Kungsgeten Posted February 17, 2014 Report Share Posted February 17, 2014 I've been thinking about using transfers if the opponents double or overcall 1H over our natural unbalanced diamond opening. I've thought about some structures and was wondering what you guys are playing (or have thought of playing). In particular the sequence 1D-(1H)-2H is interesting, since we can make a direct raise or a transfer raise to diamonds and use 1S as balanced. 1D--(1H)---Dbl = 4+ spades1S = 0-3 spades, usually balanced1N = Transfer to clubs. We play this as weak or GF uncontested, perhaps it should be here too?2C = Transfer raise. We play his as weak or GF uncontested.2D = Direct raise. We play this as INV uncontested.2H = ???2S = Weak2N = Natural INV?3C = We play this as natural INV uncontested.3D = Preemptive raise3H = Splinter, or perhaps a transfer to 3NT?3S = Fit show4C = Fit show Over our Swedish club (11--13 bal or 17+) we play 1C--(1H)--2H as a GF stopper ask. Does this make sense here too? Quote Link to comment Share on other sites More sharing options...
Finch Posted February 17, 2014 Report Share Posted February 17, 2014 I like 2H to show 6 or more spades and some agreed range. That takes some of the strain off the double. After, say, 1D 1H dbl 4H P P you are guessing a bit when you have a game force with long spades, after 1D 1H 2H 4H P P you can double happily. Quote Link to comment Share on other sites More sharing options...
paulg Posted February 17, 2014 Report Share Posted February 17, 2014 We play the Garozzo method where the cue bid shows 5-5 in the unbid suits, with invitational or better values. I doubt it has the frequency of Frances' method, but it is useful when it does come up. Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted February 17, 2014 Report Share Posted February 17, 2014 X = 4+ spades1♠ = clubs or balanced without stop1NT = nat2♣ = raise2♦ = raise2♥ = 6+ spades, weak or GF2♠ = fit jump I looked up Ben's Equality and he plays: X = spades1♠ = Clubs, or balanced misfit1NT = Natural, non-forcing2♣ = 4+ spades, relatively balanced2♦ = 5+ spades, forcing2♥ = Diamond fit, invite (not GF, see 2NT)2♠ = Fit jump, NF2NT = Weak or game forcing raise3♣♠ = Fit jump, NF3♦ = Weak (but not desperately weak)3♥ = Looks for 3NT with stopper Using the 2♣ response to take additional load off the double looks an interesting idea. I think a compromise between the 2 schemes where one of 2♣/2♦ shows a raise and the other shows spades might be better than both of these. Perhaps 2♣ as a diamond raise (of all strengths) and 2♦ to show 5+ spades, INV+? That is: X = 4+ spades1♠ = clubs or balanced without stop1NT = nat2♣ = raise2♦ = 5 spades, GF; or 5+ spades, invite2♥ = 6+ spades, weak or GF2♠ = fit jump Quote Link to comment Share on other sites More sharing options...
phoenix214 Posted February 17, 2014 Report Share Posted February 17, 2014 Well you can try the Canadian version which was in Nightmare:X-4 or 5 ♠1♠- 0-3 spades1NT-NAT2♣, NF2♦, NF2♥, 6+♠ - 8+HCP(wants to be in game opposite good hand with support)2♠, 6+ 0-72NT+ Up to youI tried playing this over the precision diamond. Although now we might find a better structure playing precision with an unbalanced diamond, where 1♦ is similar to yours, and at the moment we play X=4, and 1♠=5+, but i suppose i could try to market my partner one of these methods(Muhahaha)Today showed him Equality. About 2♥ overall, i think it should be used a forcing hand with a spade-onesuiter, as mentioned above Quote Link to comment Share on other sites More sharing options...
gnasher Posted February 17, 2014 Report Share Posted February 17, 2014 I like2♥ = 6 spades any strength, or 5 spades game-forcing2♠ = exactly 5 spades with a reasonable suit, exactly invitational This means that in a sequence like1♣ 1♥ dbl 5♥pass pass dblresponder will usually have only four spades. Quote Link to comment Share on other sites More sharing options...
Free Posted February 17, 2014 Report Share Posted February 17, 2014 I use it as 6+♠ weak or GF (and 2♠ shows the intermediate hand). This relieves some tension of the Dbl (now showing 4-5♠). Remark: this is in a precision framework, where ♦s aren't natural and opener is limited. Quote Link to comment Share on other sites More sharing options...
kgr Posted February 17, 2014 Report Share Posted February 17, 2014 1D-(1H)-?DBL=4+cS1S=0-3cS1NT=Natural, stop2C=Nat, 1RF2D=6cS, weak or GF2H=D-fit, inv+2S=5cS, 4cD, weak2NT=4+cD, very weak3C=6cC, invite3D=4cD, 6-93H=splinter3S=6cS, invite Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.