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3NT failures


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First one is a sanity check, making sure I'm only 99% crazy and not 100%:

 

[hv=d=n&v=e&n=skqhaj9dak96ckj109&s=sa10hkq65dj84c8652]133|200|Scoring: IMP

1-2-X-P-

3-P-3NT-AP

Lead is 2 in 3NT in the South[/hv]

 

1 was variable, showing either any balanced hand or a strong hand with one/both minors. RHO has a necessity to overcall this bid, so it's not 100% assured that he has all remaining 9 points. Now the opponents are heckling you for thinking when a 21 pt dummy has come up. In a higher level contract you would test clubs for lack of tricks, but is there a better line in 3NT than the double diamond finesse or a better way to combine chances? Spades are 6-3 with no blockage.

 

 

 

Second hand, you're South again.:

[hv=d=e&v=b&s=skj96h1074da6c10964]133|100|Scoring: IMP

P-P-1-P

1NT-P-2-P

2-P-3NT-AP[/hv]

 

Wrongsided! 1 was a strong club, 1NT showed heart length, 2 was a relay, 2 showed spade shortness. What are you leading if a) the spade shortness promises a singleton or void, or b ) if RHO could have up to two cards in the suit?

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Maybe a better line on the first one is to cash AK of diamonds hoping that either the Q or T will fall. If that fails, cash hearts ending in dummy and try to guess clubs.

 

The chance of this succeeding is something like:

P(singleton T/Q) + P(double T/Q) + P(QTx) + P(club guess)

15*(2/6) + 48*(5/9) + 36*(1/4) + 50

5 + 26.6 + 9 + 50 = 90.6

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Maybe a better line on the first one is to cash AK of diamonds hoping that either the Q or T will fall.  If that fails, cash hearts ending in dummy and try to guess clubs. 

 

The chance of this succeeding is something like:

P(singleton T/Q) + P(double T/Q) + P(QTx) + P(club guess)

15*(2/6) + 48*(5/9) + 36*(1/4) + 50

5 + 26.6 + 9 + 50 = 90.6

I don't agree with your numbers.

 

P (singleton T or Q) = 2 cases out of 6 (6C1) = 1/3 * 15 = 5

P (doubleton T or Q) = 9 cases out of 15 (6C2) = 3/5 * 48 = 28.8

P (QTx) = [EDIT: 8] cases out of 20 (6C3) = 2/5 * 36 = 14.4

 

P (diamonds coming in) = 48%

 

When diamonds don't come in (52%) then you win approximately half the time (too lazy to do a full calc on clubs) or another 26%, so the total chance is approximately 74%, not 90%. You can't add a straight 50% to 48%, you are double-counting the times when diamonds come in.

 

Later edit:

Note: this assumes clubs are a total guess and that short honor in the LHO is impossible (obviating the guess). In practice I do not think the clubs are a total guess -- LHO should have the ace more often than not for preempting on a jack-high suit, unfavorable.

Edited by eyhung
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How good are my opponents? How about combining the chances of

 

1) Diamond T with RHO;

2) Diamond Q with LHO; and

3) RHO grabs the Q or tanks when a diamond comes off dummy.

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Don't take my word for it, but....

 

1 - Count me in for AK, to the K.  If LHO can bid that way with 5HCP, he's got me.

Unfortunately, North is dealer & opened 1, RHO/East bid 2, and South has become declarer in 3N.

 

I think it is quite likely that RHO/East will have both the A and the Q given the vulnerability and the outstanding available cards.

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I am liking A followed by a diamond to the jack. On a good day Q is onside and we establish the 3rd diamond winner immediately. On a bad day it loses, and when we get back in we run all the hearts before we commit ourselves to either playing for 3-3 diamonds or finessing with the K-9. Given the 6-3 spade break, playing West for 4 diamonds is likely better.
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