Jinksy Posted November 30, 2011 Report Share Posted November 30, 2011 Suppose you're playing a version of Gazz, with a (semi)forcing 2/1. It goes 1S 1N 2C back to you. Is there a clearly best system to deal with the following distributions when too weak for a 2D response? 1444, 1435,1453, 1345,1354, 1255 (if it makes a difference, 1S 1N 2N would have been a strong balanced hand. No room for it to be otherwise in our system) 1 Quote Link to comment Share on other sites More sharing options...
paulg Posted November 30, 2011 Report Share Posted November 30, 2011 Suppose you're playing a version of Gazz, with a (semi)forcing 2/1. It goes 1S 1N 2C back to you. Is there a clearly best system to deal with the following distributions when too weak for a 2D response? 1444, 1435,1453, 1345,1354, 1255 (if it makes a difference, 1S 1N 2N would have been a strong balanced hand. No room for it to be otherwise in our system)Short answer: No. Longer answer: The 1444 is the most problematic and I'd just bid two spades and hope to survive. With five clubs I just raise to three clubs. With five diamonds I bid 2NT which often implies secondary clubs and gives us a chance to play in three clubs when partner is not strong without a diamond fit. Quote Link to comment Share on other sites More sharing options...
Jinksy Posted November 30, 2011 Author Report Share Posted November 30, 2011 After 1S 1N 2C, would 2H normally show 4+ or 5+? 1 Quote Link to comment Share on other sites More sharing options...
Free Posted November 30, 2011 Report Share Posted November 30, 2011 Not sure what you mean with "(semi)forcing 2/1", must be something new. :rolleyes: 1444: as I described on my blog, this is THE problem case. There's no good solution, but usually I'll bid 2♥. This promisses 5+♥, but hey, nothing is perfect... If I have a stiff ♠ honor, I might be tempted to bid 2♠. If I have 4 small ♥s and a small ♠, then I usually bid 2NT showing both minors. 1435: easy 3♣. 1453: I prefer to bid 2NT with this. 1345: I prefer to bid 2NT with this, although 3♣ is also fine (depends on suit quality). 1354: easy 2NT. 1255: easy 2NT. Quote Link to comment Share on other sites More sharing options...
zenko Posted November 30, 2011 Report Share Posted November 30, 2011 Suppose you're playing a version of Gazz, with a (semi)forcing 2/1. It goes 1S 1N 2C back to you. Is there a clearly best system to deal with the following distributions when too weak for a 2D response? 1444, 1435,1453, 1345,1354, 1255 (if it makes a difference, 1S 1N 2N would have been a strong balanced hand. No room for it to be otherwise in our system) 1444 - 2S1435 - 2S/2N depending of the texture, most of the time 2S better1453 - 2S1345 - 2N1354 - 2S1255 - 2N Key thing to consider is that the issue of missing club fit in real life rarely occurs, with a half a deck of points and likley 8 card fits in a red suit(s) they will almost never let you bid alone, which is actually a good thing in these cases, i.e. if they do not interefere assume pard has a strong option, and will knowe to bid again if needed after you "support" him with singleton, he is very much aware that you have exactly 1 or 2 spades and very crappy hand 2 Quote Link to comment Share on other sites More sharing options...
Free Posted November 30, 2011 Report Share Posted November 30, 2011 Unlike zenko I don't like bidding 2♠ with a singleton (except perhaps with a top honor and no better alternatives). Quote Link to comment Share on other sites More sharing options...
han Posted December 1, 2011 Report Share Posted December 1, 2011 I play that 1S - 1NT2C - 2H shows 4+ hearts. I would bid it with 1444 as well as 1435 and 1453. The main disadvantage is that partner will pull more often, which can hurt when you hold 6+ hearts. 2NT shows both minors. After 1H - 1NT - 2C we play that 2S and 2NT both show both minors, with 2NT showing longer diamonds. Quote Link to comment Share on other sites More sharing options...
gwnn Posted December 1, 2011 Report Share Posted December 1, 2011 We showed both minors with 1444. a little silly but hey when you have 1444 sometimes you end up in silly contracts. with 53/35 in the minors I guess we had to bid 3m, which is even worse. Quote Link to comment Share on other sites More sharing options...
Free Posted December 1, 2011 Report Share Posted December 1, 2011 After 1H - 1NT - 2C we play that 2S and 2NT both show both minors, with 2NT showing longer diamonds.We play 1♥-1NT-2♣-2♠ as 3 card ♠ and both minors. We've only had good experiences with this: once opener had 4♠ and had an easy pass, another time we just played 3m. This also means that 2NT denies 3♠ and 2♥, so you basically have at least 5-5 (because with 6-4 you bid your 6 card suit). Quote Link to comment Share on other sites More sharing options...
mattias Posted December 1, 2011 Report Share Posted December 1, 2011 Suppose you're playing a version of Gazz, with a (semi)forcing 2/1. It goes 1S 1N 2C back to you. Is there a clearly best system to deal with the following distributions when too weak for a 2D response? 1444, 1435,1453, 1345,1354, 1255 (if it makes a difference, 1S 1N 2N would have been a strong balanced hand. No room for it to be otherwise in our system) If you play a semi forcing 1NT, so that you bid 2♣ with a strong hand or with real clubs it's a good idea to switch the weak meaning in 2♣ and 2M. This way 2♣ becomes either strong or a weak onesuiter in M, and 2M becomes 11-15 with 5M and 4C. Most of your problem hands go away like this, but 1543 becomes harder to bid over 2M. In total however, you have fewer problems. Over a forcing NT where 2♣ could be a 3-card (or even a 2-card) suit this might not work so well though. 1 Quote Link to comment Share on other sites More sharing options...
Free Posted December 1, 2011 Report Share Posted December 1, 2011 If you play a semi forcing 1NT, so that you bid 2♣ with a strong hand or with real clubs it's a good idea to switch the weak meaning in 2♣ and 2M. This way 2♣ becomes either strong or a weak onesuiter in M, and 2M becomes 11-15 with 5M and 4C. Most of your problem hands go away like this, but 1543 becomes harder to bid over 2M. In total however, you have fewer problems. Over a forcing NT where 2♣ could be a 3-card (or even a 2-card) suit this might not work so well though.That's simply not true. Bidding over 2M is a lot more difficult when it shows 5M and possibly 2+♣. Playing normal Gazzilli the only problem hand is 1=4=4=4. All others have easy rebids, sometimes even multiple choices. You create more problems by reversing the meanings. Not only a 1=5=4=3, but also 1=4=5=3 are problems. Not to mention that opener can have a max balanced hand as well. Quote Link to comment Share on other sites More sharing options...
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