mck4711 Posted July 22, 2011 Report Share Posted July 22, 2011 1C - 1H1NT - 3NT, maybe 1NT not the best option, but I considered 1NT better than 2C KxxxKQ10xxAJ8x AJxA108xxA109xx opening lead: K of DWhat is the best plan? Funny: Now when writing, everything is suddenly so clear and simple :). Take both red A and then low S to K. K and Q of H, hoping that J drops. Both would follow, but no J. And now S to J, holds, and A of S. Last step: low C from hand. If LHO has both K and Q, and J of D, I make 3NT, provided he doesnt have 10xxx, Jxxx, KQJ, KQ. If he has max 3S or 3H opps get only 4 tricks. LHO has to give me 9th trick either in D or in C, endplayed. Ahhh..... Quote Link to comment Share on other sites More sharing options...
billw55 Posted July 22, 2011 Report Share Posted July 22, 2011 I would just run the ♣J at trick 2. This is 75% by itself. Also if LHO has ♦KQJxx and ♣KQ, he probably would have bid 1♦ over 1♣. Which means I have a good chance to make even when ♣KQ is offside. Quote Link to comment Share on other sites More sharing options...
Wackojack Posted July 22, 2011 Report Share Posted July 22, 2011 1C - 1H1NT - 3NT, maybe 1NT not the best option, but I considered 1NT better than 2C KxxxKQ10xxAJ8x AJxA108xxA109xx Run Jack♣, 10 tricks guaranteed if honours are split. However......If east does not cover and west plays off QJand another ♦, then you may suspect that west started with both K and Q ♣. So now try the hearts. If the jack falls then you are home. If west follows to 3 rounds then play another heart and you are home. If west started with only 2 hearts, then you have some guessing to do. Quote Link to comment Share on other sites More sharing options...
mck4711 Posted July 22, 2011 Author Report Share Posted July 22, 2011 Run Jack♣, 10 tricks guaranteed if honours are split. However......If east does not cover and west plays off QJand another ♦, then you may suspect that west started with both K and Q ♣. So now try the hearts. If the jack falls then you are home. If west follows to 3 rounds then play another heart and you are home. If west started with only 2 hearts, then you have some guessing to do. Actually, KQ are offside. So, it might be that LHO exists in H, hoping that declarer has entry-problems, meaning A of H single, or to find E with A of H, running then D through declarer - what leaves some problems.But, yes, the probability-play seems to be J of C. Quote Link to comment Share on other sites More sharing options...
billw55 Posted July 22, 2011 Report Share Posted July 22, 2011 I suppose we could construct a scenario where there is some risk to the club hook. Say LHO holds ♦KQ9xx. In with a club honor, diamond to partner's jack, diamond back through. We might try to analyze RHO's card at trick one; presumably holding ♦Jxx he will encourage. By the way, there isn't an entry problem to dummy - the second club hook is low to the 10. If it loses, the 8 is an entry. Quote Link to comment Share on other sites More sharing options...
nige1 Posted July 22, 2011 Report Share Posted July 22, 2011 (edited) IMO: mck4711's suggested line may be successful but only a kibitzer would find it. bilw55's line is sensible, even if it fails as the cards lie. Edited July 22, 2011 by nige1 Quote Link to comment Share on other sites More sharing options...
mck4711 Posted July 22, 2011 Author Report Share Posted July 22, 2011 IMO: mck4711's suggested line may be successful but only a kibitzer would find it. bilw55's line is more sensible, even if it fails as the cards lie. It seems that I see today problems where there is a quite easy solution... And these problems include to count properly up to 9. Quote Link to comment Share on other sites More sharing options...
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