mtvesuvius Posted May 6, 2009 Report Share Posted May 6, 2009 All NV at IMPs you hold: QxxxTxAQJxAKx (1♦) - P - (2♠*) - ? *Weak Quote Link to comment Share on other sites More sharing options...
rbforster Posted May 6, 2009 Report Share Posted May 6, 2009 Why am I annoyed? They bid my 2 longest suits... perhaps they will get to play there. If partner wants to double with his spade shortness, then I'll probably bid 3N. Quote Link to comment Share on other sites More sharing options...
Echognome Posted May 6, 2009 Report Share Posted May 6, 2009 Seems to me like an easy pass. Maybe you will color me yellow, but I would have passed as well over a 1♠ response. Quote Link to comment Share on other sites More sharing options...
JLOL Posted May 6, 2009 Report Share Posted May 6, 2009 2N Quote Link to comment Share on other sites More sharing options...
the hog Posted May 6, 2009 Report Share Posted May 6, 2009 Easy pass. Partner passed over 1D after all. Quote Link to comment Share on other sites More sharing options...
Phil Posted May 6, 2009 Report Share Posted May 6, 2009 I pass although 2N could be right. Quote Link to comment Share on other sites More sharing options...
andy_h Posted May 6, 2009 Report Share Posted May 6, 2009 I'm up for 2NT. Quote Link to comment Share on other sites More sharing options...
Hanoi5 Posted May 6, 2009 Report Share Posted May 6, 2009 I think I pass. Partner didn't bid 1♥ or 2♣. Quote Link to comment Share on other sites More sharing options...
whereagles Posted May 6, 2009 Report Share Posted May 6, 2009 Very easy pass. LHO is short in spades, thus long in diamonds. Pard must therefore be short in diamonds and, since he didn't act over 1♦, he's broke. Justin's 2NT gets a LOL from me... :P Quote Link to comment Share on other sites More sharing options...
Gerben42 Posted May 6, 2009 Report Share Posted May 6, 2009 2NT is LOL Pass is obvious, they are bidding your best suits, be happy! Quote Link to comment Share on other sites More sharing options...
655321 Posted May 6, 2009 Report Share Posted May 6, 2009 LHO is short in spades, thus long in diamonds. Pard must therefore be short in diamonds and, since he didn't act over 1♦, he's broke. Thanks. I am having trouble following these words. To help me understand, would you be able to put them into numbers? LHO has ... of the 3 missing spades - leaving ... for partner.LHO has ... of the 9 missing diamonds (RHO having ... diamonds, and partner ...)Partner therefore has a ???? shape. He would have bid with this shape and 9 HCP, did not bid, therefore is 'broke' (has less than 9 points). Anyway, in the meantime put me down for 2NT. Quote Link to comment Share on other sites More sharing options...
whereagles Posted May 6, 2009 Report Share Posted May 6, 2009 hum.. well, reasoning goes like this: ("-->" = "hints at") RHO long spades + we long spades --> LHO short spades --> LHO long diamonds + we long diamonds --> pard short diamonds -->pard short diamonds + pard no bid --> pard is broke If I had to guess, I'd say shapes across are something like.. .........25241453..........6223 .........4243 Or thereabouts. One could run a simulation, though. Quote Link to comment Share on other sites More sharing options...
655321 Posted May 6, 2009 Report Share Posted May 6, 2009 OK, serves me right for trying to be subtle. Whereagles, my point was that your chain of reasoning, without numbers, proves nothing. All of the links in your chain are correct, but your conclusion (partner must be short in diamonds, and is therefore 'broke' because he passed 1♦) is way too strong. (As well as suggesting to me that partner would have made a takeout double with values and a singleton diamond, when we know that his spades are too short for a takeout double). Partner is likely to have 2 or 3 diamonds, as well as 1 or 2 spades. I agree that 2524 is his single most likely shape, amongst the many possible shapes he can hold. But there are many hands with 2 or 3 diamonds, and reasonable values where he would pass over 1♦. I think it will usually be hard for them to double even when we are in trouble (the weak hand with the long spades has no entry, and the opening bidder doesn't have the AQJ in the suit he opened), and that we will have a chance at 3NT often enough that I want to bid here. Quote Link to comment Share on other sites More sharing options...
helene_t Posted May 6, 2009 Report Share Posted May 6, 2009 2N You promised to stop drinking, Justin. Quote Link to comment Share on other sites More sharing options...
JLOL Posted May 6, 2009 Report Share Posted May 6, 2009 LOL at people LOLing 655321 and me. Quote Link to comment Share on other sites More sharing options...
paulg Posted May 6, 2009 Report Share Posted May 6, 2009 Echognome Quote Link to comment Share on other sites More sharing options...
jdonn Posted May 6, 2009 Report Share Posted May 6, 2009 I would have instinctively passed without even thinking much about it, but admittedly I don't have much experience in this spot. Now that I'm seeing the 2NT bids.... I don't know. I agree it's not that likely to be doubled, and we could have a game but I think it's a fair amount more likely we don't. Color me chicken I still pass. But I'm not LOLing anyone. Quote Link to comment Share on other sites More sharing options...
Echognome Posted May 6, 2009 Report Share Posted May 6, 2009 <snip> Color me chicken I still pass. But I'm not LOLing anyone. And pray tell what color is that? Whitish yellow? Quote Link to comment Share on other sites More sharing options...
Phil Posted May 6, 2009 Report Share Posted May 6, 2009 ( @ r (:D) $ # @ r (:)) Quote Link to comment Share on other sites More sharing options...
Trumpace Posted May 6, 2009 Report Share Posted May 6, 2009 OK, serves me right for trying to be subtle. Whereagles, my point was that your chain of reasoning, without numbers, proves nothing. All of the links in your chain are correct, but your conclusion (partner must be short in diamonds, and is therefore 'broke' because he passed 1♦) is way too strong. (As well as suggesting to me that partner would have made a takeout double with values and a singleton diamond, when we know that his spades are too short for a takeout double). Partner is likely to have 2 or 3 diamonds, as well as 1 or 2 spades. I agree that 2524 is his single most likely shape, amongst the many possible shapes he can hold. But there are many hands with 2 or 3 diamonds, and reasonable values where he would pass over 1♦. I think it will usually be hard for them to double even when we are in trouble (the weak hand with the long spades has no entry, and the opening bidder doesn't have the AQJ in the suit he opened), and that we will have a chance at 3NT often enough that I want to bid here. How many 2524 hands will partner have, where he won't overcall 1H (or something else other than pass) over 1D and we have a 3NT? Quote Link to comment Share on other sites More sharing options...
whereagles Posted May 6, 2009 Report Share Posted May 6, 2009 Whereagles, my point was that your chain of reasoning, without numbers, proves nothing. Sorry, I'm not still at the point where I can crunch the numbers real-time at the table. But I'm working on it :rolleyes: Agree that the conclusion of short (0-2) diamonds may be a bit too strong, but I would insist the odds are good pard has club or heart length. Since he didn't overcall, he's prolly broke. Keep in mind you have 16 hcp and LHO is unlimited. Assuming LHO to be 11+, RHO 3+ and distributing the rest of hcps evenly, we come to something like LHO pard RHO we14 .... 4 .... 6 ... 16 Quote Link to comment Share on other sites More sharing options...
gwnn Posted May 6, 2009 Report Share Posted May 6, 2009 Whereagles, it is not a good idea to just "distribute the rest of hcp evenly" for the same reason you shouldn't say that when LHO opens 1♥, his average heart length is 7 Quote Link to comment Share on other sites More sharing options...
655321 Posted May 6, 2009 Report Share Posted May 6, 2009 How many 2524 hands will partner have, where he won't overcall 1H (or something else other than pass) over 1D and we have a 3NT?Probably none at all for me. But do you see the difference between "Partner's shape is 2524" and "2524 is his single most likely shape, amongst the many possible shapes he can hold"? Quote Link to comment Share on other sites More sharing options...
Trumpace Posted May 6, 2009 Report Share Posted May 6, 2009 How many 2524 hands will partner have, where he won't overcall 1H (or something else other than pass) over 1D and we have a 3NT?Probably none at all for me. But do you see the difference between "Partner's shape is 2524" and "2524 is his single most likely shape, amongst the many possible shapes he can hold"? Yes.. so? I am not saying that 2NT is incorrect, just that I haven't seen any compelling reason for it (apart from maybe the below)... (Sorry for the basic question:) does 2NT show a balanced 15-18 count? Quote Link to comment Share on other sites More sharing options...
cherdanno Posted May 6, 2009 Report Share Posted May 6, 2009 (Sorry for the basic question:) does 2NT show a balanced 15-18 count? Yes. More like 16-18 I guess. Quote Link to comment Share on other sites More sharing options...
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