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Make 6 spades


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I’m stumped, even with Badgers clue. The only line of play I could find was to win the diamond lead, play the heart queen, and then play North’s remaining heart honors until one of them wins. However, this doesn’t work because there aren’t enough entries to North unless East plays the king on the first round of hearts.
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I’m stumped, even with Badgers clue. The only line of play I could find was to win the diamond lead, play the heart queen, and then play North’s remaining heart honors until one of them wins. However, this doesn’t work because there aren’t enough entries to North unless East plays the king on the first round of hearts.

 

You've identified the problem! Can you figure out the solution? Clearly winning 1 diamond and playing hearts doesn't work due to entries, as you have correctly identified...

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It's not even like there's a possible finesse to take where the card is offside... you just have to find the right line to overcome the entry problem. DD just distracts from this in my opinion.

I usually do post SD first then DD later, but in this case I thought DD did not help much anyway. An intermediate is likely to still have difficulty in eliminating the impossible to embrace the unlikely.

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play A, K and drop A on K. run Q discarding a if East does not cover.

Correct

 

In real play, I've only seen one hand where discarding an ace might have been necessary, unfortunately the opps didn't find the lead that would have necessitated it.

 

[hv=pc=n&s=s5hada96542cak742&n=sakq87642hkqj5dc6&d=n&v=b&b=13&a=2cp3dp4sp7n]266|200[/hv]

 

Unusual auction consisting only of jump bids and the best hand I've ever held opposite a 2 opener, unfortunately they didn't lead a spade

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Since it is described as a classroom problem, perhaps a classroom observation is appropriate. It can be very useful to count 12 tricks and then plan out how they will be taken. In this case. it's 7 spade tricks,. 2 heart tricks, 2 diamond tricks, 1 club trick..

 

What can go wrong? And what can be done? As soon as we see that the heart A is not needed to total 12, and then see that is an obstacle, we are apt to see the solution.

 

Not all hands can be thoroughly planned at T1, but some can. Not that I always take my own advice.

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A 4NT opening (asking for specific aces) is a bid that I never make at the table - but often seem to make in discussion forums.

It wouldn't help you here, if you got the answer of two aces.

 

Just realised you might be talking about the original hand. It still wouldn't help, but in this case because you don't have enough tricks.

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Correct

 

In real play, I've only seen one hand where discarding an ace might have been necessary, unfortunately the opps didn't find the lead that would have necessitated it.

 

[hv=pc=n&s=s5hada96542cak742&n=sakq87642hkqj5dc6&d=n&v=b&b=13&a=2cp3dp4sp7n]266|200[/hv]

 

Unusual auction consisting only of jump bids and the best hand I've ever held opposite a 2 opener, unfortunately they didn't lead a spade

Wouldn't be such a great contract if the reason for not leading a spade was not having one.:)

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A 4NT opening (asking for specific aces) is a bid that I never make at the table - but often seem to make in discussion forums.

My question was to msjennifer about the responder in the OP hand.

 

But yes opener in your hand might like to use 4nt, although he needs an unusual version as he lacks three aces of which only two of interest. We would have bid 1S 2D.

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Out of interest, after a 1S opening would you force to game with North hand?

As a matter of fact ,although there is a Qxx support and 13 HCP there are 8 losers and there are no ruffing values allso.The game can be there if S has 6 or less losers.He has not opened 1NT and so if he has a normal 5332 hand and 7 losers 4S may not make.Playing Precision a response of 1NT is .one round forcing followed by 3S the next round.Playing Standard we bid 2D and follow with 2/3/4 S depending on openers rebid.I can not for sure say what will be the bidding by a pair which plays gadget like Gazzilli.In the present South hand there are four losers and the slam will duly be reached.This apart one has to play with the field and so a bid of 2NT by N is quite acceptable as with 13 HCP every other pair is almost certain to bid some game.

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