inquiry Posted July 28, 2010 Author Report Share Posted July 28, 2010 Btw, I still don't understand why 5♣ is supposed to be a 60% game. When I tried simulations, I got 38%. If this is 38%, then the scores are all wrong and will need to be recalculated. How did you come up with 38%? Remember the following: North has an opening handSouth has a responding handNorth does not have three or four card heart support (no mention of support dbl)North has at least five diamondsSourth has, obviously, at least six hearts and I think no more than 7North has at 11 hcp, but not all the missing hcp as south has a response Did you apply anything like the above to the constraints? The more hcp you allow north to hold, the better the chances of making 5♣ (increases chances of spade KQ in north). There are also some squeeze chances (if spades are split). When I apply those constaints, limiting north to 11-15 hcp, I find five clubs making 65% of the time. Quote Link to comment Share on other sites More sharing options...
Mbodell Posted July 28, 2010 Report Share Posted July 28, 2010 North does not have three or four card heart support (no mention of support dbl)Sourth has, obviously, at least six hearts and I think no more than 7 I question these assumptions. Is it really the case that North can not have 3 hearts? Not everyone plays support doubles! And if North has a good 6 card diamond suit and 3 hearts might well bid 2♦ anyways. Quote Link to comment Share on other sites More sharing options...
awm Posted July 28, 2010 Report Share Posted July 28, 2010 Another thing that seems to come up is that often declarer needs to establish a second spade trick for a diamond discard. This often winds up with a series of spade plays where declarer leads the spade ten to an honor and the ace, then has to decide whether to lead up to the jack (playing opener for the king and queen) or try to ruff a spade (hoping RHO started with honor-third). Double dummy play will always get this right (for example always establishing the second spade trick when opener has four spades and responder has three, which is a fairly common layout) but at the table it is not so easy. Of course, the double-dummy assumption can help the defense too, but the main issue there seems to be the opening lead, and I think a trump lead when you're defending a game-level contract bid on very thin values is a fairly common approach. Quote Link to comment Share on other sites More sharing options...
655321 Posted July 28, 2010 Report Share Posted July 28, 2010 I question these assumptions. Is it really the case that North can not have 3 hearts? Not everyone plays support doubles! And if North has a good 6 card diamond suit and 3 hearts might well bid 2♦ anyways.The assumptions seem fair enough to me when the bidding has stayed low. But if the auction was something like (1♦) X (1♥) 5♣ we would know nothing about North's shape. Quote Link to comment Share on other sites More sharing options...
Hanoi5 Posted July 28, 2010 Report Share Posted July 28, 2010 Another thing that seems to come up is that often declarer needs to establish a second spade trick for a diamond discard. This often winds up with a series of spade plays where declarer leads the spade ten to an honor and the ace, then has to decide whether to lead up to the jack (playing opener for the king and queen) or try to ruff a spade (hoping RHO started with honor-third). Double dummy play will always get this right (for example always establishing the second spade trick when opener has four spades and responder has three, which is a fairly common layout) but at the table it is not so easy. Of course, the double-dummy assumption can help the defense too, but the main issue there seems to be the opening lead, and I think a trump lead when you're defending a game-level contract bid on very thin values is a fairly common approach. Don't people avoid leading a trump with singleton? Quote Link to comment Share on other sites More sharing options...
cherdanno Posted July 28, 2010 Report Share Posted July 28, 2010 Yes sorry I had a typo in my simulations, I now get similar numbers as Ben. They seem to be based mostly on the fact that declarer is picking up both KQx(x) and Hxxx with North, just as Adam wrote. Quote Link to comment Share on other sites More sharing options...
TimG Posted July 28, 2010 Report Share Posted July 28, 2010 Yes sorry I had a typo in my simulations, I now get similar numbers as Ben. They seem to be based mostly on the fact that declarer is picking up both KQx(x) and Hxxx with North, just as Adam wrote. Can you see which is less frequent and subtract that likelihood from the making percentage? Quote Link to comment Share on other sites More sharing options...
Fluffy Posted July 28, 2010 Report Share Posted July 28, 2010 when north fails to lead ♠K you have a clue, althou well you also don't know if they overruff your diamonds or not so probably evens out. Quote Link to comment Share on other sites More sharing options...
cherdanno Posted July 28, 2010 Report Share Posted July 28, 2010 Yes sorry I had a typo in my simulations, I now get similar numbers as Ben. They seem to be based mostly on the fact that declarer is picking up both KQx(x) and Hxxx with North, just as Adam wrote. Can you see which is less frequent and subtract that likelihood from the making percentage? Constraints:- North has at least 11 hcp, South at least 5.- North has at least as many diamonds as clubs, and (no 5-card major) or (more diamonds than cards in each major)- South has at least 4 hearts- If South has 5 spades, he has more hearts than spades West makes 5♣ 59.3% of the time (10000 runs)North has ♠KQ: 30.1% of the timeNorth has ♠Hxxx: 27.8% of the time Quote Link to comment Share on other sites More sharing options...
TimG Posted July 28, 2010 Report Share Posted July 28, 2010 Yes sorry I had a typo in my simulations, I now get similar numbers as Ben. They seem to be based mostly on the fact that declarer is picking up both KQx(x) and Hxxx with North, just as Adam wrote. Can you see which is less frequent and subtract that likelihood from the making percentage? Constraints:- North has at least 11 hcp, South at least 5.- North has at least as many diamonds as clubs, and (no 5-card major) or (more diamonds than cards in each major)- South has at least 4 hearts- If South has 5 spades, he has more hearts than spades West makes 5♣ 59.3% of the time (10000 runs)North has ♠KQ: 30.1% of the timeNorth has ♠Hxxx: 27.8% of the time I realize there are some other considerations -- 5C making isn't always due to the spade position -- but it does seem like the correct percentage is much closer to half the 60%. Quote Link to comment Share on other sites More sharing options...
awm Posted July 28, 2010 Report Share Posted July 28, 2010 Don't people avoid leading a trump with singleton? This doesn't actually matter much. The thing is, LHO is known to have the long diamonds and RHO the short diamonds. Any time RHO has ♣Jx, you basically have to pull trump anyway because otherwise RHO will overruff one of the diamonds relatively early in the hand. Of course, LHO is also known to have the short hearts, and if my plan in the play is to cross-ruff (ruffing three diamonds in dummy before pulling a second round of trumps) then I need to ruff hearts in order to re-enter my hand. If LHO has ♣Jx, he is well-positioned to overruff one of my heart re-entries. So the only position where I'm likely to make by ruffing three diamonds is where the club jack is singleton and the opponents don't find a trump lead. If LHO has ♣xx he may well lead a trump (it does seem like a normal lead when opponents bid to 5♣ on very few points) and leading from ♣J stiff is probably more common than leading from ♣Jx or ♣x. Looking at Cherdano's results, it does seem like the chances of 5♣ making are very close to the chances of being able to pick up a second spade trick. Quote Link to comment Share on other sites More sharing options...
TimG Posted July 28, 2010 Report Share Posted July 28, 2010 Perhaps a better way to judge how much the spade position plays in the success of the contract is to change the spade position so that two spade tricks are not possible and see how good 5C is then. Quote Link to comment Share on other sites More sharing options...
TimG Posted July 31, 2010 Report Share Posted July 31, 2010 Constraints:- North has at least 11 hcp, South at least 5.- North has at least as many diamonds as clubs, and (no 5-card major) or (more diamonds than cards in each major)- South has at least 4 hearts- If South has 5 spades, he has more hearts than spades West makes 5♣ 59.3% of the time (10000 runs)North has ♠KQ: 30.1% of the timeNorth has ♠Hxxx: 27.8% of the time I've tried to duplicate these condition. My first run of 1000 deals produced a 5♣ making percentage of 56.6%, so I suspect I've got something slightly off, but pretty close. I then replaced East's ♠J with the ♠6. Under this condition 5♣ made 9.3% of the time. I think it is safe to say that the double dummy results greatly overstate the chances of 5♣ making as a result of being successful against both ♠KQ and ♠Hxxx in north. If you allow declarer to make 9.3% of the time plus 30.1% of the remaining 90.7% (cherdanno's percentage for KQ in north), you get 5♣ making 36.6%. Under both conditions, 4♣ failed less than 0.5% of the time, so it doesn't seem to me that there should be any difference between the scores for 3♣ and 4♣. Quote Link to comment Share on other sites More sharing options...
gnasher Posted July 31, 2010 Report Share Posted July 31, 2010 If you allow declarer to make 9.3% of the time plus 30.1% of the remaining 90.7% (cherdanno's percentage for KQ in north), you get 5♣ making 36.6%. Don't we get anything for a non-trump lead, or a bit of card-reading? Also, Cherdano's conditions included "South has at least 4 hearts". but the opposition bidding implies that South has six hearts. That must significantly increase the chance of both spades being onside. Quote Link to comment Share on other sites More sharing options...
TimG Posted July 31, 2010 Report Share Posted July 31, 2010 If you allow declarer to make 9.3% of the time plus 30.1% of the remaining 90.7% (cherdanno's percentage for KQ in north), you get 5♣ making 36.6%. Don't we get anything for a non-trump lead, or a bit of card-reading? Perhaps you should, I was just reporting what I found through simulation. Did not mean to imply anything beyond that. Quote Link to comment Share on other sites More sharing options...
TimG Posted July 31, 2010 Report Share Posted July 31, 2010 Also, Cherdano's conditions included "South has at least 4 hearts". but the opposition bidding implies that South has six hearts. That must significantly increase the chance of both spades being onside. "If north can rebid 2♦, he does" so it also sounds like north has 6 diamonds. I changed the simulation conditions to give north 6+ diamonds and south 6+ hearts and came up with north holding ♠KQ 28.2% of the time. Quote Link to comment Share on other sites More sharing options...
Phil Posted July 31, 2010 Report Share Posted July 31, 2010 Not sure this is a great hand for a bidding contest if there is going to be this much debate about what the top contract is. Quote Link to comment Share on other sites More sharing options...
cherdanno Posted August 1, 2010 Report Share Posted August 1, 2010 If you allow declarer to make 9.3% of the time plus 30.1% of the remaining 90.7% (cherdanno's percentage for KQ in north), you get 5♣ making 36.6%. Don't we get anything for a non-trump lead, or a bit of card-reading? Also, Cherdano's conditions included "South has at least 4 hearts". but the opposition bidding implies that South has six hearts. That must significantly increase the chance of both spades being onside. Well, on many auctions we will only have learnt that South has at least 4 hearts (see 655321's comment). But actually it doesn't make a big difference: (Same constraints as above, but South 6+hearts:) Makes 5C: 0.6067North has S KQ:=0.3256 North has S Hxxx:=0.3289 Quote Link to comment Share on other sites More sharing options...
TylerE Posted August 1, 2010 Report Share Posted August 1, 2010 Just registering my unhappiness with this is scored... A thin, nearly even-money minor sut game at MP can hardly have an EXPECTATION of a near top. The significant part of the time that it's down those in 5♣ are getting essentially a bottom...this is not a 3 or 5 hand. Quote Link to comment Share on other sites More sharing options...
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