FM75 Posted February 11, 2013 Report Share Posted February 11, 2013 OCP 1♣ - 1♦ (1♥)2N - 3N Quote Link to comment Share on other sites More sharing options...
Lord Molyb Posted February 18, 2013 Report Share Posted February 18, 2013 I'm not pro enough to end up defending 1♥x ;) Molybdenum Forcing Pass System:S ---- NP --- 1♣ (1♥) (opening hand, 0-bad 12)dbl --- 2♠ (4+ ♠ and pretty much anything else, 6-9 points and 4 spades :blink: )4♠ --- P (signoff) OCP 1♣ - 1♦ (1♥)2N - 3NHow do you find spades with that system?What do those bids mean? Quote Link to comment Share on other sites More sharing options...
CamHenry Posted February 25, 2013 Report Share Posted February 25, 2013 Unnamed Homebrew Diamond:2♣-2♦ weak ♦ OR weak majors OR GF majors OR 20-23 bal / pass-or-correct2N-2♦ 20-23 bal / transfer ♥3♥-3♠ denies 4-card support / also 4 ♠4♦-4♥ 5 or 7 CPs, agreeing ♠ / interest in slam opposite 75♣-5♠ second-round ♣ control / signoff as there is ♣ duplication Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted February 26, 2013 Report Share Posted February 26, 2013 Unnamed Homebrew Diamond:4♦-4♥ 5 or 7 CPs, agreeing ♠ / interest in slam opposite 75♣-5♠ second-round ♣ control / signoff as there is ♣ duplicationSouth has 6 CPs (1 ace and 4 kings). What would South bid over 4♥ with first round club control instead of second? Quote Link to comment Share on other sites More sharing options...
CamHenry Posted February 26, 2013 Report Share Posted February 26, 2013 South has 6 CPs (1 ace and 4 kings). What would South bid over 4♥ with first round club control instead of second? (i) we count the trump Q as a control(ii) after establishing that we may have enough CPs for slam (11 for small, 13 for grand), we bid 2nd-round controls up the line. If duplication is found, we sign off. Obviously with 6 facing 6, for example, we can ignore the first point of duplication (K facing singleton).(iii) I miscounted N's controls; on the actual hand he's only got 3 CPs (DA, C singleton) and would therefore sign off in 4♠ Let's modify the hands a little to T943JT965AK39 AKQ8KQQ974A85 Here S still has 7 CPs (2 aces at 2 each, 2 kings at 1 each, trump Q at 1) and N now has 4 (A, K, singleton). The auction, from S making a slam try in S, would be:4♦-4♥ 5 or 7 CPs, agreeing ♠/interest in slam opposite 75♥-6♠ Second-round ♥ control, no 2nd-round control in either minor, 7 CPs/7 facing 4, no duplication, => 11 working CPs, a fit, and hopefully enough for slam. I hope this illustration is a little clearer! Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted February 26, 2013 Report Share Posted February 26, 2013 I hope this illustration is a little clearer!Excellent description! Yes, that is much clearer. The point I am still slightly unsure of is when you say that North has 3 CPs consisting of ♦A and ♣x. First of all, that you count a singleton as 1CP and secondly if that means the ♦K is not worth anything. Finally, there is a the question as to how you find duplication opposite a void. This is certainly an interesting method though - not one I have come across before. Quote Link to comment Share on other sites More sharing options...
CamHenry Posted February 26, 2013 Report Share Posted February 26, 2013 Excellent description! Yes, that is much clearer. The point I am still slightly unsure of is when you say that North has 3 CPs consisting of ♦A and ♣x. First of all, that you count a singleton as 1CP and secondly if that means the ♦K is not worth anything. Finally, there is a the question as to how you find duplication opposite a void. This is certainly an interesting method though - not one I have come across before. First off, in the original hand N has 3CPs as he doesn't have the ♦K. We count singletons as 1 CP. As for voids: we also count those as singletons if responding to the slam try. We try not to make a slam try of this type when holding a void: there are many different enquiries we can make (e.g. Exclusion, etc.; on some sequences we have cue-bidding available). Full system notes are available at http://www.matthew.ath.cx/misc/systemnotes.pdf - the section on this slam method is at p.34 (General Swiss). We picked it up from another player at the Cambridge Bridge Club (I think we tweaked it a bit, but I can't remember). Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted February 26, 2013 Report Share Posted February 26, 2013 Thanks for this link. The write-up is very clear and the approach is interesting. It is (kind of) a little like Turbo but with CPs instead of key cards. Hopefully it will come up on a few of the upcoming hands so we can see it in action. For the strong 2-suited openings, you could take a look at Ben (inquiry)'s MisIry method if you wanted to add some extra detail/complexity to the follow-ups. Quote Link to comment Share on other sites More sharing options...
PrecisionL Posted March 1, 2013 Report Share Posted March 1, 2013 Upgraded Ultra Club Relay (C3) 1♣ - 1♦ (1♥)X for TO - 1♠ (hearts are not good enough for penalty pass) -2♠ - 4♠ All Pass Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.