lycier Posted December 28, 2012 Report Share Posted December 28, 2012 小splinter翻译:lycier 定义:由开叫人或应叫人所作出的跳逆叫表示4张支持,所跳叫的花色是单缺,16+分布点,邀请估值。 1C - 1S;3D 承诺4张S支持,D单缺,邀请估值。1C - 1S;3D - 3S 应叫人最低水平叫回将牌=止叫,低限估值。1C - 1S;3D - 4S 应叫人直接进局=补偿估值。1C - 1S;3D - ? 当有额外估值时,应叫人可以扣叫新花=有额外估值,满贯兴趣,在短套中没有浪费的估值。注意:1-有些搭档约定:小splinter逼局。2-依据定义,小splinter肯定要低于应叫人的花色,当应叫人低限6-坏8p时,允许应叫人止叫于3H/S. Quote Link to comment Share on other sites More sharing options...
wuhuan Posted December 29, 2012 Report Share Posted December 29, 2012 老师好:学习了才知道这个叫品官名——小斯普林特,谢谢您! Quote Link to comment Share on other sites More sharing options...
lycier Posted December 29, 2012 Author Report Share Posted December 29, 2012 貌似简单,其实应用起来复杂的变化也不少,必须是搭档间的约定了。本帖子里,我们看到的splinter都是跳叫方式的,还有splinter是约定性的,非跳叫性的。比如: [hv=d=n&v=0&b=1&a=1dp2dp3cp]133|100[/hv] 这个3♣就是非跳叫性的spinliter,♣单张。 惟须注意的是,在哈代体系中,应用直接性的splinter越来越少了,而代之以隐匿性的splinter的广泛应用。 Quote Link to comment Share on other sites More sharing options...
sungh Posted January 5, 2013 Report Share Posted January 5, 2013 总结一下spinliter约定叫。首先spinliter是对同伴的加叫,主要分有开叫方的spinliter和应叫方的spinliter两大类。1、应叫方的spinliter:①应叫人所作出的跳逆叫表示对开叫花色的4张支持,所跳叫的花色是单缺,逼局。②哈代加叫,使用隐匿性的spinliter。③MTWS和XYZ约定中的spinliter序列。2、开叫方的spinliter:①由开叫人所作出的跳逆叫表示4张支持,所跳叫的花色是单缺,16+分布点,邀请估值。②在逼叫性1nt后,开叫人在四阶上再叫新花。③约定性的,非跳叫性的spinliter。如低花反加叫后的spinliter。见楼上的例子。请大家补充。 Quote Link to comment Share on other sites More sharing options...
lycier Posted January 6, 2013 Author Report Share Posted January 6, 2013 那孙老版,请您说说非跳叫性的spinliter特指的例子。好像有两种,应该都掌握了,知识总结不容易。 Quote Link to comment Share on other sites More sharing options...
sungh Posted January 10, 2013 Report Share Posted January 10, 2013 那孙老版,请您说说非跳叫性的spinliter特指的例子。好像有两种,应该都掌握了,知识总结不容易。约定性的,非跳叫性的spinliter的两种特例。1.低花反加叫后的spinliter。如:1D-2D后;3C。2.高花加叫后的spinliter。如:1M-2M后;3阶新花。 Quote Link to comment Share on other sites More sharing options...
lycier Posted January 10, 2013 Author Report Share Posted January 10, 2013 孙老版,毫不犹豫的标准答案,厉害呀。 Quote Link to comment Share on other sites More sharing options...
lycier Posted March 6, 2013 Author Report Share Posted March 6, 2013 正式的小splinter必须是含4张将牌支持的应叫;其目的是表露出单缺花色,同时也不向敌透露更多的信息。邀局。根据美国桥牌百科全书,定义牌力范围:14-17p。在哈代体系中,由于直接splinter叫品让位给反瑞士加叫,所以大量采用mini-splinter(小splinter)和concealed splinter(隐匿性splinter),下面介绍一些我们至今沿用的splinter: 1-[hv=d=n&v=0&b=1&a=1hp1sp4cp]133|100[/hv][hv=d=n&v=0&b=1&a=1hp1sp4dp]133|100[/hv] 2-[hv=d=n&v=0&b=1&a=1cp1hp3dp]133|100[/hv][hv=d=n&v=0&b=1&a=1cp1hp3sp]133|100[/hv][hv=d=n&v=0&b=1&a=1cp1sp3dp]133|100[/hv][hv=d=n&v=0&b=1&a=1cp1sp3hp]133|100[/hv] 3-[hv=d=n&v=0&b=1&a=1sp2hp2sp4cp]133|100[/hv][hv=d=n&v=0&b=1&a=1sp2hp2sp4dp]133|100[/hv] 4-[hv=d=n&v=0&b=1&a=1sp2hp4cp]133|100[/hv][hv=d=n&v=0&b=1&a=1sp2hp4dp]133|100[/hv] 5- [hv=d=n&v=0&b=1&a=1sp2dp2sp4cp]133|100[/hv] 6-[hv=d=n&v=0&b=1&a=1sp2hp4cp]133|100[/hv][hv=d=n&v=0&b=1&a=1sp2hp4dp]133|100[/hv] 7-[hv=d=n&v=0&b=1&a=1h1s3sp]133|100[/hv] 8-[hv=d=n&v=0&b=1&a=1np2dp2hp4dp]133|100[/hv] 9-[hv=d=n&v=0&b=1&a=1sp1np]133|100[/hv] 开叫人再叫4♣,4♦,4♥都是单 Quote Link to comment Share on other sites More sharing options...
lycier Posted March 6, 2013 Author Report Share Posted March 6, 2013 [hv=d=n&v=0&b=1&a=1dp1sp4cp]133|100[/hv] [hv=d=n&v=0&b=1&a=1dp1sp4hp]133|100[/hv] [hv=d=n&v=0&b=1&a=1cp1sp4dp]133|100[/hv] [hv=d=n&v=0&b=1&a=1cp1sp4hp]133|100[/hv] 都表示18p+估值分布点,4张将牌支持,所叫花色为单缺。 Quote Link to comment Share on other sites More sharing options...
lycier Posted March 6, 2013 Author Report Share Posted March 6, 2013 以开叫1♦为例: [hv=d=n&v=0&b=1&a=1dp1sp3cp]133|100[/hv] 表示18p,低花5-5分布,逼叫。 [hv=d=n&v=0&b=1&a=1dp1sp3hp]133|100[/hv] 表示14-17p,也许有单张,尤其是好的14p时,邀局;允许应叫人在坏8p以下牌力时,再叫3♠止叫;而下面如果是: [hv=d=n&v=0&b=1&a=1dp1sp3hp4spp]133|100[/hv] 表示拥有足以进局没有满贯兴趣的补偿估值。 [hv=d=n&v=0&b=1&a=1dp1sp4cp]133|100[/hv] 表示18p+估值分布点,4张将牌支持,所叫花色为单缺。 [hv=d=n&v=0&b=1&a=1dp1sp4dp]133|100[/hv] 高花附加叫,6张半强♦套+4张♠;最差也是12p的双套硬实力的纯净牌,也有14-17p双套牌的情况。满贯兴趣。一般后续注意采用扣叫示控的方法。 Quote Link to comment Share on other sites More sharing options...
lycier Posted March 8, 2013 Author Report Share Posted March 8, 2013 这些都是最基础的需要你颠来倒去反反复复弄明白记清楚的基础知识和叫牌技巧啊。 Quote Link to comment Share on other sites More sharing options...
sungh Posted March 9, 2013 Report Share Posted March 9, 2013 点击可以进入开叫人叫无将后的spinliter实例1、[hv=d=n&v=0&b=1&a=1cp1hp1np3s]133|100[/hv] 2、[hv=d=n&v=0&b=1&a=1np2np3cp3h]133|100[/hv] 3、[hv=d=n&v=0&b=1&a=1cp1hp1np2cp2dp3s]133|100[/hv] Quote Link to comment Share on other sites More sharing options...
wuhuan Posted March 12, 2013 Report Share Posted March 12, 2013 这么多的叫品,一定要好好吸收,掌握。 Quote Link to comment Share on other sites More sharing options...
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