Precision 1D: 4M unbal or bal. Developments?

[arnoldson]

Assuming 1D shows 4M and an unbalanced hand, i.e. a longer minor or 4441 shape, or a variable NT range (11-13 or 14-16 depending on vul/seat), what should the continuations be? Yes, I tried searching.

 

Courtesy of Bertheau and Nystrom I have:-

1♦-1♥ (nat or relay):

1♠=11-15, 5+m and 4♠, 1NT=BAL, not 4♥, 2♣=4♥ not BAL, 2♦=Max, 4♠ 3♥ +SPL, 2♥=BAL 4♥, 2♠=12-16, 4144, 2NT=Max, 6♦4♥, 3♣=Max, 6♣ 4♥

1♦-1♠ (nat):

1NT=BAL w/o 4♠ or 1444

2m= 5+suit w/ 4♥. and 0-2♠

2H.=4S. any hand

2S.=11-14, 4H. 3S. + SPL

2NT=Good Max w/ SPL and 3S

3.=Max 6+suit w/ 4S

3.=Max 6+suit w/ 4S

 

Obviously this needs some fleshing out, or alternatively maybe you can think of something better entirely. I'm particularly dubious about the 1D-1S-1NT sequence. This could evidently be anywhere between a flat 11 count and a 1444 15 or even 16.

[mattias]

This is what we play. The difference is that we don't use relays over 1♦, so the 1♥ response is natural. Because of this we we change the responses slightly. Also, after 1♦ - 1♠ we rebid 2♣/♦ with 1444 if we are out of the balanced range. If we're in the balanced range we can choose between 1NT and 2♣/♦.

 

After 1♦ - 1♥ - 1♠ the responses are

 

1NT relay, 11+

2♣ P/C

2♦ 9-12 with 4 spades, continue over a signoff with max

2♥ 9-12 six hearts, compare w. 3♥

2♠ 5-8

2NT GF spade raise

3♣/♦ 4♥ 6m invite

3♥ 11-12 6 hearts good suit

 

After 1♦ - 1♥ - 1♠ - 1NT

 

2♣/♦ 11-13 5+minor, 4 spades, 0-2 hearts

2♥ 11-13 5+minor, 4 spades, 3 hearts. Now 2♠ asks for the suit, 2NT is nat non-forcing and 3♣ is P/C

2♠ 11-13 4144

2NT 14-15 4315

3♣ 14-15 4351

3♦ 14-15 4225

3♥ 14-15 4252

3♠ 14-15 4135

3NT 14-15 4153

 

Over the 14-15 showing bids the lower bids show longer hearts so repsonder can set hearts by bidding 3♥

[Zelandakh]

You could certainly start with a "skip bid" base which seems to work quite well opposite this kind of opening:-

 

1♥ = <4 hearts

... - 1♠ = 4 spades

... - 1NT = nat

... - 2♣ = clubs and hearts

... - 2♦ = diamonds and hearts

1♠ = 4+ hearts, <4 spades

... - 1NT = nat

... - 2♣ = clubs and spades

... - 2♦ = diamonds and spades

... - 2♥ = nat raise

 

Any of 1NT, 2♣ and/or 2♦ can handle the hands with 4+ hearts and 4+ spades and any unused bids can be employed to catch any awkward hand types.

[dake50]

Do you intend some catchall continue-to-explore

as NmF, Checkback, XYZ?

Or natural rebids not reserving some rebid to

explore? Rather a seat-of-the-pants scheme.

Reserving some general exploring bid frees

up other bids to be clear.

Flesh it out that way seems best.

[PrecisionL]

I would ask a different question for playing such a 1♦ opening:

 

Can responder limit his hand so that opener's rebids do not get us too high?

 

My answer (playing such a 1♦ opening with two partners):

 

1♥ = Usually 4 or more ♥, may have longer ♠, may be very weak with 3♥ and 0-2 ♦

1♠ = denies 4♥ and less than invitational values (limit raise)

1NT = 6-9 hcp

2♣ = 0-9 hcp and 9 cards or more in the minors: Pass or correct

3♣ = 10-11 hcp (LR) and 9 cards or more in the minors: G.I.

 

2♦ = LR with or without a 4-cd major or ♦ support

2♥/♠ = G.I. playable opposite a singleton trump

2NT = G.F. asking for singleton or void

3NT = To play

 

Opener's rebids: 1NT = balanced or 4441 with 1 in responder's suit

2♣ or 2♦ = 5 or 6 in the minor and 4 in the other major

[Free]

You could certainly start with a "skip bid" base which seems to work quite well opposite this kind of opening:-

 

1♥ = <4 hearts

... - 1♠ = 4 spades

... - 1NT = nat

... - 2♣ = clubs and hearts

... - 2♦ = diamonds and hearts

1♠ = 4+ hearts, <4 spades

... - 1NT = nat

... - 2♣ = clubs and spades

... - 2♦ = diamonds and spades

... - 2♥ = nat raise

 

Any of 1NT, 2♣ and/or 2♦ can handle the hands with 4+ hearts and 4+ spades and any unused bids can be employed to catch any awkward hand types.

Very nice idea.

 

I wonder if reversing the Majors would be better, because ♠s are most important. Use 1♥ to show <4♠ and 1♠ to show 4+♠. And after 1♦-1♥: 1♠ = 4♥ / 1NT = nat / 2m = 4♠ & 5+m