lucy_shb03 Posted January 11, 2015 Report Share Posted January 11, 2015 [hv=pc=n&s=saqth932dkq982ct6&e=s542hq6da3cak9753&d=w&v=n&b=12&a=p1h2cdp2hp3hppp]266|200[/hv]击垮3♥定约如何首攻与计算？ Quote Link to comment Share on other sites More sharing options...
dvd Posted January 11, 2015 Report Share Posted January 11, 2015 攻CA，如果同伴给双张信号，最好的机会就是同伴有hK或者hJ10，能吃到c3d1h1； 如果同伴居然有3张c，只好换攻s，希望h上面还能吃到一墩。 Quote Link to comment Share on other sites More sharing options...
lucy_shb03 Posted January 13, 2015 Author Report Share Posted January 13, 2015 攻CA，如果同伴给双张信号，最好的机会就是同伴有hK或者hJ10，能吃到c3d1h1； 如果同伴居然有3张c，只好换攻s，希望h上面还能吃到一墩。嗯，首攻与计算路子对头。1.首攻♣K,同伴掉下♣J，♣J是单还是双张大小信号呢？若是双张则庄家♣有3张；2.继续♣A，同伴垫边花，庄家原来持有♣QXXX;计算到此，后面的预期如同你的寄望，欲击败定约同伴王牌需有超吃南家王牌的能力，所以3.续攻最小的♣，同伴第一次H10超吃南家；4.同伴放♦回手到首攻方；5.再攻♣，同伴HJ第二次超吃明手，3H定约-1。 Quote Link to comment Share on other sites More sharing options...
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