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Transfers after 1D-X


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i'm sure ive seen system of transfers over takeout double of 1N here. Ive tried searching but u cant search on 1D(too small) so didn't have any luck

 

transfers over 1 double make a lot of sense and is easy to come up with a system that is nice

 

1 double a little more difficult. I think your gonna lose natural redouble. Anyone got a method?

 

if it makes a difference 1 is unbalanced

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I never developed a fully fleshed out system over 1-X, but having worked hard on the 1M-X version, the "lost" XX hands pass and then double. If 3 hands have near opening values (in the case of a normal XX responder), you can bet 4th hand isn't sitting for the X and is taking it out to some cheap suit since they're nearly broke. So you've essentially got a situation where the opps are in a forcing auction, so you can safely pass and plan on bidding again later. This opens up a lot of options, systems-wise, for how to treat strongish hands by repsonder.
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We play an entire level of transfers, starting with the RDbl. The loss of the natural RDbl isn't that big imo, and there are other ways to penalize opps.

 

So:

RDbl = 4+

1 = 4+

1 = transfer to NT

1NT = transfer , pretty much any strength

2 = good raise

2 = weak raise

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While over 1 (X) I play transfers with a 4+ card suit (twalsh "on"), after 1 (X) transfer (pass), how do you play? Jump completion with 4, completion with 2+, or what?

In general I think you should follow the same style that you play over 1-(X)-transfer.

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After 1-(P)-? => We play T-Walsh.

 

Playing T-Walsh it is easy to play a similar system after:

1x-(1D/H)-?

(with DBL is transfer to 1 over 1).

 

or after:

1C/D/H-(DBL)-

(with RDBL is transfer to 1 over 1).

 

=> I would recommend these transfers when playing T-walsh.

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Playing T-Walsh it is easy to play a similar system after:

1x-(1D/H)-?

(with RDBL is transfer to 1 over 1).

Its my understanding that under ACBL GCC conventional meanings may be given to redoubles and responses

(including free bids)

 

so you can use 1= and 1= etc. as these are free bids

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After 1-(P)-? => We play T-Walsh.

 

Playing T-Walsh it is easy to play a similar system after:

1x-(1D/H)-?

(with RDBL DBL is transfer to 1 over 1).

Its my understanding that under ACBL GCC conventional meanings may be given to redoubles and responses

(including free bids)

 

so you can use 1= and 1= etc. as these are free bids

I obviously did mean DBL iso RDBL

(and all other 1-level bids are transfer, with 1 transfer to 1NT)

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under ACBL GCC conventional meanings may be given to redoubles and responses

(including free bids) thereto

 

Assuming you are referring to "Competitive" section, item 2, you missed a word.

 

1 (1) 1= is not GCC-legal (unless 1 was strong and forcing, not the case under discussion here, or 1 was conventional, unlikely).

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Yeah, double is a cheat, because *everybody* plays double as conventional, so you get to make "any [non-purely-destructive] agreements" over it.

 

Woe betide you if you find the one pair in the country that plays penalty doubles. Having said that, I might try that one day just for the director calls :-)

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