djehuti Posted May 3, 2013 Report Share Posted May 3, 2013 AT82K43For 3 tricks. a) K, finesse T, Ab) K, finesse 8, finesse T My math tells me that both lines are equal. However, from suitplay: SUITPLAY - needing 3 tricks: b) best (Gets 3 tricks more often on average) MP's a) best. IMPS 3NT White, No doubles a) b) same 3NT VUL, No doubles b) best 3NT White/VUL Doubled/Redoubled a) best What happens when either 9 or H appears on RHO on the 1st trick:a) finesse 8b) A I think i suspect why B is better but its just too complicated and i'm really not sure... maybe i'm missing something and the reason is simple? Quote Link to comment Share on other sites More sharing options...
Siegmund Posted May 3, 2013 Report Share Posted May 3, 2013 AT82K43For 3 tricks. a) K, finesse T, Ab) K, finesse 8, finesse T My math tells me that both lines are equal. However, from suitplay: They both work on the same number of combinations. A beats B 7 times (one 5-1 break, three 4-2s, three 3-3s) and B beatsA 7 times (six 4-2 breaks, one 3-3 break.) The 5-1 break is enough less frequent to give B a very very tiny edge. Quote Link to comment Share on other sites More sharing options...
Fluffy Posted May 3, 2013 Report Share Posted May 3, 2013 If you are playing towards the 8 for 4 tricks in MPs, suitplay will falsecard from QJ9 and H9 Quote Link to comment Share on other sites More sharing options...
djehuti Posted May 3, 2013 Author Report Share Posted May 3, 2013 Yeah i know, i was thinking that the falsecards, when declarer's intention is for the max, had influence on how many times 9x would appear. Line a) attemps the max, line b) doesn't. But Siegmund's reasoning seems right and simpler. Quote Link to comment Share on other sites More sharing options...
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