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Sorry, I thought you posed the question as a riddle, not as a genuine question. I'll try to explain why I think the A is right, and better players will hopefully correct me if I'm wrong.

Because dummy has a singleton diamond, and there are seven diamonds out there, even if the K is "onside" (i.e. the Q wins), we won't be able to repeat the winning finesse - we just don't have any more diamonds to lead. So, playing the Q is a losing proposition, pretty much irrespective of where the K is. The fact the 8 was the card that was led is also important: it means my AQJT7 just became solid (i.e. the 7 is a top honor), and it makes it almost impossible for the king to be with the opening leader (assuming they lead high from doubleton, low from honor, etc).

So, I give up on the finesse, and switch to a plan called "ruffing finesse", where I lead my sequence of honors and discard losers from dummy. If the K is "wrong" (for a regular finesse) it's now "right" - if W covers, I can ruff and the rest of my diamonds are good. And if the king was with E, it's no biggie, I'll lose a diamond but I already discarded a loser on that trick, so I didn't really lose anything.

The only problem with running the sequence is if I can lose two diamonds - one to the K and one to a ruff. That's why I proposed starting with three rounds of trumps, so even if trumps are 4-1, once you lose one diamond trick to the K, you can draw the outstanding trump and run diamonds.

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How does one make 6 if you play the Ace? You have to lose a trump and the SA.

 

ahydra

Win the A.

Play a spade, knocking out the A.

Win any return, cash two spades and two clubs and try to cross ruff the rest. You have to be careful to play the opening leader for short diamonds. You can only make one low diamond ruff.

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