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Deal #12


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I'm not pro enough to end up defending 1x ;)

 

Molybdenum Forcing Pass System:

S ---- N

P --- 1 (1) (opening hand, 0-bad 12)

dbl --- 2 (4+ and pretty much anything else, 6-9 points and 4 spades :blink: )

4 --- P (signoff)

 

 

OCP

 

1 - 1 (1)

2N - 3N

How do you find spades with that system?

What do those bids mean?

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Unnamed Homebrew Diamond:

2-2 weak OR weak majors OR GF majors OR 20-23 bal / pass-or-correct

2N-2 20-23 bal / transfer

3-3 denies 4-card support / also 4

4-4 5 or 7 CPs, agreeing / interest in slam opposite 7

5-5 second-round control / signoff as there is duplication

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South has 6 CPs (1 ace and 4 kings). What would South bid over 4 with first round club control instead of second?

 

(i) we count the trump Q as a control

(ii) after establishing that we may have enough CPs for slam (11 for small, 13 for grand), we bid 2nd-round controls up the line. If duplication is found, we sign off. Obviously with 6 facing 6, for example, we can ignore the first point of duplication (K facing singleton).

(iii) I miscounted N's controls; on the actual hand he's only got 3 CPs (DA, C singleton) and would therefore sign off in 4

 

Let's modify the hands a little to

 

T943

JT965

AK3

9

 

AKQ8

KQ

Q974

A85

 

Here S still has 7 CPs (2 aces at 2 each, 2 kings at 1 each, trump Q at 1) and N now has 4 (A, K, singleton). The auction, from S making a slam try in S, would be:

4-4 5 or 7 CPs, agreeing /interest in slam opposite 7

5-6 Second-round control, no 2nd-round control in either minor, 7 CPs/7 facing 4, no duplication, => 11 working CPs, a fit, and hopefully enough for slam.

 

I hope this illustration is a little clearer!

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I hope this illustration is a little clearer!

Excellent description! Yes, that is much clearer. The point I am still slightly unsure of is when you say that North has 3 CPs consisting of A and x. First of all, that you count a singleton as 1CP and secondly if that means the K is not worth anything. Finally, there is a the question as to how you find duplication opposite a void. This is certainly an interesting method though - not one I have come across before.

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Excellent description! Yes, that is much clearer. The point I am still slightly unsure of is when you say that North has 3 CPs consisting of A and x. First of all, that you count a singleton as 1CP and secondly if that means the K is not worth anything. Finally, there is a the question as to how you find duplication opposite a void. This is certainly an interesting method though - not one I have come across before.

 

First off, in the original hand N has 3CPs as he doesn't have the K. We count singletons as 1 CP.

 

As for voids: we also count those as singletons if responding to the slam try. We try not to make a slam try of this type when holding a void: there are many different enquiries we can make (e.g. Exclusion, etc.; on some sequences we have cue-bidding available).

 

Full system notes are available at http://www.matthew.ath.cx/misc/systemnotes.pdf - the section on this slam method is at p.34 (General Swiss). We picked it up from another player at the Cambridge Bridge Club (I think we tweaked it a bit, but I can't remember).

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Thanks for this link. The write-up is very clear and the approach is interesting. It is (kind of) a little like Turbo but with CPs instead of key cards. Hopefully it will come up on a few of the upcoming hands so we can see it in action. For the strong 2-suited openings, you could take a look at Ben (inquiry)'s MisIry method if you wanted to add some extra detail/complexity to the follow-ups.
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