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How do you reach the laydown grand?


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Basic system is 2/1:

[hv=pc=n&s=sa764hadkqj9ckj95&w=sq532hkt742d74c73&n=s8hq8da8632caq864&e=skjt9hj9653dt5ct2&d=s&v=0&b=11&a=1dp2c(Game%20force)p3c(Club%20fit)p3d(Double%20fit)p4d(6-card%20RKCB)p5c(2%20with%20lower%20queen)p]399|300[/hv]

What now? South has 3 losers to get rid of. How must the bidding continue now to find the grand? North's bidding has shown 5 clubs and 4 diamonds. That leaves 4-cards in the majors, 2 are taken care of by South's two aces. What about the other two?

 

 

given your auction...if south can now show KC and all keycards...north can jump to 7.

 

Also with extra length north might show that or QD IN RESPONSE TO KEY CARD ASK.

 

north MIGHT start with 3s or 2c...I kinda like 3s but 2c is fine.

After 3s south can start cuebidding stuff.

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  • 2 weeks later...
  • 4 weeks later...

Answer to the title question - does not assume 2/1

 

1 precision 16+, not 4441 and 16-23 (Oliver Clarke variation)

2 8+ and 5+ clubs

2 - control ask for aces and kings

2NT - 4 controls A=2, K=1

3 agrees trump and asks about club support (at this point p has AA or AKK)

3 2 of 3 top honors and exactly 5 clubs (p known to be AQxxx)

4 control asking bid in diamonds

5 1st and 3rd round control Ax, AQ(x)(x)(x) - this clarifies controls to A in each minor suit

5 control ask in spades with just barely enough room - responses of 5N= no control or 1st and 2nd, 6C = xx or Qxx, 6D = 2nd round control

5 - 2nd round control

7 - since Kx(x) has already been eliminated partner has singleton spade

 

Can count 1 spade, and 3 spade ruffs, 1 heart, 4 diamonds, 4 natural club tricks.

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  • 3 weeks later...

Basic system is 2/1:

[hv=pc=n&s=sa764hadkqj9ckj95&w=sq532hkt742d74c73&n=s8hq8da8632caq864&e=skjt9hj9653dt5ct2&d=s&v=0&b=11&a=1dp2c(Game%20force)p3c(Club%20fit)p3d(Double%20fit)p4d(6-card%20RKCB)p5c(2%20with%20lower%20queen)p]399|300[/hv]

What now? South has 3 losers to get rid of. How must the bidding continue now to find the grand? North's bidding has shown 5 clubs and 4 diamonds. That leaves 4-cards in the majors, 2 are taken care of by South's two aces. What about the other two?

South knows North has a GF with 54 in the minors and he knows 10HCP.

North cant have any add. HCP in the minors, since all 20HCP in the

minors are acoounted for.

=> Would North really make a GF with 5422 and no major suit control?

The worst you could have maybe Qx in both majors, but maybe North would

have suggested NT on the road?

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