lycier Posted May 24, 2013 Report Share Posted May 24, 2013 [hv=sn=Niemi&s=S85HKTD9743CAKQ95&wn=Jón Baldur&w=S74HQJ974DQTC8763&nn=Koistinen&n=SAK6HA53DAKJ862C2&en=Þorlákur J&e=SQJT932H862D5CJT4&d=e&v=b&b=10&a=P1DP2DP3CP4NP5DP5HP6DPPP&p=S4SASQS5DAD5D3DTDKS2D4DQ&c=13]499|350[/hv] 我们对他们采用的什么体系不感兴趣，我们的兴趣是：用我们自己的体系，如何叫上大满贯呢？ Quote Link to comment Share on other sites More sharing options...
chenxuemin Posted June 10, 2013 Report Share Posted June 10, 2013 1d 1h2c 2d2h 2s2nt 3c3d 3h3s 4c5c 7d 1d=虚叫1h=逼局/h套2c=9张以上低花2d=接力2h=4d5c2nt=11-12牌力3d=2245牌型3s=1个A5c=2个K（s+d/h+c) 海盗精确比mosicto精确多了个显示牌力的过程，这样就占了1级空间，有兴趣的可以深人研究 Quote Link to comment Share on other sites More sharing options...
bgm Posted June 10, 2013 Report Share Posted June 10, 2013 [hv=v=b&b=10&d=e&a=p1sp1np2cp2dp2hp2sp3cp3dp3np4cp4hp7nppp]400|300[/hv] 看到 Moscito 就試一試吧! 1♠ = 6+♦ or (54)+m's w/o 4M, 9-14 HCP1NT = INV+ Relay2♣ = (54)+m's w/o 4M2♦ = FG Relay2♥ = 5+♣, 4♦2♠ = Relay3♣ = 22453♦ = QP ask3NT = 8QP (base = 6; +3 = 8)4♣ = DCB w/ K parity4♥ = Even K, 0/3 ♣ Honors7NT = S/O Quote Link to comment Share on other sites More sharing options...
dvd Posted June 10, 2013 Report Share Posted June 10, 2013 选择开叫1c，后续叫到7应该问题不大。开1d后，多少有点问题。这样的牌强烈建议开1c。 Quote Link to comment Share on other sites More sharing options...
chenxuemin Posted June 10, 2013 Report Share Posted June 10, 2013 1c 2d2h 2s4d 4h4nt 5s7nt 2d=低花满贯兴趣（费尔德曼约定叫）2h=接力2s=6张以上d套（2nt=双套低花55以上）4d=rkcb4nt=?K(如果没有S-K，后续可以SSA，打7d) 这是标准的哈代2/1，注意2d的使用方法 Quote Link to comment Share on other sites More sharing options...
xuefeier Posted June 10, 2013 Report Share Posted June 10, 2013 chenxuemin 1c 2d2h 2s4d 4h4nt 5s7nt 2d=低花满贯兴趣（费尔德曼约定叫）2h=接力2s=6张以上d套（2nt=双套低花55以上）4d=rkcb4nt=?K(如果没有S-K，后续可以SSA，打7d) 这是标准的哈代2/1，注意2d的使用方法 老师如果不用这个约定叫，2D就是弱阻击了，还有2/1里面也用接力吗？ Quote Link to comment Share on other sites More sharing options...
chenxuemin Posted June 10, 2013 Report Share Posted June 10, 2013 1c 1d2d 4nt5c 5s6h 7nt 4nt=rkcb(d已经配合，只有4个失张）5s=?K(5d=pass,5h=?Q,5nt=问最低花色K)6h=3个（因为问K的目的就是要7，C-Q是绝对的大牌） SAYC一样可以叫到，要注意早期的RKCB比较简单 Quote Link to comment Share on other sites More sharing options...
xuefeier Posted June 11, 2013 Report Share Posted June 11, 2013 chenxuemin Group: Members Posts: 47 Joined: 2012-June-05 Posted Today, 08:30 1c 1d2d 4nt5c 5s6h 7nt 4nt=rkcb(d已经配合，只有4个失张）5s=?K(5d=pass,5h=?Q,5nt=问最低花色K)6h=3个（因为问K的目的就是要7，C-Q是绝对的大牌） 谢谢老师！明白了。 Quote Link to comment Share on other sites More sharing options...
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