red ace

until after East has committed himself.

For example, In his suggested ending,

East can defeat the contract by keeping JT QJT

 

The solution is for declarer to delay the discard of the appropriate red ace,

until his last ,

As 661_Pete points out, If East abandons and

obstinately hangs onto his s, then,

on declarer's last , declarer jettisons dummy's A..

Thanks. I was already thinking, after I'd posted above, that I hadn't quite covered every eventuality. And I don't claim any skills at DD problem-solving!

 

Certainly a very difficult and complex squeeze! Surely even a world-class player would have a hard time bringing that off in actual play! (though I suppose the Hideous Hog might...)

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Surely even a world-class player would have a hard time bringing that off in actual play! (though I suppose the Hideous Hog might...)

IMO...

  • A good player would solve the 1st problem, in ordinary play, at the table.
  • A player would solve the 2nd problem, only at double-dummy. At the table, one would play for a 2-1 break.
  • A good player might solve the 3rd problem, single-dummy, but it's hard and would take one some time.

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