whereagles Posted July 1, 2011 Report Share Posted July 1, 2011 Playing 16-18nt 2♣ is obvious. I find it obvious even if 1NT is 15-17 :) Quote Link to comment Share on other sites More sharing options...
gwnn Posted July 1, 2011 Report Share Posted July 1, 2011 http://i.imgur.com/wE5KG.jpgNot so far Quote Link to comment Share on other sites More sharing options...
JLOGIC Posted July 1, 2011 Report Share Posted July 1, 2011 Once upon a time, my partner had 4 spades when he opened 1N, and my hand was a GF and worth far more than 7 points with a singleton and a fit. Another time, my partner had 18 points, and we made 3N. An even crazier time, my partner had only a good 17 count, and we were able to make game in NT with just 24 points. Another time, partner had neither 4 spades nor a good 17-18, and we played 2N with 23-bad 24 HCP and were able to make it, so I lost nothing by inviting. I told my expert friend about these unusual occurences with my bad 7 count, and he told me that my 7 count was not so bad. In fact, I have 3 9s and a 10 in my 4 card suits. I also have an AJ combination and a Q which are pretty good honor combinations, especially in combination with my good spots. He even had the crazy idea that everyone who passes with this hand would invite with a similarly average + 4144 8 count opposite a 15-17 NT, which is almost the same thing. The things you see these days. 1 Quote Link to comment Share on other sites More sharing options...
daveharty Posted July 2, 2011 Report Share Posted July 2, 2011 <sarcasm>This is funny, and your points are well taken, it's not as if "25 hcp" is some mystical barrier that must be breached in order to make nine tricks in NT. But isn't MP about the frequency of being right? One of my first thoughts on seeing this hand was "3NT is not going to be a favorite here, why not take advantage of our slightly unusual NT range by staying low and hoping to beat the people who start with 1m-1S-2NT...and if partner has 16 or 17, far more likely than 18, other tables will be opening 1NT too and (whereagles comment notwithstanding) won't be getting any higher". Is this twisted? Quote Link to comment Share on other sites More sharing options...
semeai Posted July 2, 2011 Report Share Posted July 2, 2011 You need to factor in that one person (us) is already know to have a 7 point hand. This is what Hrothgar does above. Yes, definitely good, and the right way to do it. I applaud his post. In defense of my laziness: As gwnn notes, hrothgar's original post was unconstrained: it used randperm(52), etc at the time. In addition, he had no output at that point, so I just intended to add numbers. At least the ratio p(16hcp) : (18hcp), roughly 2:1, is similar in the constrained and unconstrained data! Quote Link to comment Share on other sites More sharing options...
whereagles Posted July 2, 2011 Report Share Posted July 2, 2011 csaba, was that R? Quote Link to comment Share on other sites More sharing options...
whereagles Posted July 2, 2011 Report Share Posted July 2, 2011 The things you see these days. Still no match for that footage of a circus goat going left and right on a hanging rope, HA! Quote Link to comment Share on other sites More sharing options...
gwnn Posted July 2, 2011 Report Share Posted July 2, 2011 whereagles: gnuplot. I will mention in passing that I fitted the points nearly perfectly with two gaussians, one centred around 9.8 and one at 2.3. Quote Link to comment Share on other sites More sharing options...
cherdano Posted July 2, 2011 Report Share Posted July 2, 2011 I find this to be a clear 2♣ bid. Most of the arguments have been exchanged, but let me just add that the fear of the natural heart lead against 3NT is way overblown. If we play 3NT, then partner has made a natural 2♥ bid. (I am passing 2♦.) Quote Link to comment Share on other sites More sharing options...
the hog Posted July 3, 2011 Report Share Posted July 3, 2011 Clear cut pass for me, 16-18 or not. Quote Link to comment Share on other sites More sharing options...
hrothgar Posted July 3, 2011 Report Share Posted July 3, 2011 Yes, definitely good, and the right way to do it. I applaud his post. In defense of my laziness: As gwnn notes, hrothgar's original post was unconstrained: it used randperm(52), etc at the time. In addition, he had no output at that point, so I just intended to add numbers. At least the ratio p(16hcp) : (18hcp), roughly 2:1, is similar in the constrained and unconstrained data! FWIW, as folks have noted, my original post didn't include the conditional probability...I probably should have waited until I had everything complete to post. Quote Link to comment Share on other sites More sharing options...
phil_20686 Posted July 3, 2011 Report Share Posted July 3, 2011 I literally cannot imagine passing. When partner has 4 spades I am surely favourite to have a decent game. If he does not we will play in 2/3N and I expect that to be close to neutral equity for that part, with a big gaim when partner has spades, Quote Link to comment Share on other sites More sharing options...
hrothgar Posted July 3, 2011 Report Share Posted July 3, 2011 I will mention in passing that I fitted the points nearly perfectly with two gaussians, one centred around 9.8 and one at 2.3. Why would you want to when there are better methods available? Non parametric fitting techniques are all fine and dandy if you can't specify an appropriate parametric model.However, its really bad form to use these if you can specify model... (Of course, the same critique can be leveled at me for using a Monte Carlo simulation instead of solving this all analytically like RP did) Quote Link to comment Share on other sites More sharing options...
gwnn Posted July 3, 2011 Report Share Posted July 3, 2011 Why would you want to when there are better methods available?I was curious how many it would take. Probably a bad excuse. :) Quote Link to comment Share on other sites More sharing options...
Flameous Posted July 3, 2011 Report Share Posted July 3, 2011 Seems like a hand for me to advertise my garbage w/ minor suit stayman twist: 1NT - 2♣ - 2red - 2♠= Nonforcing minor suit stayman, ie: shows 4 spades and both/long minor. Not having this toy, it's quite marginal invite. I'd probably still go for it. Quote Link to comment Share on other sites More sharing options...
MrAce Posted July 3, 2011 Report Share Posted July 3, 2011 I voted what i would bid at the table. 2♣ it is. Quote Link to comment Share on other sites More sharing options...
Zelandakh Posted July 3, 2011 Report Share Posted July 3, 2011 That is the lesser know part of the Crawling/Creeping Stayman convention Flameous. The first part (that many play only a subest of) is 2H showing hearts and spades or hearts and a longer minor after a 2D response. Whether the entire scheme is worth using up the 2 most economic bids after Stayman is another question... Quote Link to comment Share on other sites More sharing options...
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