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the hog

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3. First time around, I did not bid my . Hence support now should show specifically 3 card support. Not a very weak hand, as I could have used Lebensohl ( or any of its variants ) after the reverse to bid my suit.

 

If partner is 5-6-1-1, this will be good news to explore slam. With normal 4-5-x-y type of hands, it will help partner to decide to play in the Moysian fit or 3NT

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Opposite an unknown parter, I bid 4S. Pard has a strong hand already, so I'm not giving him any more excuses to head for slam, which is what might happen if I bid a stronger-looking 3S.

 

Of course, if I had discussed with pard 3S here might be ambigous in terms of strenght, I'd bid it.

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3sp, if this is about the question before then true partner will never know we have 4 card suit, but sometime with 4-3 he will get us to 4sp, and if we have 4 he will be happier.

responder only has THREE spades doesn't he? so why the comment "partner doesn't know we (meaning resopnder?) has 4 spades?? :rolleyes:

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Opposite an unknown parter, I bid 4S. Pard has a strong hand already, so I'm not giving him any more excuses to head for slam, which is what might happen if I bid a stronger-looking 3S.

 

Of course, if I had discussed with pard 3S here might be ambigous in terms of strenght, I'd bid it.

I am REALLY missing something here :rolleyes: WHY is 3S stronger than 4S??

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Opposite an unknown parter, I bid 4S. Pard has a strong hand already, so I'm not giving him any more excuses to head for slam, which is what might happen if I bid a stronger-looking 3S.

 

Of course, if I had discussed with pard 3S here might be ambigous in terms of strenght, I'd bid it.

I am REALLY missing something here :rolleyes: WHY is 3S stronger than 4S??

Well, assuming responder didn't bypass a 4-card spade suit, 3S and 4S shows what? Must be 3-card support, a singleton (otherwise you bid something else), and some points. Since 2S is game-forcing, 3S is stronger than 4S. If 2S wasn't game-forcing, the meanings would be reversed.

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Kinda stuck between 2 and 2 NT.

I think I opt for 3, since it sounds like pd is unbalanced, and I only stop one of the minors.

He knows I have no 4, at least playing with me. So he pretty much "knows" I have singleton .

 

Mike :)

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Hi all,

Since 2 bid might not be natural ( AJxAQJxxxxxAK for example) I think for 3 bid we need to be near the max of 1NT (9-10 p) so with the present hand 2NT seems more flexible ( stopper + length in minors and min but useful values) and when partner continue with 3 level bid to show our support or others

Rado

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Kinda stuck between 2 and 2 NT.

I think I opt for 3, since it sounds like pd is unbalanced, and I only stop one of the minors.

He knows I have no 4, at least playing with me. So he pretty much "knows" I have singleton .

 

Mike :D

Hey Mike!

 

I am just wondering wich one of the minors are you stopping :)

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Very interesting comments:

 

"Well, assuming responder didn't bypass a 4-card spade suit, 3S and 4S shows what?"

 

Weren't you given advice to by pass a bad 4 card Major?

 

Rado, an excellent player, believes that 2S may not even be natural, and I fully agree, so now we have a situation where the 2S bid can show 3/4 or 5S if responder has 6H and 5S.

 

And finally, Flame has made his most accurate comment for weeks:

"true partner will never know we have 4 card suit,"

 

How much easier to bid naturally!

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Ofcourse bypassing a 4 card major will many time mean we wont bid a 4-4 major fit, but these 4-4 major fit doesnt necessarly be the best contract on those hands, our suit is weak and partner suit is probebly weak too, we have stopers for all the suits and we have other long and strong suit that might be very good for 3nt.

On do i know our suit is bad and we got stopers ? because without stopers and good suit we would bid 4M on assumingly 4-3 major fit and partner would just smile when we surprise him with a 4 card suit we denied.

And sure this wont win 100% of the boards, im sure we will get some bad results from this here and there, but on avarage when you consider some benefits of this hiding a major and the small danger of it, you can find cases when its the right plan.

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3sp, if this is about the question before then true partner will never know we have 4 card suit, but sometime with 4-3 he will get us to 4sp, and if we have 4 he will be happier.

responder only has THREE spades doesn't he? so why the comment "partner doesn't know we (meaning resopnder?) has 4 spades?? :unsure:

I was reffering to another posts on the same subject. on this forum.

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1H 1N

2S

 

2S is a GF. Your bid is?

That reverse is a GF in your system? Standard meaning is a 1RF.

 

If it is truly a GF, then 3S seems obvious (assuming that 1N denied 4s).

 

If it is a 1RF, then 2N followed by 3S showing a weak hand that does not want game opposite a minimum reverse also seems obvious.

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Imps, all vul if it matters.

 

1H  1N

2S

 

2S is a GF. Your bid is?

 

Qxx

x

Axxx

xxxxx

 

CASE 1

If 2S is gf it must have 19+ hcp.

In this case I bid 3NT.

 

 

I expect pard to have 4+ tricks in H and get 4 tricks in spades with my spades Q.

If we can survive a clubs lead we are home. With xxxxx, if pard has as little as x in clubs, opps may probably score only 4 club tricks and we get the rest.

 

If we do not survive the club lead, chances are that a forcing defence in clubs may defeat 4 spades.

 

CASE 2

If 2S can be as little as 17+,

I bid 2NT Ingberman/Lebensohl to which pard relays to 3clubs with a minimum reverse and I pass or correct (here I'd signoff in 3S).

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I thought if it is a game force bid, the weakest bid you can show is 4Spades, that to me seems appropriate here, shows no interest in anything else. and it is a 3 card support limit raise.

 

Intersting I did not realise 2 spades reverse was game forcing (or is that dependant on agreements?), I thought it was only forcing 1 round as your 1nt could be zero points depending who teaches you 2/1 I suppose.

 

 

Also I dont know enough conventions to know if there is one to show second suit support and the singleton or the A diamonds just in case pards reverse is super strong or super distributional

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