cargobeep Posted July 5, 2013 Report Share Posted July 5, 2013 On a random hand, what is the probability that you and your partner have an 8-card or greater fit in some suit? Quote Link to comment Share on other sites More sharing options...
ArtK78 Posted July 5, 2013 Report Share Posted July 5, 2013 I will leave this to others to calculate. But it seems to me that the basic problem is how many random assortments of 26 cards will have at least 8 in one suit? Obviously, the percentage will be quite high, as the only assortments of 26 cards that do not have at least 8 in one suit are 7-7-6-6 and 7-7-7-5 (in any order). Quote Link to comment Share on other sites More sharing options...
hrothgar Posted July 5, 2013 Report Share Posted July 5, 2013 I'm lazy, so I wrote a dealer script which estimates that the probability is approximately 15.73% seven = spades(north) + spades(south) <= 7 and hearts(north) + hearts(south) <= 7 and diamonds(north) + diamonds(south) <= 7 and clubs(north) + clubs(south) <= 7 action average seven Quote Link to comment Share on other sites More sharing options...
campboy Posted July 5, 2013 Report Share Posted July 5, 2013 Yes, about 15.736% that you don't. You may as well shuffle your hand with partner's as it makes no difference who has what. There are combin(13,7)=1716 different ways to have 7 spades. Likewise there are 1716 different ways to have 6 and 1287 ways to have 5. There are 6 different patterns for 7,7,6,6, and 4 patterns for 7,7,7,5. So the total number of ways is 6*1716^4+4*1287*1716^3. Then divide by combin(52,26) which is the number of possible sets of 26 cards the two of you can have. The chance that neither pair has an 8-card fit is about 10.49% 1 Quote Link to comment Share on other sites More sharing options...
nige1 Posted July 5, 2013 Report Share Posted July 5, 2013 # Trying to learn Dealer Script and confirming Hrothgar's result NStrumps = 8 EWtrumps = 8 NSfit = spades(north) + spades(south) >= NStrumps or hearts(north) + hearts(south) >= NStrumps or diamonds(north) + diamonds(south) >= NStrumps or clubs(north) + clubs(south) >= NStrumps EWfit = spades(east) + spades(west) >= EWtrumps or hearts(east) + hearts(west) >= EWtrumps or diamonds(east) + diamonds(west) >= EWtrumps or clubs(east) + clubs(west) >= EWtrumps action average NSfit, average EWfit, average NSfit and EWfit Yes About 84% of deals: you have have an 8+ fit.About 79% of deals: both sides have an 8+ fit.Test: changing NStrumps to nineAbout 38% of deals: you have have an 9+ fit.If you have a 9+ fit, then opponents have an 8+ fit. Quote Link to comment Share on other sites More sharing options...
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