lycier Posted January 23, 2014 Report Share Posted January 23, 2014 [hv=d=n&v=0&b=1&a=1cp1dp1hp2hp]133|100[/hv] 前置条件是：Walsh应叫原则+XYZ问题：你觉得2♥确切的含义是什么？为什么？注意回答问题前别忘记投票。 Quote Link to comment Share on other sites More sharing options...
shisun Posted January 23, 2014 Report Share Posted January 23, 2014 N 1H 说明是非均的牌h4+，牌点最高17-（如果是低限的均型，会应1nt）S 2H 也许是非均的牌型5d4c3h1s，弱牌，不适合1nt（因为1h是逼叫，1nt牌型不适合，如果是邀请和逼局用xyz） 所以我选择建设性加叫。3张h Quote Link to comment Share on other sites More sharing options...
wuhuan Posted January 24, 2014 Report Share Posted January 24, 2014 Walsh应叫原则+XYZ——这个前置条件，让我很纠结。walsh弱牌6+p4张套应该先应叫1H，先1D后在加H肯定D5张以上、4张H不是弱牌；xyz邀叫要经过2C，逼局要经过2D，咳——真难了。xyz我投弱牌，walsh我投邀叫，两者相加？ Quote Link to comment Share on other sites More sharing options...
shisun Posted June 27, 2014 Report Share Posted June 27, 2014 看了qlpsecond的帖子后。查找顶一下 Quote Link to comment Share on other sites More sharing options...
lycier Posted June 30, 2014 Author Report Share Posted June 30, 2014 我以为这是建设性4张加叫，而缺乏邀请实力。这似乎合乎常理。 Quote Link to comment Share on other sites More sharing options...
sfbcs Posted July 4, 2014 Report Share Posted July 4, 2014 不逼局有4张高花总是先1M。所以是逼局4+H。 Quote Link to comment Share on other sites More sharing options...
lycier Posted July 5, 2014 Author Report Share Posted July 5, 2014 delete Quote Link to comment Share on other sites More sharing options...
chinalxm Posted September 11, 2014 Report Share Posted September 11, 2014 我以为这是建设性4张加叫，而缺乏邀请实力。这似乎合乎常理。因为你用walsh+xyz，不够逼局实力，有4个H会先叫h，所以应该是3个好的h建设性加叫 Quote Link to comment Share on other sites More sharing options...
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