zyp163 Posted January 6, 2013 Report Share Posted January 6, 2013 [hv=pc=n&s=s32hk65432d2cakqj&n=saqjt9hj7dakqjc32&d=s&v=0&b=11&a=1hp1sp2cp2dp2hp6hppp]266|200|West lead D10[/hv] 西首攻D10不妙的定约，但依然有完成的机会。请设计一下线路。 Quote Link to comment Share on other sites More sharing options...
000ffj Posted January 6, 2013 Report Share Posted January 6, 2013 只能寄望于特定牌面，即西家skxx,hxxx,dxxx,cxxxx,东家sxxx,h aq d xxxx c xxxx,交叉将吃完成定约 Quote Link to comment Share on other sites More sharing options...
zyp163 Posted January 9, 2013 Author Report Share Posted January 9, 2013 000ffj说的对，特定的牌面必须如下：[hv=pc=n&s=shk6dcj&w=sht98dc&n=s9hj7dc&e=shaqdc2]399|300[/hv]根据这种局面设计线路即可. Quote Link to comment Share on other sites More sharing options...
madongjun Posted January 9, 2013 Report Share Posted January 9, 2013 多么弱的将牌呀，看来边花的均分是必须的。这样才能在减将过程中不至于被超将吃。还要注意顺序和进手的调配。 Quote Link to comment Share on other sites More sharing options...
dvd Posted May 23, 2013 Report Share Posted May 23, 2013 怎么瞅着这么熟悉呢？如果没有记错，应该是N年前桥牌杂志上的一副，给个完整答案吧。 [hv=pc=n&w=sk54ht98d5432c654&e=s876haqd9876ct987]266|100[/hv] 庄家需要4重缩将，然后明手hJ将c，必须要飞到sK。 Quote Link to comment Share on other sites More sharing options...
zyp163 Posted May 24, 2013 Author Report Share Posted May 24, 2013 BM2000做庄练习第五级的C09，我发的贴图对东西的牌标错了。原理：当西-东的将牌是T98-AQ时，庄家手上将吃四次明手的D与S，第11墩时，庄家手上打出最后一张C（要求东家是4个C）时，明手超吃西家将牌，第十二墩时，从明手出S，拿到第十二墩。与之前madongjun发的龚启英的《醉牌》例子一样，异曲同工。http://www.bridgebase.com/forums/topic/60315-%26-26377%3B%26-36259%3B%26-30340%3B%26-19968%3B%26-25163%3B%26-29260%3B%26-65288%3B%26-25688%3B%26-33258%3B%26-37257%3B%26-29260%3B%26-65289%3B/ Quote Link to comment Share on other sites More sharing options...
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