lycier Posted March 1, 2013 Report Share Posted March 1, 2013 [hv=pc=n&s=s2h32dkq9876ckj97&d=n&v=0&b=1&a=1cp1dp1np]133|200[/hv] Assume that the partner open 1♣,you respond to 1♦,it is a normal auction,however,with the opener rebid any bids including 1♥ ,1♠ or 1nt at 1-level,and then some problems will come to pass,now for this hand,how do you handle? 假如同伴开叫1♣,你应叫1♦后,问题来了:开叫人在一阶再叫包括1♥,1♠和1nt时,你是如何构思处理好这副牌的再叫描述? Quote Link to comment Share on other sites More sharing options...
chenxuemin Posted March 2, 2013 Report Share Posted March 2, 2013 2c!-2d-2nt(4-c邀局) 如果不是1nt,就3d换2nt Quote Link to comment Share on other sites More sharing options...
lycier Posted March 3, 2013 Author Report Share Posted March 3, 2013 ####牌面估值:这是一幅邀请牌力的牌面,也许开叫人只要有一枚♦Ace就是赢墩大部所需。 ####当你不打XYZ约定叫时,采取朴实的方法:持6张牌面的邀请,这是一副任何体系都难描述的牌面。不打XYZ约定叫时,采取朴实的方法是:跳叫3♦做邀请。而跳叫3♣是逼局逼叫的唯一进程。 ####当你打XYZ约定叫时,采取约定的方法:2♣接力至2♦后,再次叫3♦. Quote Link to comment Share on other sites More sharing options...
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