JonnyQuest Posted May 4, 2013 Report Share Posted May 4, 2013 In the following sequence: 1♥ - 1♠1NT - 2♣2NT - 3♠ Assuming a Standard American or 2/1 system, using NMF. 1. 1NT = 12-14 2. 2NT = denies 3 card ♠ support (so presumably 2=5=3=3), and denies Max of 14 HCP What is 3♠? :blink: Quote Link to comment Share on other sites More sharing options...
Vampyr Posted May 4, 2013 Report Share Posted May 4, 2013 What is 3♠? :blink: Forcing with spades; quite possibly 6. Why do you choose to get to 2NT or higher when opener does not have a maximum? Quote Link to comment Share on other sites More sharing options...
aguahombre Posted May 4, 2013 Report Share Posted May 4, 2013 Responder didn't bid 2S, 3S, or 4S. He bid nmf, and then set trump anyway. That, by logic, is slammish. Reconsider 2NT not showing a max good 13 or 14. Quote Link to comment Share on other sites More sharing options...
Siegmund Posted May 4, 2013 Report Share Posted May 4, 2013 You have posited what I feel is an unusual meaning for 2NT - I would expect this call to promise a maximum, not deny one, as opener could have bid 2D or 2H and left the door open to stopping in 2S. Quote Link to comment Share on other sites More sharing options...
Codo Posted May 5, 2013 Report Share Posted May 5, 2013 slammish in spades of course. :) Quote Link to comment Share on other sites More sharing options...
TWO4BRIDGE Posted May 6, 2013 Report Share Posted May 6, 2013 You have posited what I feel is an unusual meaning for 2NT .... EDIT: I deleted my jibberish. I agree with the others, that Opener's 1NT rebid already denies 4 cards in either minor. Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted May 6, 2013 Report Share Posted May 6, 2013 A simple way of playing NMF is that going via the relay shows a hand stronger than the equivalent direct sequence. For bidding spade one-suiters after 1♥ - 1♠; 1NT, we have 2♠ to show a sign off, 3♠ for an invite and therefore bidding 2♣ followed by 3♠ must be game forcing, and in addition slam interest since we did not bid 4♠. As others have said, consider using 2♦ over 2♣ to show a minimum without 3 spades. Quote Link to comment Share on other sites More sharing options...
aguahombre Posted May 6, 2013 Report Share Posted May 6, 2013 As others have said, consider using 2♦ over 2♣ to show a minimum without 3 spades.Opener's distribution will be known at this point (2-5-3-3). So, we can actually use either 2D or 2H with the 11-12 point hands... 2D with a diamond stop, and 2H without for instance. Now responder can end the auction in 2H, 2S, or 2N based on positional considerations. Quote Link to comment Share on other sites More sharing options...
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