vitorlopes Posted April 9, 2013 Report Share Posted April 9, 2013 Playing normal Precision, with the following Match-Point bidding: Opener Hand: 5=3=1=4Responder Hand: 1=3=6=3 1♣-(P)-1♦-(P)1♠-(P)-2♦-(P) Assume that 1♠ is limited to a bad 21 HCP (yes, they do exist!) and 2♦ shows 6-7 HCP. 1. Should Opener rebid 3♣ with 16-18 HCP?2. Should Opener rebid 4♣ with 19-21 HCP? Quote Link to comment Share on other sites More sharing options...
helene_t Posted April 9, 2013 Report Share Posted April 9, 2013 somewhat depending on honour location but most likely opener should pass with 16-17, bid 2NT with 18-19 and 3NT with 20-22. Or something like that. Quote Link to comment Share on other sites More sharing options...
rhm Posted April 9, 2013 Report Share Posted April 9, 2013 Playing normal Precision, with the following Match-Point bidding: Opener Hand: 5=3=1=4Responder Hand: 1=3=6=3 1♣-(P)-1♦-(P)1♠-(P)-2♦-(P) Assume that 1♠ is limited to a bad 21 HCP (yes, they do exist!) and 2♦ shows 6-7 HCP. 2. Should Opener rebid 4♣ with 19-21 HCP?This depends on agreementsBut agreements, which suggest to bypass 3NT, when there is a suggestion of a misfit already and 3NT is your most likely game contract, are simply a big error in Bridge judgment.Agreements must first cater for the most likely successful contracts not the least ones. Rainer Herrmann Quote Link to comment Share on other sites More sharing options...
WellSpyder Posted April 9, 2013 Report Share Posted April 9, 2013 1. Should Opener rebid 3♣ with 16-18 HCP?2. Should Opener rebid 4♣ with 19-21 HCP?I would expect 3♣ to be forcing, on normal approach forcing principles, so there is no need to jump to 4♣ without significantly more shape than 5-4. If you don't want to bid 2N/3N, then 3♣ sounds OK to me. Quote Link to comment Share on other sites More sharing options...
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