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Round 2, Board 1


inquiry

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[hv=d=n&v=n&n=skqj53h73dk8cakq9&s=sat8hat9da92cjt63]133|200|Scoring: IMP

EW stay silent through-out the auction.

 

This is a hand that seems ideal for a relay system, as the trick is to find the club fit and get out of the known spade fit. It is also reasonable easy to get to clubs if south to make (gulp) a natural 2 response to 1 showing a real club suit. [/hv]

 

7C is a 10, 6N is 7, 6S is 4, 6C is 3, 5N is 2, 5S is 1

 

 

7CN bluecalm/redds

7CS elianna/awm

7CS jlall/hanp

7CS karlson/threenobob

7CS tlgoodwin/timg

7CS tylere / bid_em_up

6NN lobowolf/bkjswan

6NS mbodell - javabean

6SN ant590 - crayzeejim

6SN East4Evil/sohcahtoa

6SS Flycycle/Wackojack

6SN kristen33/jillybean

6SN rogerClee/cherdano

6CN hrothgar/Free

6CS jdonn/gib

4NS olegru - driver733

4SN kfay/jchiu

4SN sallyally/joylson

4SN Siegmund/MSchmahl

7NN gnasher/catch22

7NS peachy/lg62

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Of course 7C is lovely and flamboyent but should it score 3 more than 6N? 1/3 of the time when clubs split 4-1 or 5-0, 7 clubs will go off whereas 6NT is a laydown and will likely score about 67%. By that reckoning 6N should score about the same as 7clubs.
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Of course 7C is lovely and flamboyent but should it score 3 more than 6N? 1/3 of the time when clubs split 4-1 or 5-0, 7 clubs will go off whereas 6NT is a laydown and will likely score about 67%. By that reckoning 6N should score about the same as 7clubs.

4-1 clubs doesn't hurt unless diamonds are 7-1.

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Of course 7C is lovely and flamboyent but should it score 3 more than 6N? 1/3 of the time when clubs split 4-1 or 5-0, 7 clubs will go off whereas 6NT is a laydown and will likely score about 67%. By that reckoning 6N should score about the same as 7clubs.

4-1 clubs are not a problem on this hand.

 

It's true that 5-0 clubs or 5-0 spades (or for that matter, 7-1 diamonds or 8-0 hearts) present a difficulty, but these are all extremely low probability especially given the lack of opponent bids.

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Of course 7C is lovely and flamboyent

 

!???

Flamboyant ? It's just 90+% contract with 13top tricks barring some crazy breaks.

Imo the question is if 6NT should get that much but apparently people had difficulties finding clubs so 6NT would score some matchpoints. I think that if the field is very strong it should be more like 4points (80% pairs 6nt, 20% pairs 7c) than 7.

 

In our field 6NT would get exactly 70% for example hence the score...

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This one was my fault that we play a relay system but didn't find 7. I choose the wrong way to investigate and then had to use all my room to hunt for the Q to choose between 7nt and 6nt and forgot that 7 would be pretty good (although I also didn't know about the J so didn't know how good). Also, I think, that 7 for us over 6nt would have been a relay, not to play, given we had relayed to 6nt (which denied the Q).

 

Really I should have key carded in clubs and then searched for the diamond Q on the way to 7.

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We had an interesting disaster on this one. (We had a number of uninteresting disasters too.)

 

We bid

 

1-2 (natural / artificial, various)

2-2 (artificial, 15+ / balanced 11+)

3-4 (natural, not 5-5 but can be 6-4 / natural)

4-4 (cue bids)

4NT-5 (Keycard / 0 or 3)

 

At this point we seem to be in fairly good shape. Opener already knows that 7 is a good contract, and we have two whole levels available to investigate alternatives. K or Q is enough for 7NT, so:

 

5NT       (King-ask, promises all the keycards)

 

Responder, thinking that the question was whether to bid 6 or 7, pictures KQxxx xx Kx AKQx, where opener can't bid 7 because he might be opposite Ax Axxx Axx Jxxx. In this scenario, the third spade is enough for grand slam, because we no longer need to use a trump to ruff the spades good, so:

 

     -7

 

Opener, expecting either K or Q opposite, can now count 13 top tricks, so:

 

7NT

 

Oops. I'm not sure how we should have avoided this problem, though one answer would be to stop playing matchpoints.

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Andy, if responder had K, why wouldn't he show it by bidding 6? He also knows it's matchpoints.

My reasoning about the Q will probably sound less convincing - if the 4D cuebid shows a king, then responder could arguably show the Q by bidding 6D. If he thinks it might be shortness, then the Q is not great asset for bidding 7.

 

Of course, opener might find another excuse to bid 7N - responder's most likely extras are, I suppose, a 5th trump.

 

I guess a systemic solution would be a way to show a double fit with slam try over 3. The 6th round of bidding is kind of late to show a 3-card fit for opener's 5-card major.

 

(This post is fairly long because it's really a pretty interesting problem. And I sympathize, also having played a multi-purpose 2C/1M with artificial followups.)

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Andy, if responder had K, why wouldn't he show it by bidding 6? He also knows it's matchpoints.

My reasoning about the Q will probably sound less convincing - if the 4D cuebid shows a king, then responder could arguably show the Q by bidding 6D. If he thinks it might be shortness, then the Q is not great asset for bidding 7.

4 could have been shortage, but with KQJxx xxx x AKQx I don't think opener should take control over 4 - I'd just bid 4 and leave it to responder to make a decision. So your suggestion for showing Q probably works.

 

This post is fairly long because it's really a pretty interesting problem.

You don't know the meaning of the word "long". ;)

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Thanks, Ben -- yes, I ran into it on a bidding practice table and I thought it would make a nice hand for the par contest, with lots of potential traps yet biddable.
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Andy: I think it is wrong for south to bid 7 on that auction.

 

south can picture also

 

KQJxx

xx

xx

AKQx

 

 

(add a red queen if you want)

 

where the 3rd spade is useless. Add to that that third spade when spades break 4-1 ain't that great either and you get to an overbid IMO.

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Andy: I think it is wrong for south to bid 7 on that auction.

 

south can picture also

 

KQJxx

xx

xx

AKQx

 

 

(add a red queen if you want)

 

where the 3rd spade is useless. Add to that that third spade when spades break 4-1 ain't that great either and you get to an overbid IMO.

North has cue-bid diamonds. so he can't have xx.

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Here we were lucky because our system bid the hand for us:

 

1 - 2NT

3 - 3

4 - 4

4NT etc.

 

1 = 16+

2NT = 12-13balanced

3 = spades

4 = natural slam try

4 = cuebid setting clubs

4NT = rkcb in

 

Then opener can count 13 tricks.

My partner forgot 2NT is 12-13 (he thought it's 12+) so he even made an attempt towards 7NT but that was rejected lacking fifth club (he thought I would accept with queen more or something but I obviously couldn't have that).

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