cargobeep Posted October 11, 2012 Report Share Posted October 11, 2012 Is there any possible hand where no one can make 1♣,1♦,1♥,1♠, or 1 notrump, regardless of who is declarer (double-dummy play)? Some of you of course are thinking I'm crazy, since someone has to take at least 7 tricks on any play of the hand. But the placement of the lead can of course affect how many tricks you can take. So, is it possible? :D 1 Quote Link to comment Share on other sites More sharing options...
RunemPard Posted October 11, 2012 Report Share Posted October 11, 2012 NORTHKxxxKxxKxxKQx EASTAQxxAQxxQJxAx SOUTHJxJ432Axx5432 WESTxxxxxxxxxJxxx This looks rather challenging for all sides... Quote Link to comment Share on other sites More sharing options...
rwbarton Posted October 12, 2012 Report Share Posted October 12, 2012 See http://bridge.thomasoandrews.com/deals/parzero/ for a large number of examples with analysis. Quote Link to comment Share on other sites More sharing options...
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