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Highest combined HCP that can't make any slam?


AyunuS

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http://tinyurl.com/m9awxnq

 

Just played this hand where my team had a combined 34 HCP, and yet there's no way to play this in order to make any slam. Has anyone ever been stuck where there was no way to make a slam with more? In theory, it's possible to not be able to make any slam with 40 HCP, if everyone has a ridiculous 2-suited hand. I mean more like normal-shaped hands like these are. So maybe what's the most where the offense has entries to both of its hands and the defense doesn't ruff?

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http://tinyurl.com/m9awxnq

 

Just played this hand where my team had a combined 34 HCP, and yet there's no way to play this in order to make any slam. Has anyone ever been stuck where there was no way to make a slam with more? In theory, it's possible to not be able to make any slam with 40 HCP, if everyone has a ridiculous 2-suited hand. I mean more like normal-shaped hands like these are. So maybe what's the most where the offense has entries to both of its hands and the defense doesn't ruff?

 

I guess for balanced you could make a QJ9x behind to score 2 tricks or simply QJ109, even 2* J109x would be possible on mirror hand. But I haven't seen any 34 HCP hand yet. Only one 33 HCP with AK missing.

 

EDIT, it looks like nobody reads my posts, so I will add a diagram (rolls eyes)

 

[hv=pc=n&s=sakq2h6432dakjckq&w=sjt98hjd7543c7532&n=s6543hakq5dqt9caj&e=s7ht987d862ct9864]399|300[/hv]

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what's the most HCP where the offense has entries to both of its hands and the defense doesn't ruff?
[hv=pc=n&s=sa876haqtdaqtcaqt&w=sqjt9h876d876c876&n=sk543hkj9dkj9ckj9&e=s2h5432d5432c5432]399|300|

To get the ball rolling:

37 HCP[/hv]

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That give me an idea. It could just be an offsides QT.

 

North:

AKQ

J109

AK

AKJ32

 

East:

87

654

8765

Q1098

 

South:

J109

AKQ

QJ

7654

 

West: Whatever garbage is left lol. Does that work for getting it up to 38 HCP? Or can it be forced into an endplay?

If you give South a 13th card, say a , and you give NS appropriate entries (as above), then the defender will succumb to a "shape-shifter" squeeze-strip. Here, AK, AKQ, AKQ, squeeze RHO out of a , then Q strips him for the end-play.

 

But if NS lack sufficient entries, then this would work.

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Oh oops lol didn't realize south only had 12 cards. Any 13th will either mean N/S have too much length in the 4th suit for east to have enough cards to stop it, or just a 12th top trick. So it doesn't work. New idea. 2 offsides jacks?

 

North:

AKQ10

AK

J109

5432

 

East:

J543

109872

876

8

 

South:

9876

QJ

AKQ

AKQ10

 

West:

2

6543

5432

J632

 

Edit: Fixed, I think

Edited by AyunuS
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[hv=pc=n&s=sakqthT987daqtcaq&w=sj543h5d8765cT987&n=s8765hakq6dkj9ckj&e=s22hJ432d432c65432&d=s&a=6nppp]399|300|

AyunuS wrote:

 

"New idea. 2 offsides jacks?"

 

Oh!. I see that Fluffy has now posted a similar hand diagram.

 

38 HCP.! Brilliant, both of you! :)

 

[/hv] [hv=pc=n&s=sjt98hjt9d7654caq&w=s76hj8765dct98765&n=sakqhakqdakj98ckj&e=s5432h32dqt32c432&d=s&a=6nppp]399|300|

This is a variant of AyunuS's previous hand, modified so that the only communication is in --- and only a lead defeats 6N -- by attacking that communication! :)

38 HCP but slightly marred by West's void :( [/hv]

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A better question is without extreme breaks. What is the most HCP where you can can't make slam.

 

[hv=pc=n&s=sakqhakqd542cakq5&n=sjt9hjt9dakq3c432]133|200[/hv]

 

Just give East-West a normal 4-2 breaks in minors and no contract has any chance.

You have 12 top tricks in this diagram. :blink:

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