plum_tree Posted December 1, 2015 Report Share Posted December 1, 2015 Can someone provide a link to the movement for a Rotating-Team-of-Four tournament for 4 tables? This is for a fun tournament at our local club. Instead of playing an Individual Tournament, the idea is to play with your regular partner the whole time, but during the course of the tournament, every other partnership will be your teammates once and your opponents once. With 4 tables it is 8 pairs, and say, 6 boards against every pair, would equate to 42 boards to complete the tournament. Any help will be appreciated. Quote Link to comment Share on other sites More sharing options...
gordontd Posted December 1, 2015 Report Share Posted December 1, 2015 I haven't come across such a thing but I imagine it would work to play a barometer Howell movement (two sets of boards would be best, but they needn't be duplicated if you don't have the facilities for that) and nominate tables 1 & 3 to be playing a match at any one time and tables 2 & 4 correspondingly. 1 Quote Link to comment Share on other sites More sharing options...
RMB1 Posted December 1, 2015 Report Share Posted December 1, 2015 I haven't come across such a thing but I imagine it would work to play a barometer Howell movement (two sets of boards would be best, but they needn't be duplicated if you don't have the facilities for that) and nominate tables 1 & 3 to be playing a match at any one time and tables 2 & 4 correspondingly.I thought that would work, but the 4-table "Flower" Howell movement (below) does not do what we want. There is no round where 1 and 2 are NS/EW at tables 1/3 or 2/4. 8v1 2v7 3v6 5v48v2 3v1 4v7 6v58v3 4v2 5v1 7v68v4 5v3 6v2 1v78v5 6v4 7v3 2v18v6 7v5 1v4 3v28v7 1v6 2v5 4v3 Quote Link to comment Share on other sites More sharing options...
gordontd Posted December 2, 2015 Report Share Posted December 2, 2015 I've found a different 4-table Howell movement that looks to me as though it would work, whether you have tables 1 & 2 playing the same match or 1 & 3: 8 v 1 ... 5 v 6 ... 2 v 4 ... 3 v 78 v 2 ... 6 v 7 ... 3 v 5 ... 4 v 18 v 3 ... 7 v 1 ... 4 v 6 ... 5 v 28 v 4 ... 1 v 2 ... 5 v 7 ... 6 v 38 v 5 ... 2 v 3 ... 6 v 1 ... 7 v 48 v 6 ... 3 v 4 ... 7 v 2 ... 1 v 58 v 7 ... 4 v 5 ... 1 v 3 ... 2 v 6 It looks like the important thing is that the switch table should be at some point other than between pairs T/2 & T/2 + 1 Quote Link to comment Share on other sites More sharing options...
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