55771199 Posted October 20, 2012 Report Share Posted October 20, 2012 S:K86 H:AQ942 D:AQ3 C:K4 在1H-2C后再叫2N?3N?S:AQ4 H:KJ7 DKQJ5 C:Q93在1D-2C后再叫2N?3N?二个牌例请各位高手解答并解释一下详细的原因.谢谢 Quote Link to comment Share on other sites More sharing options...
gamebridge Posted October 20, 2012 Report Share Posted October 20, 2012 简单点的:开叫1M的5332,同伴二盖一低花后,不考虑止张情况。再叫:2N=12-14 或 18-19(其后同伴3NT就4NT表示余力。);3N=15-17。 原因很简单,速度表明点力牌型。 例二 一样处理。 1 Quote Link to comment Share on other sites More sharing options...
cqwbc Posted October 20, 2012 Report Share Posted October 20, 2012 简单点的:开叫1M的5332,同伴二盖一低花后,不考虑止张情况。再叫:2N=12-14 或 18-19(其后同伴3NT就4NT表示余力。);3N=15-17。 原因很简单,速度表明点力牌型。 例二 一样处理。 同意！ Quote Link to comment Share on other sites More sharing options...
yunlongg Posted October 20, 2012 Report Share Posted October 20, 2012 1 2NT, 原因见2楼2 3NT。 1d-2c后，开叫方再叫2nt为12-14 4♦，再叫3NT为 18-19hcp，4♦. 这时再叫，开叫低花和开叫高花有差别，因为这时已经不存在15-17的均型牌了。 注意一点，1d-2c后，再叫2NT或3NT，都否认有5♦，既牌型为4432或4333。如有5♦必须再叫2d。 Quote Link to comment Share on other sites More sharing options...
21574770 Posted October 22, 2012 Report Share Posted October 22, 2012 2盖1过后叫2NT可能是低限，但由于是逼叫到局的，所以高限也可以只叫2NT，以后再显示高限，18-19P应再叫2NT Quote Link to comment Share on other sites More sharing options...
55771199 Posted October 22, 2012 Author Report Share Posted October 22, 2012 谢谢各位朋友的解答！在二盖一的上册中这个问题的处理和yunlongg的说法是一致的，但是通过牌例处理看到的，并没有解释原因，我还以为是书中有误呢，我在此之前的想法和其他朋友一样。 Quote Link to comment Share on other sites More sharing options...
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