MrAce Posted October 1, 2016 Report Share Posted October 1, 2016 Why not take the club finesse at trick 3 (after cashing the ♥A and seeing that both opps follow)? The point is: * If there are 4 diamond tricks available, taking the club finesse can never cost the contract.* If there are at most 3 diamond tricks available, we'll need to take the club finesse at some point anyway.* The number of diamond tricks we need depends on how the club suit behaves. (There are 4 possibilites to consider, in terms of who has the ♣K and whether clubs split (32).) Because when ♦K is on, when you take the club finesse first you are reducing your chances of making 3 ♣ tricks. You are losing to all 4-1 stiff K and Kxxx with East and Kxxxx with East. You are dropping about 17% of your odds to make 3 club tricks Quote Link to comment Share on other sites More sharing options...
661_Pete Posted October 1, 2016 Report Share Posted October 1, 2016 Well - without looking at any of the other answers: 9 top tricks. Possible two more in clubs if the King is with East or they break 3-2. I don't like that club finesse though: even if it wins the cards have to lie very nicely for four tricks. And I don't think there's a squeeze on. Even if I duck the spade lead. So I'd simply go for the diamond finesse. If it fails - well you can still try for a lucky lie of the cards in clubs. Quote Link to comment Share on other sites More sharing options...
msjennifer Posted October 1, 2016 Report Share Posted October 1, 2016 No.I don't think this is a sure tricks problem.A small diamond from North and if easts 10 appears,finesse the Q and if it does win then there are no further problems.If the 10 has not appeared and the Q wins switch to clubs and hope they break 3/2.There is no fool proof play. Quote Link to comment Share on other sites More sharing options...
nullve Posted October 1, 2016 Report Share Posted October 1, 2016 Because when ♦K is on, when you take the club finesse first you are reducing your chances of making 3 ♣ tricks. You are losing to all 4-1 stiff K and Kxxx with East and Kxxxx with East. Yes, unless losing a club trick also means that my line is losing. The cases where I "lose": a) LHO has the stiff ♣Kb) RHO has the stiff ♣Kc) RHO has ♣Kxxx(x) In all cases we can assume that the ♦K is onside, or else all realistic lines will fail. But then a) and c) aren't really bad for me at all, as RHO will eventualy be squeezed in the minor suits. And b) isn't necessarily that bad for me either, since on many layouts it will be possible to get 3 diamond tricks without letting opps in. That might actually be the most likely outcome, as RHO not only is favourite to have diamond length but per hypothesis also has the ♦K. 1 Quote Link to comment Share on other sites More sharing options...
ncohen Posted October 1, 2016 Report Share Posted October 1, 2016 Good discussion.The standard way of playing clubs is best -- to A, then to QJ. The posters have pointed out that running the Q works against 5 4-1 splits, but the boring normal play works against 6 -- any of 5 singletons in W, singleton K in E. Quote Link to comment Share on other sites More sharing options...
ncohen Posted October 1, 2016 Report Share Posted October 1, 2016 Another idea on playing clubs when D finesse wins: Lead to Q or J first, without cashing A. If E plays 9 or 10, run the remaining honor from S next. This has the possibility of picking up 7 4-1 club holdings -- any singleton but K in W, singleton K, 10, 9 in E. The success is reduced by an expert E who falsecards 10 or 9 from K109x, and from beginner E who plays the 9 or 10 to "force" the Q from S. Quote Link to comment Share on other sites More sharing options...
MrAce Posted October 1, 2016 Report Share Posted October 1, 2016 Yes, unless losing a club trick also means that my line is losing. The cases where I "lose": a) LHO has the stiff ♣Kb) RHO has the stiff ♣Kc) RHO has ♣Kxxx(x) In all cases we can assume that the ♦K is onside, or else all realistic lines will fail. But then a) and c) aren't really bad for me at all, as RHO will eventualy be squeezed in the minor suits. And b) isn't necessarily that bad for me either, since on many layouts it will be possible to get 3 diamond tricks without letting opps in. That might actually be the most likely outcome, as RHO not only is favourite to have diamond length but per hypothesis also has the ♦K. +1 Nice!I never said losing a ♣ means your line is losing, since you did not mention a line. You said try clubs first and play diamonds accordingly. And this reduces your chances by 17% excluding squeeze.I think the line you just suggested is the best so far when ♦K is on. Quote Link to comment Share on other sites More sharing options...
MrAce Posted October 1, 2016 Report Share Posted October 1, 2016 Lead to Q or J first, without cashing A. If E plays 9 or 10, run the remaining honor from S next. This has the possibility of picking up 7 4-1 club holdings -- any singleton but K in W, singleton K, 10, 9 in E. The success is reduced by an expert E who falsecards 10 or 9 from K109x, and from beginner E who plays the 9 or 10 to "force" the Q from S. How on earth are you planning to pick 3 ♣ tricks when E has stiff T or 9 ? Forget about false carding, assume you see their hands and make 3 ♣ tricks please when E has stiff 9 or T. KT8x-9K98x-T Quote Link to comment Share on other sites More sharing options...
Phil Posted October 1, 2016 Author Report Share Posted October 1, 2016 My partner played this and actually did start ♣Q, covered (but the JACK has to be a much better card). At the table, I thought, club to Ace, club back was best, but that clearly isn't the case. Quote Link to comment Share on other sites More sharing options...
zillahandp Posted October 1, 2016 Report Share Posted October 1, 2016 It seems to me Caitlynne is spot on, I do not see how leading the knave cane be right as it will be covered or lose, except. On bbo! So two spades fivehearts and two da and a club is still not enough. We needto play clubs for no losers , if we cannot then we need d finesse so play clubs first. Now its a standard play you all know if we lose one then we need d finesse Quote Link to comment Share on other sites More sharing options...
Phil Posted October 1, 2016 Author Report Share Posted October 1, 2016 It seems to me Caitlynne is spot on, I do not see how leading the knave cane be right as it will be covered or lose, except. On bbo! So two spades fivehearts and two da and a club is still not enough. We needto play clubs for no losers , if we cannot then we need d finesse so play clubs first. Now its a standard play you all know if we lose one then we need d finesse If LHO has ♣K9x it can be quite expensive to cover the J if partner has Qx. 1 Quote Link to comment Share on other sites More sharing options...
zillahandp Posted October 1, 2016 Report Share Posted October 1, 2016 Phil if! But if not? Quote Link to comment Share on other sites More sharing options...
Phil Posted October 1, 2016 Author Report Share Posted October 1, 2016 Phil if! But if not? If LHo does not cover, we are a tempo ahead. LHO probably does not have Kx, KT8 or KT98. We cross to a heart and hook a diamond. Our squeeze chances are much better too. You just aren't going to get any useful information if it starts ♣Q, K, A. Quote Link to comment Share on other sites More sharing options...
zillahandp Posted October 1, 2016 Report Share Posted October 1, 2016 No phil the only chance of four club tricks is a stiff king on your left then finesse against 10,9 on right, however unlikely then you do not need d finesse so small to Ac, and small to Q assuming it does not drop king on first round the we need two diamonds so chance is 50% plus a tiny bit for singleton k of clubs, if clubs split badly and we need three d tricks the you have to play for Kx on your right. Good luck in the Ryder cup. Quote Link to comment Share on other sites More sharing options...
zillahandp Posted October 1, 2016 Report Share Posted October 1, 2016 By the way losing a club will rectify the count whatever good that may do! Quote Link to comment Share on other sites More sharing options...
Fluffy Posted October 1, 2016 Report Share Posted October 1, 2016 No phil the only chance of four club tricks is a stiff king on your left then finesse against 10,9 on right, however unlikely then you do not need d finesse so small to Ac, and small to Q assuming it does not drop king on first round the we need two diamonds so chance is 50% plus a tiny bit for singleton k of clubs, if clubs split badly and we need three d tricks the you have to play for Kx on your right. Good luck in the Ryder cup. You might be looking at the wrong diagram. We are missing 10, 9 and 8 in clubs. Quote Link to comment Share on other sites More sharing options...
Phil Posted October 1, 2016 Author Report Share Posted October 1, 2016 Good luck in the Ryder cup. Thanks. Kooch played like a champ today and it's great to go into singles up 3. Quote Link to comment Share on other sites More sharing options...
Kaitlyn S Posted October 2, 2016 Report Share Posted October 2, 2016 No phil the only chance of four club tricks is a stiff king on your left then finesse against 10,9 on right, however unlikely then you do not need d finesse so small to Ac, and small to Q assuming it does not drop king on first round the we need two diamonds so chance is 50% plus a tiny bit for singleton k of clubs, if clubs split badly and we need three d tricks the you have to play for Kx on your right. Good luck in the Ryder cup.What am I missing? Even if we had the C8, we're saying 50% on a good club break and some small chance on a 4-1 break? That's like a total of 37% or so. (It might be slightly improved by playing West for 10x of diamonds if West has the four clubs.) My initial stab has to be better than 37%. When I led a diamond to the queen, I was making on 3-2 clubs, singleton king, plus when I got the extra heart entry (East didn't have four hearts) 4-1 clubs in East. That's close to 82% of the DK onside combinations, so that's 41% right there, which whoops that 37%. But I also made the hand sometimes when the DK was off - when West has the CK and diamonds were 3-3 or a club-diamond squeeze or a doubleton king of clubs I get to pick 2 out of three of these I think. I may be off but I think that's another 16% or so, putting me at about 57%. This might be enhanced a bit because when West covers the club, I get to include a doubleton D10 (I can cash my top D, if the 10 drops, cash the D9 and have my tricks. If the D10 doesn't drop, I cash the other diamond picking up 3-3 and still have my squeeze possibility.) Once you give up a club trick, you're never better than 50% (you need the diamond period) so it seems like those initial lines were better. What am I missing? Quote Link to comment Share on other sites More sharing options...
MrAce Posted October 2, 2016 Report Share Posted October 2, 2016 No phil the only chance of four club tricks is a stiff king on your left then finesse against 10,9 on right, however unlikely then you do not need d finesse so small to Ac, and small to Q assuming it does not drop king on first round the we need two diamonds so chance is 50% plus a tiny bit for singleton k of clubs, if clubs split badly and we need three d tricks the you have to play for Kx on your right. Good luck in the Ryder cup. Are you aware that you do not have ♣8? Quote Link to comment Share on other sites More sharing options...
Kaitlyn S Posted October 2, 2016 Report Share Posted October 2, 2016 7 User(s) are reading this topic 2 members, 5 guests, 0 anonymous users Five guests reading THIS topic? Seems like if they are still with us, they should be participants! 1 Quote Link to comment Share on other sites More sharing options...
MrAce Posted October 2, 2016 Report Share Posted October 2, 2016 Why not take the club finesse at trick 3 (after cashing the ♥A and seeing that both opps follow)? The point is: * If there are 4 diamond tricks available, taking the club finesse can never cost the contract.* If there are at most 3 diamond tricks available, we'll need to take the club finesse at some point anyway.* The number of diamond tricks we need depends on how the club suit behaves. (There are 4 possibilites to consider, in terms of who has the ♣K and whether clubs split (32).) I like things you say when ♦K is on but I am still not convinced in the points you try to make (highlighted bold) What is your line exactly? And how does playing clubs help you to play diamonds? As far as I know, you suggest to play ♣J/Q at trick 3 (after ♥A) (correct me if I am wrong) Assume that it is covered and you won with ♣A (or do you duck?) Do you play 2nd club to test clubs? If not test clubs how will this help you to decide how to play diamonds? If you test and find out 3-2 , you just created a club winner for W when he hold Kxx ♦, where starting ♦ to Q would, a very realistic line, makes easy 3♦+2♠+2♣+5♥=12 tricks. Looks like you go down when 3-2 clubs and 3-3 diamonds, everything friendly. No? Assume the ♣J/Q is not covered and held the trick, what next? Same position. You either test clubs and create 2nd trick for defense when W has ♦K and ♣K. Or you play diamonds without knowing how the club suit behaves. Quote Link to comment Share on other sites More sharing options...
Phil Posted October 2, 2016 Author Report Share Posted October 2, 2016 The number of diamond tricks we need depends on how the club suit behaves. (There are 4 possibilites to consider, in terms of who has the ♣K and whether clubs split (32).) Actually, I would say the opposite - the number of club tricks we need depends on what happens in the diamond suit. Quote Link to comment Share on other sites More sharing options...
nullve Posted October 2, 2016 Report Share Posted October 2, 2016 As far as I know, you suggest to play ♣J/Q at trick 3 (after ♥A) Yes. Assume that it is covered and you won with ♣A (or do you duck?) Do you play 2nd club to test clubs? If not test clubs how will this help you to decide how to play diamonds? If you test and find out 3-2 , you just created a club winner for W when he hold Kxx ♦, where starting ♦ to Q would, a very realistic line, makes easy 3♦+2♠+2♣+5♥=12 tricks. Looks like you go down when 3-2 clubs and 3-3 diamonds, everything friendly. No? Assume the ♣J/Q is not covered and held the trick, what next? Same position. You either test clubs and create 2nd trick for defense when W has ♦K and ♣K. Or you play diamonds without knowing how the club suit behaves.Ok, I realise it sounded like I wanted to find out everything about the club suit before playing on diamonds, but that wasn't the idea. Sorry. The idea was rather that even partial information about the club suit, e.g. about who has the K, might be useful when handling the diamond suit. For instance, suppose the ♣Q/J is not covered. Then it makes sense to switch to a "diamonds first" line of the kind that others have suggested, except that one's handling of the diamond suit might be influenced by whether RHO follows suit. And suppose the ♣Q/J is covered, which seems to be the critical variaton for my line. Then it might be relevant whether i) RHO shows out (indicating diamond length)ii) RHO follows suit with the 8,9 or T (Grosvenor from ♣T98x, so suggesting a (32) or 41 club break and therefore diamond length with RHO rather than with LHO).iii) RHO follows suit with the only spot below the 8 (not revealing much about how clubs break, except that RHO might have chosen to Grosvenor with T98x) I'm not sure what's best in each case (and I must admit I haven't thought much about it), but I can think of two natural sublines: 1) [cases i) and ii) primarily] Play the ♦J from dummy at trick 4, both with a view to finessing diamonds twice and as a smothering play against LHO, since RHO is the opp most likely to have diamond length. But if RHO covers and the 8 or T doesn't appear from LHO, it might be best to duck a club at trick 5 in ii) or iii). 2) [cases ii) and iii only] Play a diamond towards the Q, intending to duck a club if it holds the trick. Then if clubs are (32), I'm home. If clubs are 14, East will again be squeezed in the minor suits provided he also has the ♦K (seems likely). Quote Link to comment Share on other sites More sharing options...
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