Fluffy Posted October 25, 2012 Report Share Posted October 25, 2012 what is a good system to answer 1♣ (strong)-2♦ (nat 5+, maybe 5♦-4M, otherwise 6+♦) Quote Link to comment Share on other sites More sharing options...
straube Posted October 25, 2012 Report Share Posted October 25, 2012 I'd have opener bid naturally. I think that 2D call takes up too much space so I would expect a difficult aucton. Quote Link to comment Share on other sites More sharing options...
awm Posted October 25, 2012 Report Share Posted October 25, 2012 How about: 2nt = hearts2h = asking usually balanced Over 2h you can find out if partner has a 4M and what his shortness is (if any); you likely lack the space to get full shape but this is usually enough. Something like: 1c-2d-2h: 2s = hearts2n = spades3c/3h/3s = shortness with 6+ diamond3d = 6+ diamond semi-balanced Presumably after opener rebids 2h, the only possible trump suits are diamonds or responder's 4M (if any) so you can cue bid next. Quote Link to comment Share on other sites More sharing options...
Free Posted October 25, 2012 Report Share Posted October 25, 2012 Basically I do what awm says:2♥ = bal2NT = ♥rest = natural After 2♥, responder bids 2NT if he holds 5♦-4♥, other bids are natural. Quote Link to comment Share on other sites More sharing options...
woefuwabit Posted October 25, 2012 Report Share Posted October 25, 2012 what is a good system to answer 1♣ (strong)-2♦ (nat 5+, maybe 5♦-4M, otherwise 6+♦) If 2!D promises 6!Ds or 5!Ds + 4M, how would you respond to opening 1!C with 1354 or 3154? Quote Link to comment Share on other sites More sharing options...
dake50 Posted October 26, 2012 Report Share Posted October 26, 2012 Is this with a criss-cross Major transfers scheme? Esp 1H->Spades and 1S->Hearts?That response scheme puts a lot onto no-5xM hands to do something informative/useful.Like this 2D.I like 2M rebid to ask support AND how good are your Diamonds, rather as Ogust to a weak2: step 1: no goods to show;step 2: Qxx support, not 2-tops in Diamonds; etc. Quote Link to comment Share on other sites More sharing options...
SteveMoe Posted October 26, 2012 Report Share Posted October 26, 2012 After 1♣-P-2♦:With one partner, 2M is 5+ cards (alpha).2N sets up a "4-card suit transfer sequence":3♣ = 4 ♥3♦ = single suited ♦3♥= 4 ♠3♠= 4 ♣ Generically 1♣-P-2m:2M 5+ cards (alpha)3m = single suit3om = 4 ♥3♥ = 4 ♠3♠ = 4 om. With another partner we adjust the 1N, 2♣ and 2♦ responses to 1♣ as follows:1N = single suited clubs 6 + or 5+ ♣ 4+ diamonds (♣ dominant) Denies 4-card majors.2♣ = one or both 4-card majors (not 4441) 2♦ = exclusion stayman (♥=♠; ♠=♥; 2N=both; 3♣/♦=4405/50 respectively. Opener rebids 2M with 5+ but uses 2♦ with 5+/4 majors. 2♦ = balanced hand or single suited ♦ or 5+♦/4+♣ 2-suiter (♦ dominant). Denies 4-card major.(We use 1♣-P-2N to show 4M=6+m with 3♣ relay steps showing ♥&♣, ♠&♣, ♥&♦, ♠&♦). Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted October 26, 2012 Report Share Posted October 26, 2012 What do you use the 2M and 2NT responses for? Could you afford to play 2♦ = one-suited; 2♥ = 4 spades, 5+ diamonds; 2♠ = 4 hearts, 6+ diamonds; 2NT = 4 hearts, 5 diamonds? That would allow you to get back to symmetric levels, which is usually a pretty good indicator of a comfortable auction even if you are not using relays. Quote Link to comment Share on other sites More sharing options...
PrecisionL Posted October 30, 2012 Report Share Posted October 30, 2012 what is a good system to answer 1♣ (strong)-2♦ (nat 5+, maybe 5♦-4M, otherwise 6+♦)I play several schemes depending on my partner's preferences: 1) 1♣ - 2♦ = 8-10 Balanced (may have a weak 5cd minor) per Rodwell 2) 1♣ - 2♦ = 8+ and 5+ ♣ Transfer-like. Now 2NT is Staymanish and 3♦ is Beta 3) 1♣ - 2♦ = 8+ one or both minors, denies a 4cd major You pays your $ and take your choice ... Whoops, you asked about 5+♦: 1♣ - 2♣ Transfer showing 5+♦2♦ = Staymanish2M = Alpha (Support Asking)2NT asking if 4M Quote Link to comment Share on other sites More sharing options...
rsanja73 Posted October 31, 2012 Report Share Posted October 31, 2012 I play several schemes depending on my partner's preferences: 1) 1♣ - 2♦ = 8-10 Balanced (may have a weak 5cd minor) per Rodwell 2) 1♣ - 2♦ = 8+ and 5+ ♣ Transfer-like. Now 2NT is Staymanish and 3♦ is Beta 3) 1♣ - 2♦ = 8+ one or both minors, denies a 4cd major You pays your $ and take your choice ... Whoops, you asked about 5+♦: 1♣ - 2♣ Transfer showing 5+♦2♦ = Staymanish2M = Alpha (Support Asking)2NT asking if 4M Does anyone know the Meckwell continuations after 1C-2D (8-10 bal)? Also any thoughts on follow ups after 1C-2H (11-13 bal) and 1C-2N (14+ bal)? Quote Link to comment Share on other sites More sharing options...
SteelWheel Posted November 1, 2012 Report Share Posted November 1, 2012 Berkowitz/Cohen Precision after 1♣(strong)--2♦(natural, GF, 5+ suit) (and also after 2♣ response, fwiw): 2♥/2♠ = natural, 5+ suit, triggers a natural auction2NT = semi-natural, asking for more information about responder's hand (especially wrt to 4-card majors): 3♣ = 4-card ♥ suit3♦ = 4-card ♠ suit3♥ = "rebid" of minor3♠ = 4-card holding in other minor After this, if opener "accepts" the transfer into the major, we've confirmed our major suit fit on the three level and can start cuebidding. Additionally, the strong club opener could RKC or make non-RKC slam tries in either of responder's suits directly over the 3x rebid. If you like to play Precision and want to keep it pretty simple and natural-ish while avoiding the "jamming" problems of 1♣--2minor auctions, this is a pretty good system. Quote Link to comment Share on other sites More sharing options...
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