mgoetze Posted September 7, 2014 Report Share Posted September 7, 2014 [hv=d=n&v=0&b=1&a=1c1sd1nd]133|100[/hv]In case it matters, our 1♣ includes all 11-13 and 17-19 balanced hands. What's double? Quote Link to comment Share on other sites More sharing options...
Cyberyeti Posted September 7, 2014 Report Share Posted September 7, 2014 Penalties, very likely a balanced 17 often with 4 spades and not 4 hearts, also could be 5♣/4♠ and a 16 count 2 Quote Link to comment Share on other sites More sharing options...
SteveMoe Posted September 7, 2014 Report Share Posted September 7, 2014 Three options come to mind - 1) 17-19 Balanced,2) Takeout of ♠3) Any hand with 3♥ cards that wants to compete. I like 1). Quote Link to comment Share on other sites More sharing options...
mgoetze Posted September 7, 2014 Author Report Share Posted September 7, 2014 Three options come to mind - 1) 17-19 Balanced,2) Takeout of ♠3) Any hand with 3♥ cards that wants to compete. I like 1).1) is kind of what I assumed first, but then I thought about it and ... isn't 3) a lot more common? Quote Link to comment Share on other sites More sharing options...
mgoetze Posted September 8, 2014 Author Report Share Posted September 8, 2014 I mean, say East has 10 points, South has 6 and West has 8. Complicated mathematical deduction will lead to the conclusion that North does not have 17-19. Even if everyone is subminimum or bluffing, we might have 17-19, but then we might still have 3 or 4 hearts. Quote Link to comment Share on other sites More sharing options...
MrAce Posted September 8, 2014 Report Share Posted September 8, 2014 Penalty. He is on lead, he may hold the hands you guys already mentioned as well as he may have doubled with running clubs. Keep in mind most people bid 1 NT without caring much about stoppers in opener's minor. But even if he has a stopper pd may have the rest + sure entries. Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted September 8, 2014 Report Share Posted September 8, 2014 You could compromise and play it as support + extras. That would make it easier for partner to convert it when it is right. 1 Quote Link to comment Share on other sites More sharing options...
kgr Posted September 8, 2014 Report Share Posted September 8, 2014 1C-(P)-1H-(1NT)Here we have in our system that DBL is support. The given auction is undefined, but I would also assume support. Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted September 8, 2014 Report Share Posted September 8, 2014 1C-(P)-1H-(1NT)Here we have in our system that DBL is support. The given auction is undefined, but I would also assume support.Do you have the auction 1♣ - (1♥) - X - (1NT); X in your file? Quote Link to comment Share on other sites More sharing options...
kgr Posted September 8, 2014 Report Share Posted September 8, 2014 Do you have the auction 1♣ - (1♥) - X - (1NT); X in your file?Only that when 4th hand over calls a natural 1NT then DBL is support. System doesn't contain anything about 2nd hand also did bid in this case. But I assume it is still support. Note: if 1NT is 2-suiter then DBL is penalty oriented.Edit: verified with partner. He agrees it is still support. Quote Link to comment Share on other sites More sharing options...
SteveMoe Posted September 12, 2014 Report Share Posted September 12, 2014 1) is kind of what I assumed first, but then I thought about it and ... isn't 3) a lot more common? Yep. This auction causes 2 metas to collide - opener's double as 17 -19 and as support. Perhaps the then the default should be higher frequency occasions (support).With no agreement I suspect 1) is "safer" - more likely to be on partner's mind and more likely to win a post mortem. :rolleyes: Quote Link to comment Share on other sites More sharing options...
Trinidad Posted September 12, 2014 Report Share Posted September 12, 2014 Do you have the auction 1♣ - (1♥) - X - (1NT); X in your file?There is a big difference between 1♣-1♥-Dbl and 1♣-1♠-Dbl. On the first auction responder will have exactly four spades, on the second responder will have 4 or more hearts. That means that 1♣-1♠-Dbl-1NT-Dbl should be support since responder can easily have 5 or more hearts. The interesting question is what 1♣-1♥-Dbl-1NT-Dbl would mean. I would say that it is a hand that doesn't want to sell out to 2♥: close to a 3145 pattern and not ashamed of having opened. Rik Quote Link to comment Share on other sites More sharing options...
helene_t Posted September 12, 2014 Report Share Posted September 12, 2014 With 3145 I think you can pass (or bid 2cl with good clubs) and then bid 2s in the rebound. 2245 is more difficult but maybe 2d is weakish because a real reverse would have doubled. I think playing this double as t/o caters to a narrow set of hands so I prefer penalty. Quote Link to comment Share on other sites More sharing options...
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