manudude03 Posted January 29, 2011 Report Share Posted January 29, 2011 Fourth from the set. Other table this time :). Board 18/32. 6 imps down. [hv=pc=n&s=saqjhk96dkqtcat62&n=st74haj5daj8ckj54&d=e&v=n&b=2&a=p1cp2np4np5hp6nppp]266|200[/hv] ♥2 led to the 6-Q-A, you try the spade finesse which loses and a spade returned. If you eliminate the other suits, no-one discards anything, but if you whoever's count you believe (if either), E shows odd spades, odd hearts (present after leading) and odd diamonds while West shows odd spades, even diamonds and odd (remainder) hearts (obviously someone is lying :)). Who will you play for the ♣Q. Quote Link to comment Share on other sites More sharing options...
rogerclee Posted January 29, 2011 Report Share Posted January 29, 2011 I would rather lead from xxxx than Txxx, so if east has Txxx, we have restricted choice on him having a side 4 card suit. If he doesn't have one, he is 3433, making playing east for the ♣Q slightly more likely. He might also prefer to lead a club from 98x, so if he doesn't have this, he is also slightly more likely to have the ♣Q. Overall it's not a lot to go on but I would play east for it. Then again Crane's rule says west has it. Quote Link to comment Share on other sites More sharing options...
dellache Posted January 29, 2011 Report Share Posted January 29, 2011 This is puzzling.I can't believe East would underlead the ♥10 (dangerous !) with two perfectly safe leads in spades and diamonds xxx+. So the following might not apply to East... Anyway, as East I would certainly lead a spade/diamond with xxxx of them, hence East is 3x3z, hence East has long clubs. I finesse against him. Quote Link to comment Share on other sites More sharing options...
Finch Posted January 29, 2011 Report Share Posted January 29, 2011 This is puzzling.I can't believe East would underlead the ♥10 (dangerous !) with two perfectly safe leads in spades and diamonds xxx+. So the following might not apply to East... Anyway, as East I would certainly lead a spade/diamond with xxxx of them, hence East is 3x3z, hence East has long clubs. I finesse against him. Well, if East is Free he's led from A10xx of hearts, so West has to put the Queen in at trick 1(!) Quote Link to comment Share on other sites More sharing options...
manudude03 Posted February 1, 2011 Author Report Share Posted February 1, 2011 [hv=pc=n&s=saqjhk96dkqtcat62&w=sk63hq83d9653cq93&n=st74haj5daj8ckj54&e=s9852ht742d742c87&d=e&v=n&b=2&a=p1cp2n(11-14)p4np5hp6nppp]399|300[/hv] My table was a bit of a non-issue staying in 3NT (1C-2C-3NT-P) making +3. This table didn't get as far in the play as it should have, declarer choosing to guess clubs early. When the finesse lost to West, he was destined to go down. Lose 13. Quote Link to comment Share on other sites More sharing options...
whereagles Posted February 3, 2011 Report Share Posted February 3, 2011 Since clubs is opener's suit, I don't think restricted choice applies, so that basically leaves as with no clue who to finesse against. I'll look at opps faces and see who's more interested in the play and finesse against him... ahah. Quote Link to comment Share on other sites More sharing options...
gnasher Posted February 3, 2011 Report Share Posted February 3, 2011 Since clubs is opener's suit, I don't think restricted choice appliesRestricted choice applies to the diamond and heart suits - with a choice of 4-card suits, he might have led the other one. Therefore he is less likely to have a second 4-card suit, so he's more likely to have three clubs. Quote Link to comment Share on other sites More sharing options...
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