lycier Posted October 26, 2012 Report Share Posted October 26, 2012 [hv=d=n&v=0&b=1&a=1h1s]133|100[/hv] 很简单,假如南家同伴争叫的叫品依次是: 2♦ 3♦ 4♦ 5♦ 6♦ 你愿意如何定义这些竟叫叫品的含义? Quote Link to comment Share on other sites More sharing options...
sungh Posted October 26, 2012 Report Share Posted October 26, 2012 我来答一下，不知道正确否：2♦=5张以上♦；邀叫3♦=哈代加叫之低一级花色的跳加叫，隐匿性是斯普林特4♦=哈代加叫之瑞士反加叫5♦=方块独立套，高度描述性，6♦=同上； Quote Link to comment Share on other sites More sharing options...
601821297 Posted October 26, 2012 Report Share Posted October 26, 2012 我来试试2D=自由叫品，邀叫实力5张以上D3D=低一级的限制性加叫,隐蔽的斯普林特，9~12大牌点，4张将牌支持4D=颠倒瑞士加叫，12~15大牌点，4张较差的将牌支持5D=排除关键张问叫6D=D+H双套示选 Quote Link to comment Share on other sites More sharing options...
yzdhy668 Posted October 27, 2012 Report Share Posted October 27, 2012 我认为2D比较明确表示 邀请牌力5张+套；3D需要约定，3D可以表示阻击(也可是D套+H支持需约定），因加叫H可用2S或3S表示 4D可理解为以H为将的SLT5D是H为将将的排除问叫我赞成6D应表示要打 Quote Link to comment Share on other sites More sharing options...
lipeng2076 Posted October 27, 2012 Report Share Posted October 27, 2012 前面的怎与格格都一致，只是最后的6d，我理解为大满贯邀请叫，有一d顶张或者额外缺门控制就叫7h，没有就叫回6h。持牌类似为：HAx x x x xx DKQJT32 S-- C--。这牌不适合排除关键张问叫。您认为呢？ Quote Link to comment Share on other sites More sharing options...
dvd Posted August 30, 2013 Report Share Posted August 30, 2013 2d，强自由逼叫一轮；3d，hardy隐蔽splinter；4d，d6h4的配合显示叫；5d，缺门rkc（d套总是2d起步）；6d，和5楼一致。 Quote Link to comment Share on other sites More sharing options...
wuhuan Posted September 1, 2013 Report Share Posted September 1, 2013 5D定为排除关键张问好，哪S空门扣叫5S问吗？6D还是要打好，不然约定叫定的太多了，不好玩。 Quote Link to comment Share on other sites More sharing options...
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