DWM Posted January 3, 2010 Report Share Posted January 3, 2010 We are looking at how to bid after interference to stayman. We play promisory stayman and could be garbage. We would like to keep double as penalty if at all possible. to get a simple treatment I have got this far. pass = below invitiational valuesX = 2 stops in ops suit and inv + points2NT = 1 stop in ops suit and inv points2 level bids are invites3 level bids are GF this seems to be ok except when the interference is 2S. Any suggestions on this or a different simple treatment? Quote Link to comment Share on other sites More sharing options...
Ant590 Posted January 3, 2010 Report Share Posted January 3, 2010 If Garbage Stayman is possible then the 1NT bidder can not make game-forcing bids. I would devote time to learning a defense to a double of stayman, but just play naturally to suit bids. FWIW, here's my counter-defense to stayman doubled:(1) Bids have their previous meaning, but deny a club stop (2) Pass initially shows a club stop then i. Rdbl is Stayman (either garbage or game forcing)ii. 2♦ shows five diamonds, and a 4 card major, invitationaliii. 2♥/♠ shows 4+ cards and is invitational (3) Rdbl is a suggestion to play then i. 2♣ = garbage stayman (can be passed)ii. 2♥/♠ = 5M4oM, signoffiii. 2NT = invitational with a 4 card major Quote Link to comment Share on other sites More sharing options...
helene_t Posted January 3, 2010 Report Share Posted January 3, 2010 I am confused. Is the auction1NT-(p)-2♣-(2♠)? Then it is opener's turn, but he can't have "below invitational values". He can be min or max. Quote Link to comment Share on other sites More sharing options...
DWM Posted January 3, 2010 Author Report Share Posted January 3, 2010 Sorry, Opener is silenced by the garbage stayman option 1NT - (P) - 2♣ - (2♠)P - (P) - ??? Quote Link to comment Share on other sites More sharing options...
P_Marlowe Posted January 3, 2010 Report Share Posted January 3, 2010 Hi, assuming garbage stayman means, if 2C is weak, than responder is 4-4 in the majors,I would suggest, that X by opener in the seq. 1NT - (Pass) - 2C - (2S)X - ... is for take out. If responder is weak, than you will have at least 6 trumps, i.e. they will have at least a 7 card fit, and asumming 1NT is at leats 15-17, you will still have half of the deck. But if you want X for penalty, i.e. showing at least 4 cards, that should work as well,if you hit the weak responder, than ... how may trumps do you have? With kind regardsMarlowe Quote Link to comment Share on other sites More sharing options...
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