nnzxb Posted August 5, 2013 Report Share Posted August 5, 2013 [hv=sn=A&s=SKQ65H4DAQT984CQ6&nn=B&n=SAT2HAKT2DCAKJ954&d=n&v=e&b=25&a=PPPP/]499|350[/hv]北开叫1C-1D2H Quote Link to comment Share on other sites More sharing options...
IVAN CY LO Posted August 5, 2013 Report Share Posted August 5, 2013 1C - 2D2H - 2S3C - 3D4NT - 5C(14/03)6C - 7C 此牌要叫上大滿貫,個人認為是應叫方的感覺。在缺CQ 的情況下開叫方自願叫上6C,則應叫方應感覺出該叫7C。除此之外,我想不出在自然體制內有何辦法。 Quote Link to comment Share on other sites More sharing options...
HeartA Posted August 5, 2013 Report Share Posted August 5, 2013 1♣ - 1♦2♥ - 2♠ (2♠第四花色,可以是第二套。开叫者如果有4张支持,可以加叫,比如5-4-4-0,或者4-4-4-1)3♣ - 4♣ (3♣: 6张半坚固套;4♣:罗马关键张问叫)4♦ - 5♦ (如果是0314,开叫者答4♥。5♦问K)5♥ - 7♣ 应叫者可以数出13墩:6墩♣+1墩♥将吃+3墩♠+2墩♥+♦A Quote Link to comment Share on other sites More sharing options...
haikuo Posted August 12, 2013 Report Share Posted August 12, 2013 同意Posted 2013-August-05, 13:441♣ - 1♦2♥ - 2♠ (2♠第四花色,可以是第二套。开叫者如果有4张支持,可以加叫,比如5-4-4-0,或者4-4-4-1)3♣ - 4♣ (3♣: 6张半坚固套;4♣:罗马关键张问叫)4♦ - 5♦ (如果是0314,开叫者答4♥。5♦问K)5♥ - 7♣ 应叫者可以数出13墩:6墩♣+1墩♥将吃+3墩♠+2墩♥+♦A Quote Link to comment Share on other sites More sharing options...
601821297 Posted August 13, 2013 Report Share Posted August 13, 2013 [hv=d=n&v=e&b=9&a=1cp1dp2hp2sp3cp3dp3sp4cp4dp4sp5hp7cppp]233|200[/hv]注:4C为低花黒木4D为1/4关键张4S此时是一闲置叫品,为节约空间,因此这里用4S问边花K通过叫牌应叫方可以知道搭档是3406牌型而且拥有SA/HAK/CAK,此时13墩已经到手叫出7C Quote Link to comment Share on other sites More sharing options...
HeartA Posted August 13, 2013 Report Share Posted August 13, 2013 [hv=d=n&v=e&b=9&a=1cp1dp2hp2sp3cp3dp3sp4cp4dp4sp5hp7cppp]233|200[/hv]注:4C为低花黒木4D为1/4关键张4S此时是一闲置叫品,为节约空间,因此这里用4S问边花K通过叫牌应叫方可以知道搭档是3406牌型而且拥有SA/HAK/CAK,此时13墩已经到手叫出7C这个序列有两个问题。1)等到同伴叫了3门花色,再叫4C,还是罗马关键张问叫吗?2)4S是问边花K吗?不能为了“节省空间”而临时弄出来一个叫品。4S应该是扣叫(4H是问Q)。 Quote Link to comment Share on other sites More sharing options...
lycier Posted August 13, 2013 Report Share Posted August 13, 2013 低花木后的扣叫4♠是此轮控制,即4♠K扣叫,继续探查满贯的最佳落脚点:即6♣,6nt,7♣,还是7nt。复杂多变。 Quote Link to comment Share on other sites More sharing options...
601821297 Posted August 14, 2013 Report Share Posted August 14, 2013 这个序列有两个问题。1)等到同伴叫了3门花色,再叫4C,还是罗马关键张问叫吗?2)4S是问边花K吗?不能为了节省空间而临时弄出来一个叫品。4S应该是扣叫(4H是问Q)。1) 这个4C是3次低花木;2)用4S问是曾经和一朋友交流时他提出的观点,我感觉有一定道理所以在这里这样建议了,如果不用4S问那就换5D问吧,结果也是一样的 :) Quote Link to comment Share on other sites More sharing options...
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