luke warm Posted March 19, 2005 Report Share Posted March 19, 2005 Will responder always return to 2♥ with 5♥? If so, playing 2♥ with Jxxxx opposite xx is no fun; but if not you would miss the 5-3 fit unless opener raises. Eric not always, no... when it seems right, yes... judgement call... the point is, you can play in 4/3 or 5/3 by raising (unless responder has 6, in which case he'll bid 2H himself) or 1nt by not raising... some think it's more important to show shape first (ie, deny 4 card or *good* 3 support), regardless of distribution... some don't Quote Link to comment Share on other sites More sharing options...
Fluffy Posted March 21, 2005 Report Share Posted March 21, 2005 Playing walsh 1♣-1♥-1♠ may still be balanced. 1NT is for sure a good contract. Quote Link to comment Share on other sites More sharing options...
pclayton Posted March 21, 2005 Report Share Posted March 21, 2005 1S does not promise an unbalanced hand. But in my partnerships it carries the same level of force as a reverse.Not standard, I know. With this agreement, my biggest worry is that part holds a semi balanced 18-19 that spins 3N. Sometimes we will rebid 1S on a bare 4333 19 or a thin 18 like AQxx xx AQx AQxx. The original post explictly noted that 1♠ is non-forcingPartner doesn't have a balanced 18-19 count. The original post said 1♠ was non-forcing. It didn't deny a balanced 18-19. Opposite a mangy 5 or 6 count with 3 spades, 1♠ can be a very attractive spot. Quote Link to comment Share on other sites More sharing options...
hutchau Posted March 23, 2005 Report Share Posted March 23, 2005 This is a very basic question. As I like to play [1] The 1S bid confirms an unbalanced [or semi balanced with values in 2 suits] hand with 4+ clubs & 4+ spades....usually 5+ clubs[2] with a balanced hand & quite a few semibalanced hands with 4 spades I bid 1NT & use a checkback of some sort over this 1NT.There seem to be 2 possible bids[1]1NT[2]Pass or 2S. It would help to know the strength required to bid 2S rather than 1Sas used by the partnership.If 17+ then PASS is correct , otherwise 2S.If undiscussed I will take my chances with 2S as lots of GOOD things may happen and at worst we will be 1 down.I do not shy away from playing a moysian as many do at BBO Quote Link to comment Share on other sites More sharing options...
TimG Posted March 23, 2005 Report Share Posted March 23, 2005 Bidding goes (partner starts, opps are quiet): 1♣ - 1♥1♠ - ?You hold: Dealer: North Vul: E/W Scoring: MP ♠ QTx ♥ JT9xx ♦ A87x ♣ x What do you bid? Is this a companion hand to: ♠J1086♥K106♦8♣AKJ106 from another thread? I guess it can't quite be. Quote Link to comment Share on other sites More sharing options...
TimG Posted March 23, 2005 Report Share Posted March 23, 2005 The original post explictly noted that 1♠ is non-forcingPartner doesn't have a balanced 18-19 count. How does the non-forcing nature of 1♠ preclude the possibility of 18-19 balanced? Quote Link to comment Share on other sites More sharing options...
Free Posted March 23, 2005 Author Report Share Posted March 23, 2005 Bidding goes (partner starts, opps are quiet): 1♣ - 1♥1♠ - ?You hold: <!-- ONEHAND begin --><table border='1'> <tr> <td> <table> <tr> <td> Dealer: </td> <td> North </td> </tr> <tr> <td> Vul: </td> <td> E/W </td> </tr> <tr> <td> Scoring: </td> <td> MP </td> </tr> </table> </td> <td> <table> <tr> <th> <span class='spades'> ♠ </span> </th> <td> QTx </td> </tr> <tr> <th> <span class='hearts'> ♥ </span> </th> <td> JT9xx </td> </tr> <tr> <th> <span class='diamonds'> ♦ </span> </th> <td> A87x </td> </tr> <tr> <th> <span class='clubs'> ♣ </span> </th> <td> x </td> </tr> </table> </td> <td> </td> </tr> </table><!-- ONEHAND end --> What do you bid? Is this a companion hand to: ♠J1086♥K106♦8♣AKJ106 from another thread? I guess it can't quite be. No, as I said, he had a 4-3-2-4, no 4-3-1-5. Btw, it's a hand played f2f and probably nobody reads this forum except me... Quote Link to comment Share on other sites More sharing options...
Free Posted March 23, 2005 Author Report Share Posted March 23, 2005 The original post explictly noted that 1♠ is non-forcingPartner doesn't have a balanced 18-19 count. How does the non-forcing nature of 1♠ preclude the possibility of 18-19 balanced? I think with 18-19 they'll bid 2NT and find a ♠ fit using checkback stayman... Quote Link to comment Share on other sites More sharing options...
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